Re: problem of solving the OPF in distribution system

2018-11-21 Thread Alex David

Hi Jane,

 

Could you share the error message and the case file (maybe)? Then it will be easy to learn the reason.

 

AD

 

Sent: Wednesday, November 21, 2018 at 7:21 PM
From: "Jane Cheung" 
To: "MATPOWER discussion forum" 
Subject: Re: problem of solving the OPF in distribution system



I just use the case data in matpower, something went wrong


 

On Wed, Nov 21, 2018 at 11:01 AM Alex David <alex.david1...@gmx.com> wrote:





Hi Jane,

 

I would suggest to have a look at the casefile (your distribution system case). 

 

Kind regards,

AD

 

Sent: Wednesday, November 21, 2018 at 3:19 PM
From: "Jane Cheung" <cheung180...@gmail.com>
To: matpower-l@cornell.edu, matpowe...@list.cornell.edu
Subject: problem of solving the OPF in distribution system












Hi Ray, 
 

While I was using the MATPOWER 7.0b1 to run the command below:

                                     runopf('filename')

* where filename is the distribution power system case,

All the distribution case system could not be solved and some error came .

 

What changes have been made to the new version of matpower? If the OPF problem for distribution power systems would like to be solved, how to deal with that?

 

Best regards!

 

Jane
















Re: problem of solving the OPF in distribution system

2018-11-21 Thread Alex David

Hi Jane,

 

I would suggest to have a look at the casefile (your distribution system case). 

 

Kind regards,

AD

 

Sent: Wednesday, November 21, 2018 at 3:19 PM
From: "Jane Cheung" 
To: matpower-l@cornell.edu, matpowe...@list.cornell.edu
Subject: problem of solving the OPF in distribution system


Hi Ray, 
 

While I was using the MATPOWER 7.0b1 to run the command below:

                                     runopf('filename')

* where filename is the distribution power system case,

All the distribution case system could not be solved and some error came .

 

What changes have been made to the new version of matpower? If the OPF problem for distribution power systems would like to be solved, how to deal with that?

 

Best regards!

 

Jane







Re: AC OPF convergence/termination criteria

2018-09-17 Thread Alex David

Dear Ray,

 

Thank you for the explanation. Sorry for the confusion. I am working on probabilistic OPF. Indeed, I am using MATPOWER's deterministic power to implement my probabilistic OPF. 

 

Kind regards,

AD

 

 

 

Sent: Monday, September 17, 2018 at 7:39 PM
From: "Ray Zimmerman" 
To: "MATPOWER discussion forum" 
Subject: Re: AC OPF convergence/termination criteria


First, MATPOWER does not itself implement a probabilistic power flow, so I assume you mean you are using MATPOWER’s deterministic power flow to implement your own. However, MIPS is an optimization tool used by the OPF, not by the power flow. So, I’m not sure which you really mean.
 

Finally, the default termination criteria for MIPS or the Newton power flow should generally be fine. All you need to do is check the success flag to be sure that it converged successfully.

 

Hope this helps,

 

    Ray

 

 

On Sep 15, 2018, at 3:56 AM, Alex David <alex.david1...@gmx.com> wrote:
 





Dear Ray and others,

 

I have a basic question about the convergence/termination criteria. I want to run probabilistic power flow using AC solver and MIPS without any contingency. How do I decide the termination criteria? Or in other words, my OPF converges.

 

Sorry if it is a lame question. I am not just getting any idea.

 

Thanks

AD















AC OPF convergence/termination criteria

2018-09-15 Thread Alex David

Dear Ray and others,

 

I have a basic question about the convergence/termination criteria. I want to run probabilistic power flow using AC solver and MIPS without any contingency. How do I decide the termination criteria? Or in other words, my OPF converges.

 

Sorry if it is a lame question. I am not just getting any idea.

 

Thanks

AD



AC OPF convergence/termination criteria

2018-09-14 Thread Alex David
Dear Ray and others,

 

I have a basic question about the convergence/termination criteria. I want to run probabilistic power flow using AC solver and MIPS without any contingency. How do I decide the termination criteria? Or in other words, my OPF converges.

 

Sorry if it is a lame question. I am not just getting any idea.

 

Thanks

AD


Re: Line Real Power in p.u.

2018-03-27 Thread Alex David

Dear Gorazd,

 

Thank you for the explanation. Yes, I understand the concept of p.u. So, in this case, the real power capacity of line will be (130/100)?

 

Alex

 

Sent: Tuesday, March 27, 2018 at 6:54 PM
From: "Bone, Gorazd" <gorazd.b...@fe.uni-lj.si>
To: "MATPOWER discussion forum" <matpowe...@list.cornell.edu>
Subject: Re: Line Real Power in p.u.



​Power in pu = actual power / base power

 

the base power is usually 100 MVA and the power is given in MW so it's usually just about dividing by 100.



Od: bounce-122419795-80056...@list.cornell.edu <bounce-122419795-80056...@list.cornell.edu> v imenu Alex David <alex.david1...@gmx.com>
Poslano: 27. marec 2018 17:13
Za: matpower-l@cornell.edu
Zadeva: Line Real Power in p.u.

 




Dear all,

 

I have a query regarding line real power in p.u. For any test case, say case30, the branch details are given in p.u. I was curios as how to calcuate the real line flow in p.u. Any pointers will be really helpful.

 

E.g. Line 3-4 in case 30,

3    4    0.01    0.04    0    130    130    130    0    0    1    -360    360;

 

Thanks in advance,

Alex











Line Real Power in p.u.

2018-03-27 Thread Alex David
Dear all,

 

I have a query regarding line real power in p.u. For any test case, say case30, the branch details are given in p.u. I was curios as how to calcuate the real line flow in p.u. Any pointers will be really helpful.

 

E.g. Line 3-4 in case 30,

3    4    0.01    0.04    0    130    130    130    0    0    1    -360    360;

 

Thanks in advance,

Alex



Re: Transmat details

2018-01-25 Thread Alex David

Dear Ray,

 

Thanks for the reply. Yes I did. Unfortunately, it was not very clear to me. In addition, the values of T =  = [ 0.158655253931457; 0.682689492137086; 0.158655253931457 ] did not make any sense to me.

 

Alex

 

Sent: Thursday, January 25, 2018 at 3:04 PM
From: "Ray Zimmerman" <r...@cornell.edu>
To: "MATPOWER discussion forum" <matpowe...@list.cornell.edu>
Subject: Re: Transmat details


Did you check Section 5.1.2 in the MOST User’s Manual?

 

   Ray
 

On Jan 17, 2018, at 8:20 PM, Alex David <alex.david1...@gmx.com> wrote:
 





Dear Ray/others,

 

I have a question regarding "transmat" value used in "most ex7 suc.m". Mainly, I'm confused with the values given in "ex_transmat(nt)":

 

T = [ 0.158655253931457; 0.682689492137086; 0.158655253931457 ]

 

Any pointers can be very helpful. Also, pardon for the naive question (if it is).

 

Thanks,

Alex















Transmat details

2018-01-17 Thread Alex David

Dear Ray/others,

 

I have a question regarding "transmat" value used in "most ex7 suc.m". Mainly, I'm confused with the values given in "ex_transmat(nt)":

 

T = [ 0.158655253931457; 0.682689492137086; 0.158655253931457 ]

 

Any pointers can be very helpful. Also, pardon for the naive question (if it is).

 

Thanks,

Alex