On Mon, Nov 30, 2009 at 4:26 AM, Oliver Tomic <oliver.to...@nofima.no>wrote:
> Hi, > > I am not sure whether this has been reported before or maybe even got fixed > already. When I make scatter plot and plot a point with marker = 'o' it > appears as a circle in the plot as it should. It won't, however, appear in > the legend. > > Windows XP > Python(x,y) 2.6.0 > matplotlib 0.99.1 (I think :-) > > > Example: > ax.scatter([x_assF[6]], [y_assF[6]], s=35, c='r', marker='o', > label='Ecological') > > doesn't show in the legend. When I change the same line of code to > > ax.scatter([x_assF[6]], [y_assF[6]], s=35, c='r', marker='8', > label='Ecological') > > that is, the marker is now set to marker='8', then it will appear as a > circle in the legend. Is this a bug or am I messing something up here? Finde > complete code and data sets below: > > > > [CODE START] > # -*- coding: utf-8 -*- > """ > correlationPlot_fig15.2.py > """ > > # Import necessary modules > import numpy as np > import matplotlib.pyplot as plt > > > # Import data for correlation plot > assF = np.loadtxt('Apples_flowerFlavour_assF_corrPlot.txt') > all = np.loadtxt('Apples_flowerFlavour_allAssessors_corrPlot.txt') > > x_assF = assF[:,1].copy() > y_assF = assF[:,0].copy() > > x_all = all[:,1].copy() > y_all = all[:,0].copy() > > > # Plot correlation plot values > fig = plt.figure() > ax = fig.add_subplot(111) > ax.scatter(x_all, y_all, s=10, c='w', marker='o', edgecolor='grey', > label='_') > # NOTE: label='_' excludes the lable from legend > > ax.scatter([x_assF[0]], [y_assF[0]], s=50, c='r', marker='s', label='Alpe > Golden') > ax.scatter([x_assF[1]], [y_assF[1]], s=50, c='r', marker='v', label='Granny > Smith') > ax.scatter([x_assF[2]], [y_assF[2]], s=50, c='r', marker='d', label='Green > Star') > ax.scatter([x_assF[3]], [y_assF[3]], s=50, c='r', marker='^', > label='Kanzi') > ax.scatter([x_assF[4]], [y_assF[4]], s=50, c='r', marker='>', label='Pink > Lady') > ax.scatter([x_assF[5]], [y_assF[5]], s=50, c='r', marker='<', label='Royal > Gala') > ax.scatter([x_assF[6]], [y_assF[6]], s=35, c='r', marker='o', > label='Ecological') > > ax.plot([0,10], [0,10], 'b--') > > ax.set_xlim(0,10) > ax.set_ylim(0,10) > > # Fix legend settings > plt.legend(loc='lower right', shadow=True, scatterpoints=1) > ltext = plt.gca().get_legend().get_texts() > plt.setp(ltext[0], fontsize = 10, color = 'k') > > ax.set_xlabel('Score - panel average') > ax.set_ylabel('Score - assessor F') > > plt.show() > [CODE END] > > > > Vennlig hilsen / Yours sincerely* > Oliver Tomic* > Research scientist, Dr. scient > > > Osloveien 1 > 1430 Ås > Norway > Tel: +47 6497 0252 > Mob: +47 9574 6167* > **oliver.to...@nofima.no* <oliver.to...@nofima.no> / > *www.nofima.no*<http://www.nofima.no/> > > ------------------------------------------------------------------------------ > Let Crystal Reports handle the reporting - Free Crystal Reports 2008 30-Day > trial. Simplify your report design, integration and deployment - and focus > on > what you do best, core application coding. Discover what's new with > Crystal Reports now. http://p.sf.net/sfu/bobj-july > _______________________________________________ > Matplotlib-users mailing list > Matplotlib-users@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > > This is a very detailed description indeed :) A simple test code in Ipython v0.10: plt.scatter(np.random.rand(20), np.random.rand(20), c='r', marker='o', label='test') plt.legend() This works as you originally have expected here. (circles on the legend) I am not sure how much this to do with the svn version of the matplotlib. ================================================================================ Platform : Linux-2.6.29.6-217.2.3.fc11.i686.PAE-i686-with-fedora-11-Leonidas Python : ('CPython', 'tags/r26', '66714') IPython : 0.10 NumPy : 1.4.0.dev Matplotlib : 1.0.svn ================================================================================ -- Gökhan
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