Mersenne: Prime95 as a windows service

1999-07-23 Thread Rick Pali

This may be a silly question but I've only recently had the need for Prime95
having used the NT service version before.

If Prime95 is running as a service, how does one get at the user interface?
It doesn't have a separate interface executable like the NT service version.
Do I just start the executable manually? I don't want to just go ahead and
do that because it *used* to corrupt the safe file and I'm not sure that it
still doesn't. :-) Even still, I don't want to start another copy crunching.

If anyone can let me know, I'd appreciate it.

Rick.
-
[EMAIL PROTECTED]
http://www.alienshore.com/

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Re: Mersenne: Worth it?

1999-07-23 Thread Chris Nash

Heya Lucas

> P-1 factoring is based upon Fermat's little theorem which states that
> with gcd(a,p)=1, p prime, a^(p-1)==1 mod p
> What if we use 2 as a base?  Well, for mersenne numbers, this might be to
> our advantage.  Note that 2^n==1 mod Mn, hence 2^q==2^(q mod n) mod Mn.

Unfortunately we're in a circular argument at this point. The factors of
2^p-1 are of the form 2kp+1 - also, even for n composite, the 'new'
(primitive) factors of 2^n-1 are of the form kn+1. So any prime factor q has
q-1 divisible by n, and we already have 2^n=1 mod Mn and hence mod q...

Alternatively, think of the values 2^0, 2^1, 2^2... 2^(n-1), which would be
ALL the values 2^q mod Mn can possibly take. So if this method found a
factor, it would be a common factor of 2^q-1 and 2^n-1, in other words, just
one of the known algebraic factors 2^gcd(q,n)-1.

P-1 is good up to a point... the prime factors P it finds will by definition
either have ALL factors of P-1 very small, or your initial base is already a
high power (which is very unlikely). It's good to find the 'smooth' P-1's -
put it another way, the factors the P-1 algorithm finds are themselves very
easy to prove prime or composite. While the vast majority of primes (and
thus potential factors) certainly do not always have small factors in P-1.
It will catch a few several digit factors - after that, you've pretty well
exhausted the lowest cherries off the tree.

Chris


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Re: Mersenne: Mersenne Trivia (was Re: p-1 algorithm)

1999-07-23 Thread Conrad Curry



On Fri, 23 Jul 1999 [EMAIL PROTECTED] wrote:
> 
> EXERCISE: which movie is the following quote from?
> 
> "...and three shall be the number of the counting. Four shalt thou not count,
> nor two, excepting thou then proceed to three. Five is right out..."
> 
> -Ernst

  Too easy.  Here's more of a challenge, who wrote this about the
perfection of the number six?

"For six is the first number that is filled by conjuction of the parts,
the sixth, the third, and the half: which is one, two, and three; all
which conjoined are six. Parts in numbers are those that may be described
by how many they are, as a half, a third, a fourth, and so forth. But four
being in nine, yet is no just part of it: one is the ninth part, and three
the third part. But these two parts, one and three, are far from making
nine the whole. So four is a part of ten, but no just part: one is the
tenth part, two the fifth, and five the second: yet these three parts one,
two, and five, make not up full ten, but eight only. As for the number of
twelve, the parts exceed it. For there is one the twelfth part, six the
second, four the third, three the fourth, and two the sixth. But one, two,
three, four, and six, make about twelve, namely sixteen. This by the way
now to prove the perfection of the number of six, the first (as I said)
that is made of the conjuction of the parts..."

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Re: Mersenne: Re: p-1 algorithm

1999-07-23 Thread Joth Tupper

A small observation, maybe even trivial:

Viewed over a finite ring (field) of Mp = 2^p - 1  elements  the polynomial
x^p - 1 splits (completely, of course) into linear factors of the form  (x -
2^r) for 0 <= r <= p-1.

Alternatively,  x^p - 1 = (x-1)(x-2)(x-4)(x-8)(...)[ x - 2^(p-1)]  (mod Mp)

As a buddy once asked, "So what?"  I rarely had a good answer for him and I
do not have one now.

Joth

- Original Message -
From: <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, July 23, 1999 11:36 AM
Subject: Mersenne: Re: p-1 algorithm


> Lucas Wiman wrote, about the p-1 algorithm:
>
> >What if we use 2 as a base?
>
> Unfortunately, 2 is not an eligible base for the powering.
>
> Example: let's attempt to factor 2^11 - 1 = 23*89 via p-1. The smaller
> factor has p-1 = 22=2*11, so raising the base to the powers 2 and 11
> and gcd'ing should reveal the factor. Let's denote the product of the
> small primes used for the powering by #, and try bases A = 2 and 3:
>
> A=2: 2^22 mod M11 = (2^11)^2 mod M11 == 1. You can continue to power until
> you're blue in the face, and all you'll ever get is one, i.e. gcd(a^#-1,
M11)
> = 0.
>
> A=3: 3^22 mod M11 = 1013, so gcd(a^#-1, M11) = gcd(1012,2047) = 23.
>
> For Mersennes you can in fact use any base you like, as long as it's not
> a power of 2.
>
> EXERCISE: We wish to attempt to find an odd prime factor p of a number N
> via the p-1 method. What is the mathematical requirement for A to be an
> eligible base for the powering?
>
> EXERCISE: which movie is the following quote from?
>
> "...and three shall be the number of the counting. Four shalt thou not
count,
> nor two, excepting thou then proceed to three. Five is right out..."
>
> -Ernst
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>

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Mersenne: Re: p-1 algorithm

1999-07-23 Thread EWMAYER

Lucas Wiman wrote, about the p-1 algorithm:

>What if we use 2 as a base?

Unfortunately, 2 is not an eligible base for the powering.

Example: let's attempt to factor 2^11 - 1 = 23*89 via p-1. The smaller
factor has p-1 = 22=2*11, so raising the base to the powers 2 and 11
and gcd'ing should reveal the factor. Let's denote the product of the
small primes used for the powering by #, and try bases A = 2 and 3:

A=2: 2^22 mod M11 = (2^11)^2 mod M11 == 1. You can continue to power until
you're blue in the face, and all you'll ever get is one, i.e. gcd(a^#-1, M11) 
= 0.

A=3: 3^22 mod M11 = 1013, so gcd(a^#-1, M11) = gcd(1012,2047) = 23.

For Mersennes you can in fact use any base you like, as long as it's not
a power of 2.

EXERCISE: We wish to attempt to find an odd prime factor p of a number N
via the p-1 method. What is the mathematical requirement for A to be an
eligible base for the powering?

EXERCISE: which movie is the following quote from?

"...and three shall be the number of the counting. Four shalt thou not count,
nor two, excepting thou then proceed to three. Five is right out..."

-Ernst
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Re: Mersenne: Worth it?

1999-07-23 Thread Alex Kruppa


Lucas Wiman wrote:

> P-1 factoring is based upon Fermat's little theorem which states that
>
> [...]
> What if we use 2 as a base?  Well, for mersenne numbers, this might be to

The problem is that 2 is not a primitive root (mod Mp). From a computers
point of view, the mod Mp operation is a rotate and add, so if you
start with a single bit set (2d = 10b), that bit will rotate around the
p possible positions like mad but you´ll only ever get values of 2^n,
2^E == 2^n (mod Mp). So you could only find factors of the form
2^n-1.

Ciao,
  Alex.

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Mersenne Digest V1 #602

1999-07-23 Thread Mersenne Digest


Mersenne Digest Friday, July 23 1999 Volume 01 : Number 602




--

Date: Thu, 22 Jul 1999 11:26:03 -0400
From: Pierre Abbat <[EMAIL PROTECTED]>
Subject: Mersenne: Computing noises; was Worth it?

> (Off topic, when I computed that value in Landon's Calc program, my computer
> PII/233 started making a weird humming noise.  The noise stopped when the
> calculation finished.  Very strange indeed...)

I'm running Prime95 on a computer at the office, and it emits faint cricketish
noises from the speakers while it's working.

phma
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--

Date: Thu, 22 Jul 1999 16:50:34 +0100
From: Gordon Spence <[EMAIL PROTECTED]>
Subject: Mersenne: Re: Allocation of Prize Fund

I have watched with interest the ideas flowing around for the distribution of
the prize money awarded by the EFF and how we should try and reach an
equitable
distribution.

In fact the answer is simple, the person who discovers it is *entitled* to it,
end of story. I would hope that they would *choose* to donate some to George
and Scott, but if they decide not to well then that is up to them.

Direct quote from eff page

>
> Through the EFF Cooperative Computing Awards, EFF will confer prizes of: 
>  $50,000 to the first individual or group who discovers
> a prime number with at least 1,000,000 decimal digits 


Seems clear to me, the GIMPS s/w is given away free to the individual who runs
the test. If we want to amend that then George will (or have to get drawn
up) a
legally binding software license. Now of course if the next winner comes
from a
country who doesn't recognise US laws...

Now that would be interesting, what would the EFF do then given that they are
entirely about freedom and the rights of the infividual.

As a Mersenne prime discoverer it would appear that I would be on the panel(s)
that have been suggested, and my vote goes to allowing the discoverer to keep
it and do what their conscience tells them is the right thing to do.

I don't agree with Luke's sentiments about orderly progress, having already
tested one number in the 20m range. As soon as V19 is available I'm jumping up
into the 33-35m range. As long as they all get tested does it matter in what
order?

So a test will take my PII-300 about 3 years, so what, if I've got the
patienceI can always switch the intermediate results over to faster
processors as I get them.

regards

Gordon Spence (finder of M2976221 which earned me precisely $0.00  )


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--

Date: Thu, 22 Jul 1999 10:47:39 -0600
From: "Blosser, Jeremy" <[EMAIL PROTECTED]>
Subject: Mersenne: Squaring algorithm...

Just was thinking the other day about this... Forgive me if its been
discussed before etc.

Aren't there other "better" algorithms for finding the square of a number
besides using an FFT? Sure an FFT is great for multiplying two different
numbers, but for squaring a number isn't the case a little different. Plus,
going off what I've read on FFT's, it runs in O(n log n) time.

So wouldn't a summation algorithm work better.

For example, to find the square of a number k take the sum of n=1 to n=k of
2n-1.

So 3**2 is 1+3+5 = 9
4**2 is 1+3+5+7 = 16
etc...

So the sqaure performs in O(n) time. Plus, you could already throw in the
sub 2 by starting at -1 instead of 1. And figuring out the mod is just as
easy.

k is the sum of n=2**p-1 to n=k of 2n-1 (This would give k**2 - 2**p-1).

The only hassle is adding *big* numbers up, but I'm not sure how the
ramifications of doing carries across boundaries and such would factor into
the equation etc.

Just a thought.

- -Jeremy
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--

Date: Thu, 22 Jul 1999 19:11:07 +0200
From: "Hoogendoorn, Sander" <[EMAIL PROTECTED]>
Subject: RE: Mersenne: The sound of number searching

Read the archives, this has been discussed 2 or 3 times before

- -Original Message-
From: burlington john [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, July 21, 1999 19:47
To: [EMAIL PROTECTED]
Subject: Mersenne: The sound of number searching


Hello Mersenne,

  Sorry for bad english its not my native language, thanks.


  I run mprime (or prime95 ntprime) on my laptop.

  When I start the programm on my notebook it makes a strange mechanical
  pulsing sound like an old damaged wheel or like an ill cricket.
  The sound doesn't come out of the speakers 

Re: Mersenne: The sound of number searching

1999-07-23 Thread Kipton Moravec

Back in 1974 I got a summer job as a night time computer operator for a
NCR Century-101 (32K core memory) with two 5 MB 14" Disk Drives.  Most
things were on cards. 

The programmer had programs that would play simple tunes on the radio if
the radio was on or very near the computer.  He had about a dozen
different programs in COBOL for different tunes, like Dixie, Swanie
River, etc.

He would also use the radio as feedback as to whether his program was
running correctly or not.  He could then monitor the progress from
across the room, without looking at the console.

Kip


Luke Welsh wrote:
> 
> At 11:35 PM 7/22/99 +0100, Brian J. Beesley wrote:
> 
> >Back more or less to topic -
> 
> Oh, this is very much on topic!
> 
> > when I was a computing neophyte, a
> >quarter of a century ago, I was told a story by an engineer working
> >for a major mainframe supplier. For a laugh, the development team
> >wired up a loudspeaker (presumably through a buffer and amplifier of
> >some sort) to one of the bits in a CPU shift register. (This was
> >easily done in the days when everything was discrete components!)
> >The trick was then to code your program so that it performed to
> >specification, but, by insertion of extra instructions to tweak this
> >particular bit at suitable times, played interesting tunes whilst
> >doing so!
> 
> Alex Hurwitz loves this story.  They did just that on the SWAC.  It
> was captured for prosperity in the film 'Magnetic Monster'.  I once
> made some MPegs and put them on the wwweb.  I wonder if they are
> still there?  Alex says the sounds in the movie were produced by LL
> tests.
> 
> I recall the CDC 3150 was so wired from the factory.  There was
> even a volume control on the operator's console.  Probably a very
> helpful debug tool as you could not see the console when you were
> across the room with your head inside a 32 KB memory bank the size
> of a refrigerator, poking away looking for faulty a core memory.
> 
> --Luke
> 
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Mersenne: Links in the FAQ

1999-07-23 Thread Lucas Wiman

I added a supplemental resources, and references section to
the FAQ.  Feel free to send me any links/books that you think
should go in there.

I'm trying to keep everything at least tangentaly related to the
FAQ's on this list (and yes, the sites about general primality
proving, and factoring are supposed to be there)...

Thank you,
-Lucas
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