Re: [Mono-dev] Mono.CSharp.Evaluator: x.GetType Bug?

2013-01-31 Thread Marek Safar 
Hi,

This is regarding Mono 3.0.3: Mono.CSharp.Evaluator

 When I instantiate an Evaluator and then then evaluate following input:

 var context = new CompilerContext(new CompilerSettings(), new
 ConsoleReportPrinter());
 var evaluator = new Evaluator(context);
 evaluator.DescribeTypeExpressions = true;

 object result = null;
 bool set = false;
 evaluator.Evaluate(class A{ public int X;}, out result, out set);

 //this works
 evaluator.Evaluate(var a = new A();a.GetType();, out result, out
 set);
 Console.WriteLine(result);

 //this doesnt work
 evaluator.Evaluate(var a = new A();, out result, out set);
 //Error here:
 evaluator.Evaluate(a.GetType();, out result, out set);
 Console.WriteLine(result);

 I get an error in the second last line:
 System.IO.FileNotFoundException: Could not load file or assembly 'eval-0,
 Version=0.0.0.0, Culture=neutral, PublicKeyToken=null' o
 r one of its dependencies. The system cannot find the file specified.
 File name: 'eval-0, Version=0.0.0.0, Culture=neutral, PublicKeyToken=null'
at InteractiveExpressionClass.Host(Object $retval)
at Mono.CSharp.Evaluator.Evaluate(String input, Object result, Boolean
 result_set)
at MonoEval.Program.Main(String[] args) in
 C:\Users\Luke\Dev\Samples\MonoEval\Program.cs:line 30


This seems to happen only when run on .NET. Could you fill a bug report.

Thanks
Marek
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Re: [Mono-dev] Mono.CSharp.Evaluator: x.GetType Bug?

2013-01-25 Thread Robert Jordan 

On 25.01.2013 18:33, lukebuehler wrote:

 //this doesnt work
 evaluator.Evaluate(var a = new A();, out result, out set);
 //Error here:
 evaluator.Evaluate(a.GetType();, out result, out set);
 Console.WriteLine(result);


Local variables don't survive the evaluation. You must Run() them:

evaluator.Run(var a = new A(););
evaluator.Evaluate(a.GetType(););


Robert


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Re: [Mono-dev] Mono.CSharp.Evaluator: x.GetType Bug?

2013-01-25 Thread lukebuehler 
No that doesn't work.

1. Your code gives me the same exception
2. A quick look with reflector shows me that eval.Run is just a wrapper
over eval.Evaluate.
3. To prove it, this works:
evaluator.Evaluate(class A{ public int X;}, out result, out set);
evaluator.Evaluate(var a = new A{X=10};, out result, out set);
evaluator.Evaluate(var b = new A{X=20};, out result, out set);
// this prints 30 without an exception
evaluator.Evaluate(print(a.X+b.X);, out result, out set);

It's only the GetType call that trips up the compiler.

Cheers
-luke


On Fri, Jan 25, 2013 at 12:58 PM, Robert Jordan [via Mono] 
ml-node+s1490590n4658289...@n4.nabble.com wrote:

 On 25.01.2013 18:33, lukebuehler wrote:
   //this doesnt work
   evaluator.Evaluate(var a = new A();, out result, out set);
   //Error here:
   evaluator.Evaluate(a.GetType();, out result, out set);
   Console.WriteLine(result);

 Local variables don't survive the evaluation. You must Run() them:

 evaluator.Run(var a = new A(););
 evaluator.Evaluate(a.GetType(););


 Robert


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