[Matplotlib-users] Creating frames for use with ArtistAnimation?
Hi, I am creating a big and complicated plot by doing things like: ax.add_patch( ... ) and when I'm done I want to save the resulting frame. However, I've looked through the examples and it seems like you have to use plot() or pcolor() to create frames that you can feed into ArtistAnimation. So,then, how can I use capture the resulting axes into a frame? Thanks! -- Virtualization & Cloud Management Using Capacity Planning Cloud computing makes use of virtualization - but cloud computing also focuses on allowing computing to be delivered as a service. http://www.accelacomm.com/jaw/sfnl/114/51521223/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Alpha keyword not working with contourf
Hi All, I'm just getting started with matplotlib. I'm trying to make a contour plot using contourf and have the different paths colored and semi transparent but the alpha keyword doesn't seem to do anything. I googled around and found that other people have had this same problem but I didn't find a solution. Here's what I'm doing - contourf(metals, U, o3, levels=[o3col-nsig*o3sig, o3col+nsig*o3sig], alpha= 0.20, colors='magenta') contourf(metals, U, o2, levels=[o2col-nsig*o2sig, o2col+nsig*o2sig], alpha= 0.20, colors='blue') contourf(metals, U, c3, levels=[c3col-nsig*c3sig, c3col+nsig*c3sig], alpha= 0.20, colors='green') To plot them all together. For reference my machine is running Mac OS X 10.6.8 and my version of matplotlib is 1.2.x Thanks! -- Virtualization & Cloud Management Using Capacity Planning Cloud computing makes use of virtualization - but cloud computing also focuses on allowing computing to be delivered as a service. http://www.accelacomm.com/jaw/sfnl/114/51521223/___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Alpha keyword not working with contourf
On 02/11/2012 07:40 AM, Alexa Villaume wrote:
> Hi All,
>
> I'm just getting started with matplotlib. I'm trying to make a contour
> plot using contourf and have the different paths colored and semi
> transparent but the alpha keyword doesn't seem to do anything. I googled
> around and found that other people have had this same problem but I
> didn't find a solution. Here's what I'm doing -
>
> contourf(metals, U, o3, levels=[o3col-nsig*o3sig, o3col+nsig*o3sig],
> alpha=0.20, colors='magenta')
>
> contourf(metals, U, o2, levels=[o2col-nsig*o2sig, o2col+nsig*o2sig],
> alpha=0.20, colors='blue')
>
> contourf(metals, U, c3, levels=[c3col-nsig*c3sig, c3col+nsig*c3sig],
> alpha=0.20, colors='green')
>
>
> To plot them all together.
>
> For reference my machine is running Mac OS X 10.6.8 and my version of
> matplotlib is 1.2.x
>
> Thanks!
Please provide a minimal but complete script that illustrates the
problem; describe what it is in the output that does not match your
expectations. e.g.,
import numpy as np
import matplotlib.pyplot as plt
z = np.arange(20).reshape(4,5)
plt.contourf(z, levels=[2,3], alpha=0.2, colors='magenta')
plt.savefig("testcontourf_alpha.png")
which produces a pale magenta stripe, as expected, with mpl from github
master.
Eric
>
>
>
> --
> Virtualization& Cloud Management Using Capacity Planning
> Cloud computing makes use of virtualization - but cloud computing
> also focuses on allowing computing to be delivered as a service.
> http://www.accelacomm.com/jaw/sfnl/114/51521223/
>
>
>
> ___
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Re: [Matplotlib-users] Alpha keyword not working with contourf
On 02/11/2012 10:30 AM, Alexa Villaume wrote:
> Thanks for replying Eric.
(You're welcome. But please keep replies on the list when they are
potentially useful to others, as yours is.)
>
> Here is my minimal script -
>
> import matplotlib
>
> frompylab import*
>
> import numpy as np
>
> importos
>
>
> metals=np.arange(-3.0, 1.1, 0.1)
>
> U=np.arange(-6.0, 0.25, 0.25)
>
> o3=np.zeros([25,41])
>
>
> plt.contourf(metals, U, o3, levels=[o3col-nsig*o3sig], alpha=0.20,
> colors='blue')
>
> plt.savefig("CoutourPlot.ps")
The Postscript language does not support transparency, so transparency
is lost when you use the mpl postscript backend. The way to work around
this, if you really need to end up with a postscript file, is to save
the file as pdf, and then use a converter program to render that as
postscript. (It might be a "print-to-file" or "save-as" option on your
pdf display program, for example. I don't know what is typically
available on a Mac, but Macs have long been pdf-friendly. In general,
the need for ps files has been diminishing. I almost never generate
them any more.)
Eric
>
>
> It plots fine except except there is no transparency in colors of the
> contour, it's like alpha is always set to 1.0
>
> On Sat, Feb 11, 2012 at 8:23 AM, Eric Firing > wrote:
>
> On 02/11/2012 07:40 AM, Alexa Villaume wrote:
> > Hi All,
> >
> > I'm just getting started with matplotlib. I'm trying to make a
> contour
> > plot using contourf and have the different paths colored and semi
> > transparent but the alpha keyword doesn't seem to do anything. I
> googled
> > around and found that other people have had this same problem but I
> > didn't find a solution. Here's what I'm doing -
> >
> > contourf(metals, U, o3, levels=[o3col-nsig*o3sig, o3col+nsig*o3sig],
> > alpha=0.20, colors='magenta')
> >
> > contourf(metals, U, o2, levels=[o2col-nsig*o2sig, o2col+nsig*o2sig],
> > alpha=0.20, colors='blue')
> >
> > contourf(metals, U, c3, levels=[c3col-nsig*c3sig, c3col+nsig*c3sig],
> > alpha=0.20, colors='green')
> >
> >
> > To plot them all together.
> >
> > For reference my machine is running Mac OS X 10.6.8 and my version of
> > matplotlib is 1.2.x
> >
> > Thanks!
>
> Please provide a minimal but complete script that illustrates the
> problem; describe what it is in the output that does not match your
> expectations. e.g.,
>
> import numpy as np
> import matplotlib.pyplot as plt
> z = np.arange(20).reshape(4,5)
> plt.contourf(z, levels=[2,3], alpha=0.2, colors='magenta')
> plt.savefig("testcontourf_alpha.png")
>
> which produces a pale magenta stripe, as expected, with mpl from github
> master.
>
> Eric
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[Matplotlib-users] problem to plot constant limited(within specific xrange value) y line within a square well
import numpy as np
import matplotlib.pyplot as plt
E=[81.97400737666324, 322.0939978589591, 694.5766491226185]
V0=1000
a=0.1
def V(x):
if x > -a and x < a:
return 0
return V0
V=np.vectorize(V)
#psi=np.vectorize(psi)
x= np.linspace(-1.5*a,1.5*a,100)
plt.plot(x,V(x))
plt.xlim(-5*a,5*a)
plt.ylim(-.001*V0,1.01*V0)
for m in E:
x1=np.linspace(-a,+a,100)
#y=m
#plt.xlim(-5*a,5*a)
#plt.axhline(m)
#y=np.vectorize(y)
plt.plot(x1,m)
#plt.show()
print m
Error:
---
ValueErrorTraceback (most recent call last)
C:\Python27\lib\site-packages\IPython\utils\py3compat.pyc in
execfile(fname, glob, loc)
166 else:
167 filename = fname
--> 168 exec compile(scripttext, filename, 'exec') in glob, loc
169 else:
170 def execfile(fname, *where):
C:\Users\as\uy.py in ()
23 #plt.axhline(m)
24 #y=np.vectorize(y)
---> 25 plt.plot(x1,m)
26 #plt.show()
27 print m
C:\Python27\lib\site-packages\matplotlib\pyplot.pyc in plot(*args, **kwargs)
2456 ax.hold(hold)
2457 try:
-> 2458 ret = ax.plot(*args, **kwargs)
2459 draw_if_interactive()
2460 finally:
C:\Python27\lib\site-packages\matplotlib\axes.pyc in plot(self, *args, **kwargs)
3846 lines = []
3847
-> 3848 for line in self._get_lines(*args, **kwargs):
3849 self.add_line(line)
3850 lines.append(line)
C:\Python27\lib\site-packages\matplotlib\axes.pyc in
_grab_next_args(self, *args, **kwargs)
321 return
322 if len(remaining) <= 3:
--> 323 for seg in self._plot_args(remaining, kwargs):
324 yield seg
325 return
C:\Python27\lib\site-packages\matplotlib\axes.pyc in _plot_args(self,
tup, kwargs)
298 x = np.arange(y.shape[0], dtype=float)
299
--> 300 x, y = self._xy_from_xy(x, y)
301
302 if self.command == 'plot':
C:\Python27\lib\site-packages\matplotlib\axes.pyc in _xy_from_xy(self, x, y)
238 y = np.atleast_1d(y)
239 if x.shape[0] != y.shape[0]:
--> 240 raise ValueError("x and y must have same first dimension")
241 if x.ndim > 2 or y.ndim > 2:
242 raise ValueError("x and y can be no greater than 2-D")
ValueError: x and y must have same first dimension
Question:
then how to plot those specific component of E within the square well only?
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