[Matplotlib-users] question about stacked histograms
Hi all, Has any of you had any luck with creating stacked histograms using matplotlib? It seems to work but I have no idea how to label (or add the legend) or choose the colors of the stacks. Below is a sample code for creating a stacked histogram. Can anyone help please? Unlike the "bar()" function, hist() doesn't seem to have the color/colors parameter. #!/usr/bin/python import sys import matplotlib.pyplot as pyplot import numpy as numpy page_numbers_one = (100,100,500,600,800) page_numbers_two = (100,100,500,600,800,100,100,100,100,100) page_numbers_three = (900,100,500,600,800,500) pyplot.hist((page_numbers_one,page_numbers_two,page_numbers_three),histtype='barstacked',bins=5) pyplot.show() best, amit shrestha -- OpenSolaris 2009.06 is a cutting edge operating system for enterprises looking to deploy the next generation of Solaris that includes the latest innovations from Sun and the OpenSource community. Download a copy and enjoy capabilities such as Networking, Storage and Virtualization. Go to: http://p.sf.net/sfu/opensolaris-get ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] question about stacked histograms
Thanks John. The bar_stacked example does not seem to work for histograms, but I'm glad to know that we could manually make the legends. I still do not know how to specify the colors of the "stacks" in my histogram, so adding the manual legends for them is still a pain -- but at least doable since I can figure it out from the actual data. best, amit shrestha John Hunter wrote: On Tue, Jun 2, 2009 at 3:15 PM, Amit wrote: Hi all, Has any of you had any luck with creating stacked histograms using matplotlib? It seems to work but I have no idea how to label (or add the legend) or choose the colors of the stacks. Below is a sample code for creating a stacked histogram. Can anyone help please? Unlike the "bar()" function, hist() doesn't seem to have the color/colors parameter. #!/usr/bin/python import sys import matplotlib.pyplot as pyplot import numpy as numpy page_numbers_one = (100,100,500,600,800) page_numbers_two = (100,100,500,600,800,100,100,100,100,100) page_numbers_three = (900,100,500,600,800,500) pyplot.hist((page_numbers_one,page_numbers_two,page_numbers_three),histtype='barstacked',bins=5) pyplot.show() Have you seen this example: http://matplotlib.sourceforge.net/examples/pylab_examples/bar_stacked.html To create the legend, it is best to create proxy objects, eg Rectangles, with the right colors and manually add them to the legend. See http://matplotlib.sourceforge.net/users/plotting/legend.html#using-proxy-artist JDH -- OpenSolaris 2009.06 is a cutting edge operating system for enterprises looking to deploy the next generation of Solaris that includes the latest innovations from Sun and the OpenSource community. Download a copy and enjoy capabilities such as Networking, Storage and Virtualization. Go to: http://p.sf.net/sfu/opensolaris-get___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] Axis default limits with a Circle patch
Hi all,
Consider the following code:
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.gca()
circle = plt.Circle((0, 0), radius = 0.5)
ax.add_patch(circle)
print(plt.axis())
plt.show()
The default axis limits are printed as:
(0.0, 1.0, 0.0, 1.0)
I am not sure why this is the case. So, I would like to learn why?
PS: I know I can just do plt.axis('scaled') so that I can see the entire circle.
I also asked this on SO, so feel free to answer there as well:
http://stackoverflow.com/questions/26824696/matplotlib-axis-default-limits-with-a-circle-patch
Thanks,
-Amit.
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[Matplotlib-users] Histogram appearance
Hi, Please find attached a simple histogram created using the hist() function. Any idea why the last two bars are squeezed into each other? Is there a simple way to fix this while plotting? Thanks, Amit. -- Download BIRT iHub F-Type - The Free Enterprise-Grade BIRT Server from Actuate! Instantly Supercharge Your Business Reports and Dashboards with Interactivity, Sharing, Native Excel Exports, App Integration & more Get technology previously reserved for billion-dollar corporations, FREE http://pubads.g.doubleclick.net/gampad/clk?id=164703151&iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Histogram appearance
On Thu, Dec 4, 2014 at 6:45 AM, Brendan Barnwell wrote: > On 2014-12-03 12:39, Amit Saha wrote: >> >> Hi, >> >> Please find attached a simple histogram created using the hist() >> function. Any idea why the last two bars are squeezed into each other? >> Is there a simple way to fix this while plotting? > > > It looks like the bins are set up so that there are empty bins > between each of the other bars. How are you setting the bins? You could > try adjusting the bin boundaries. Thanks for the reply. This is my program: import matplotlib.pyplot as plt import random def roll(): return random.randint(1, 6) if __name__ == '__main__': rolls = [] for i in range(1000): rolls.append(roll()) # create a histogram plot plt.hist(rolls) plt.show() So, just using the hist() function for now. Thanks, Amit. > > -- > Brendan Barnwell > "Do not follow where the path may lead. Go, instead, where there is no > path, and leave a trail." >--author unknown -- http://echorand.me -- Download BIRT iHub F-Type - The Free Enterprise-Grade BIRT Server from Actuate! Instantly Supercharge Your Business Reports and Dashboards with Interactivity, Sharing, Native Excel Exports, App Integration & more Get technology previously reserved for billion-dollar corporations, FREE http://pubads.g.doubleclick.net/gampad/clk?id=164703151&iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Histogram appearance
Hi, On Thu, Dec 4, 2014 at 7:01 AM, Dino Bektešević wrote: > Hello, > > try doing: > > import matplotlib.pyplot as plt > import random > > rolls = list() > for i in range(1000): > rolls.append(random.randint(1,6)) > > > plt.hist(rolls, bins=6) > plt.show() > > Reason why your histogram is weird is because you only can have 6 bins > in your example. But the default bin number for hist function is 10. > The borders of bins are therefore set at half intervals. When you roll > 1, bin 0 to 0.6 gets incremented, when you roll 2.2 bin 2-2.6 gets > incremented, but the bin 0.6-2.2 never does. Thanks. That helps me in my understanding. Choosing bins = 6 fixes the problem I reported. Best, Amit. -- Download BIRT iHub F-Type - The Free Enterprise-Grade BIRT Server from Actuate! Instantly Supercharge Your Business Reports and Dashboards with Interactivity, Sharing, Native Excel Exports, App Integration & more Get technology previously reserved for billion-dollar corporations, FREE http://pubads.g.doubleclick.net/gampad/clk?id=164703151&iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] Newbie Q re: Lorenz attractor
On Mon, Mar 9, 2015 at 7:31 AM, Prahas David Nafissian wrote: > Hi, > > I want to create an animation of the Lorenz attractor, > plotting each new point as it is generated by the > equations. So we see the graph "being drawn" > over time. You will very likely need to use the animation API for this. I recently tried to demonstrate the Henon function in a fashion that it appears I am drawing it over time: https://www.youtube.com/watch?v=76ll818RlpQ You can see the code linked from there: https://github.com/amitsaha/playground/blob/master/recipes/henon_animation.py That might give you a starting point of what you are trying to do. > > Also, as it is being drawn, I want to be able to > rotate the screen in 3 dimensions. Sorry, nothing much I can add here. Best, Amit. -- http://echorand.me -- Dive into the World of Parallel Programming The Go Parallel Website, sponsored by Intel and developed in partnership with Slashdot Media, is your hub for all things parallel software development, from weekly thought leadership blogs to news, videos, case studies, tutorials and more. Take a look and join the conversation now. http://goparallel.sourceforge.net/ ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] imshow() and pixel intensity
Hi all, Just trying to understand how the value of the matrix fed to imshow() function determines the intensity of the pixel in grey scale mode. Consider the example code: import random import matplotlib.pyplot as plt import matplotlib.cm as cm def pixels(n=3): pixel_data = [] for _ in range(n): row = [] for _ in range(n): row.append(random.randint(1, 10)) pixel_data.append(row) return pixel_data if __name__ == '__main__': pixel_data = pixels() print(pixel_data) plt.imshow(pixel_data, origin='lower', cmap=cm.Greys_r) plt.show() The pixel_data here is the 3*3 "matrix": [[7, 4, 6], [7, 7, 6], [4, 7, 9]] How does the values here determine what shade of grey I see in the image? Thank you in advance. Best, Amit. -- http://echorand.me -- One dashboard for servers and applications across Physical-Virtual-Cloud Widest out-of-the-box monitoring support with 50+ applications Performance metrics, stats and reports that give you Actionable Insights Deep dive visibility with transaction tracing using APM Insight. http://ad.doubleclick.net/ddm/clk/290420510;117567292;y ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] imshow() and pixel intensity
Got my answer here: http://stackoverflow.com/questions/30301986/matplotlib-imshow-and-pixel-intensity On Sun, May 17, 2015 at 10:02 PM, Amit Saha wrote: > Hi all, > > Just trying to understand how the value of the matrix fed to imshow() > function determines the intensity of the pixel in grey scale mode. > Consider the example code: > > import random > import matplotlib.pyplot as plt > import matplotlib.cm as cm > > def pixels(n=3): > pixel_data = [] > for _ in range(n): > row = [] > for _ in range(n): > row.append(random.randint(1, 10)) > pixel_data.append(row) > return pixel_data > > if __name__ == '__main__': > pixel_data = pixels() > print(pixel_data) > plt.imshow(pixel_data, origin='lower', cmap=cm.Greys_r) > plt.show() > > > The pixel_data here is the 3*3 "matrix": > [[7, 4, 6], [7, 7, 6], [4, 7, 9]] > > How does the values here determine what shade of grey I see in the image? > > Thank you in advance. > > Best, > Amit. > > > -- > http://echorand.me -- http://echorand.me -- One dashboard for servers and applications across Physical-Virtual-Cloud Widest out-of-the-box monitoring support with 50+ applications Performance metrics, stats and reports that give you Actionable Insights Deep dive visibility with transaction tracing using APM Insight. http://ad.doubleclick.net/ddm/clk/290420510;117567292;y ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] plot() and imshow() relationship
Hi all, I am trying to understand if there is a way to compare how plot() and imshow() works for the case where I am not using imshow() to display an image. Via the plot() function, I am specifying the points that I want to plot and also optionally the color that i want the points to be in. For example, plot([1, 2, 3], [2, 3, 4], 'ro') will create a plot with those points colored "red". Via the imshow() function, we specify the color (or intensity) of each point and a figure is created with the points colored accordingly. Sure, imshow() allows me to color each point differently. Is there a way to relate them? Also asked on StackOverflow: http://stackoverflow.com/questions/30527811/plot-and-imshow-relationship Thanks, Amit. -- http://echorand.me -- ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] plot() and imshow() relationship
On Sat, May 30, 2015 at 1:50 AM, Paul Hobson wrote: > imshow is for displaying arrays as images/rasters. > > plot is for showing data/functions as points and lines. > > See the gallery for imshow: > http://matplotlib.org/gallery.html#images_contours_and_fields Thanks Paul. I have since then have been able to develop a better understanding of imshow() and it doesn't seem very sensible to try and compare/relate it to what plot() does. -- http://echorand.me -- ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
[Matplotlib-users] colorbar() ticklabel color
Hi,
I am trying to produce a pcolor figure with a black background using
pylab.figure(facecolor = 'black')
Consequently, I need to change the tick colors and xlabel and ylabel
colors to white using
pylab.xlabel('whatever is on the xlabel', color = 'white', fontsize
= 14)
pylab.ylabel('whatever is on the ylabel', color = 'white', fontsize
= 14)
pylab.yticks(color = 'white')
pylab.xticks(color = 'white')
Up to this point, everything is OK. The next thing I need to do is
change the colors of the ticks and the ticklabels in the colorbar. I
understand that there are no simple pylab. commands which do so. I saw
in some matplotlib-users messages that one can write the following to
change the fontsize, for example:
for t in cb.ax.get_yticklabels():
t.set_fontsize(14)
I tried adding another line to this loop:
t.set_color('white')
On one hand, there is no error message during parsing or compilation. On
the other hand, nothing actually changes, i.e. the color of the
ticklabels and ticks stays black.
How does one change this property?
Amit
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Re: [Matplotlib-users] Labels in a dynamic graph
John Hunter wrote:
> On Sun, Mar 23, 2008 at 3:54 AM, Amit Finkler <[EMAIL PROTECTED]> wrote:
>
>
>> I am using matplotlib to dynamically plot a graph with both my x and y
>> points taken from a measurement device. That is to say, in each iteration of
>> my while loop I'm reading two variables which I then want to plot with
>> matplotlib.
>>
>
> You will want to do something like (this is just a sketch)
>
> xdata = []
> ydata = []
>
> fig = figure()
> ax = fig.add_subplot(111)
> ax.set_xlabel('my xlabel')
> ax.set_ylabel('my ylabel')
> line, = ax.plot(xdata, ydata)
>
> def add_point(x, y):
> xdata.append(x)
> ydata.append(y)
> if len(xdata)>30: # optional, prune the early points
> del xdata[0]
> del ydata[0]
> xmin = xdata[0]
> xmax = xdata[-1]
> line.set_data(xdata, ydata)
> ax.set_xlim(xmin, xmax)
> fig.canvas.draw()
>
> while 1:
> x,y = get_data_point()
> add_point(x, y)
>
> JDH
>
John,
Thanks for getting back to me. Indeed this works, at least when I try it
line by line. When I inserted it into my module, it shot back some error
message which goes like this:
File
"/usr/lib/python2.4/site-packages/matplotlib/backends/backend_tkagg.py",
line 154, in draw
FigureCanvasAgg.draw(self)
File
"/usr/lib/python2.4/site-packages/matplotlib/backends/backend_agg.py",
line 392, in draw
self.figure.draw(renderer)
File "/usr/lib/python2.4/site-packages/matplotlib/figure.py", line
544, in draw
for a in self.axes: a.draw(renderer)
File "/usr/lib/python2.4/site-packages/matplotlib/axes.py", line
1004, in draw
try: self.transData.freeze() # eval the lazy objects
ValueError: Domain error on eval_scalars in Transformation::freeze
Since it did work on the console, i.e., line by line, I think it's only
a matter of resolving my own source code, unless of course you think
otherwise. By the way, isn't there a way to do the set_xlim/ylim
automatically? When I use only figure(), hold(False) and plot(X, Y), it
updates it automatically, so why doesn't it do it with the subplot?
Thanks for your help.
Amit.
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