Re: $r-path_info question
* simran [EMAIL PROTECTED] [2002-07-23 05:11]: However: if i create an 'auto' directory in my document root (something that was not there before) [-- snip --] Is this is feature or a bug, does path_info not check the 'Location' it matced the handler to or is it meant to look at the directory structure? This is how Apache handles path_info: it is the extra stuff after the translation handler has found a directory and filename. It starts at the left, and walks towards the right, until it finds the last component that is a directory, and then the next piece is the file (no existance check is done at this point). The rest of it is path_info. For example: A request for /foo/bar/baz/quux, with a document root of /document/root (assuming no Alias directives, that complicates things slightly), and assuming that /document/root/foo is the last *directory* in the path that exists, Apache does this: 1. look for /document - yep 2. look for /document/root - yep 3. look for /document/root/foo - yep 4. look for /document/root/foo/bar - nope So /document/root/foo/bar is r-filename, and /baz/quux is path_info. To reiterate: this is not a mod_perl thing (bug/whatever) but an Apache one. (darren) -- An operating system is just a name you give the features you left out of your editor. -- Per Abrahamsen in comp.emacs
Re: $r-path_info question
Drew Taylor said... Hi all, Hi. I currently am using my $filename = (split /\//, $r-path_info)[1]; but it seems like such a hack. What is the "suggested" way to get the "A1234567.jpg" part of the above URL? Since Apache sets path_info by scanning the physical filesystem, and since you are overcoming legacy calls to a script inside cgi-bin, your solution is probably just fine. I had a similar issue in the past: http://forum.swarthmore.edu/epigone/modperl/smumbabax As Doug mentions in that thread, $r-location might be of some assistance. Hope this helps. -- David S. Kenzik [EMAIL PROTECTED] - http://kenzik.com
Re: $r-path_info question
David Kenzik wrote: Drew Taylor said... I currently am using my $filename = (split /\//, $r-path_info)[1]; but it seems like such a hack. What is the "suggested" way to get the "A1234567.jpg" part of the above URL? Since Apache sets path_info by scanning the physical filesystem, and since you are overcoming legacy calls to a script inside cgi-bin, your solution is probably just fine. I had a similar issue in the past: http://forum.swarthmore.edu/epigone/modperl/smumbabax As Doug mentions in that thread, $r-location might be of some assistance. That was an interesting thread. However, I think Eric found the easiest solution for me. This handler is very simple and if the requested file does not pass -e, it just returns NOT_FOUND. So I guess I'll stick with my original thinking for now. Thanks. -- Drew Taylor Vialogix Communications, Inc. 501 N. College Street Charlotte, NC 28202 704 370 0550 http://www.vialogix.com/
Re: $r-path_info question
Hi all, I am using $r-path_info in an Apache handler. The handler is set via a Location directive: Location /cgi-bin/detail.pl # Overcoming Legacy code :-) SetHandler perl-script PerlHandler eLogix::Images::Detail /Location And is called like "/cgi-bin/detail.pl/A1234567.jpg". My question is this: Since there is no physical filename which corresponds to the URL, what does path_info contain? In the eagle book on page 135, when path_info is first discussed, the example uses $r-lookup_uri($path_info) to get the filename, which in this example is a purely virtual tree. $r-path_info contains what's left of the URI after it's been mapped to a (virtual) file, in your case /A1234567.jpg I currently am using my $filename = (split /\//, $r-path_info)[1]; or you could have used (my $filename = $r-path_info) =~ s!^/!!; but it seems like such a hack. What is the "suggested" way to get the "A1234567.jpg" part of the above URL? Since you have no trailing slash in your Location directive, you get a leading / in path_info. What would be the filename if the request URI was /cgi-bin/detail.pl/foo/bar.jpg ? In that case path_info will be '/foo/bar.jpg'. Maybe what you really want is my $filename = (split /\//, $r-path_info)[-1]; whatever... it's completely up to the application to define the semantics of path_info. -- Drew Taylor -- Eric
