RE: MySQL 5.0 error after upgrade

2006-01-19 Thread Kerry Frater
Thanks,

I'll look to see how to use the system. But you are right that there is an
issue somewhere given that the automatic code produced by Administrator,
Control Centre and Browser all have problems with communicating with the
tables following the upgrade.

Kerry


-Original Message-
From: Gleb Paharenko [mailto:[EMAIL PROTECTED]
Sent: 18 January 2006 15:57
To: mysql@lists.mysql.com
Subject: Re: MySQL 5.0 error after upgrade


Hello.

 ALTER TABLE `filos`.`settings` MODIFY COLUMN `IntVal` INTEGER
CHARACTER SET latin1 COLLATE latin1_general_ci;

This seems like a bug. MySQL Administrator should not assign character
set to integer columns. See:
  http://dev.mysql.com/doc/refman/5.0/en/bug-reports.html


Kerry Frater wrote:
 Can someone help me.

 I was running v4 and just upgraded the version to v5.0.

 Most of my tables are MyISAM with some InnoDb. Most of the MyISAM tables
are
 char fields but a few have integer columns. When trying to create a new
 table using the Administrator 1.1 program it is fine creating columns
which
 are of type char but it fails when creating a column of type integer.
 The error message is
 ALTER TABLE `filos`.`settings` MODIFY COLUMN `IntVal` INTEGER CHARACTER
SET
 latin1 COLLATE latin1_general_ci;

 Can someone advise me what has changed in the upgrade and how I can get
back
 to using integers?

 kERRY



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problem on mysql.sock and mysql.host

2006-01-19 Thread Chen Abella
i cant start mysql.
error in the log says: 
Fatal error: Can't open and lock privilege tables:
Table 'mysql.host' doesn't exist

service configuration says:
mysqld dead but subsys locked.

i can't find any mysql.sock in /var/lib/mysql

i reinstalled MySQL through yum but error is still the
same. 

i was able to run MySQL before. i was even able to
replicate. 
i dont know what's wrong. 

i tried many things in different forums but all is
still the same..

please can anyone help? =(

im using FC4. thanks...



   chEn 



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problem on mysql.sock and mysql.host

2006-01-19 Thread Chen Abella
i cant start mysql.
error in the log says: 
Fatal error: Can't open and lock privilege tables:
Table 'mysql.host' doesn't exist

service configuration says:
mysqld dead but subsys locked.

i can't find any mysql.sock in /var/lib/mysql

i reinstalled MySQL through yum but error is still the
same. 

i was able to run MySQL before. i was even able to
replicate. 
i dont know what's wrong. 

i tried many things in different forums but all is
still the same..

please can anyone help? =(

im using FC4. thanks...



   chEn 



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question about recovery with binlog

2006-01-19 Thread wangxu
  Mysqlbinlog throw out a error ERROR 1231 (42000) at line 10: Variable 
'sql_mode' can't be set to the value of '501481487' when i recovery a binlog. 

  What can i do?

Re: question about recovery with binlog

2006-01-19 Thread Gleb Paharenko
Hello.

Are you sure that the bug is thrown by mysqlbinlog? May be you're
getting this while importing the output produced by mysqlbinlog?
Have a look here:
  http://bugs.mysql.com/bug.php?id=13897

Check that you're using the same versions of mysql client and mysqlbinlog.


wangxu wrote:
   Mysqlbinlog throw out a error ERROR 1231 (42000) at line 10: Variable 
 'sql_mode' can't be set to the value of '501481487' when i recovery a 
 binlog. 
 
   What can i do?


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Re: problem on mysql.sock and mysql.host

2006-01-19 Thread Gleb Paharenko
Hello.

Have you run mysql_install_db? See:
  http://dev.mysql.com/doc/refman/5.0/en/unix-post-installation.html



Chen Abella wrote:
 i cant start mysql.
 error in the log says: 
 Fatal error: Can't open and lock privilege tables:
 Table 'mysql.host' doesn't exist
 
 service configuration says:
 mysqld dead but subsys locked.
 
 i can't find any mysql.sock in /var/lib/mysql
 
 i reinstalled MySQL through yum but error is still the
 same. 
 
 i was able to run MySQL before. i was even able to
 replicate. 
 i dont know what's wrong. 
 
 i tried many things in different forums but all is
 still the same..
 
 please can anyone help? =(
 
 im using FC4. thanks...
 
 
 
chEn 
 
 
 
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Re: Timezone settings

2006-01-19 Thread Gleb Paharenko
Hello.

See:
  http://dev.mysql.com/doc/refman/5.0/en/time-zone-support.html


[EMAIL PROTECTED] wrote:
 Dear Friends,
 I need to do the timezone settings so that now() gives the system
 time.Actually first i have installed mysql on a different timezone han
 changed the system time zone but perhaps mysql shows the previous time zone
 or the default time zone only.
 Pl. tell me how to change that .
 I shall be very grateful.
 --
 Regards
 Abhishek jain
 
 
 mail2web - Check your email from the web at
 http://mail2web.com/ .
 
 


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Re: 16 vs 41 byte password hashes

2006-01-19 Thread Gleb Paharenko
Hello.

Most probably the reason is in old_passwords in your configuration file.
You can check this with the following statement:
  show variables like 'old_passwords';



Gary Huntress wrote:
 I have a new installation of MySQL 5.0 (I did not port an old ver).  I
 am running a Ruby on Rails application that uses this db.  I have grants
 for [EMAIL PROTECTED], root@localhost and root@'192.168.0.63'.  The 
 passwords for
 these 3 grants are old style 16 byte hashes.  There was one single grant
 for root that had a 41 byte new style hash.  I thought it was redundant
 and deleted it.
 
 I can log in using the mysql client but my rails application can no
 longer log in.  I'm not 100% sure that the problem is because I removed
 that grant but I'm fairly sure (no other configuration info has changed)
 
 My question is, why when I GRANT all on *.* to root@'localhost'
 identified by 'xxx' do I get a 16 byte hash and not a 41 byte
 hash?   Since my theory is the lack of a grant with a 41 byte hash I'd
 like to test that. How do I create 41 byte password hashes ?
 
 Thanks,
 
 Gary
 
 
 


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Re: Install help on Linux: I cant obtain access

2006-01-19 Thread Gleb Paharenko
Hello.

See:
  http://dev.mysql.com/doc/refman/5.0/en/access-denied.html

Wade Smart wrote:
 01182006 1627 GMT-6
 
 Im on Ubuntu. I have mysql 4.0.24. I have phpmyadmin installed.
 Im a little frustrated at this point so bear with me.
 Mysql is running.
 My book says type in:  mysql -h localhost testto see if the install
 is working. That provides me with Access denied.
 
 I then tried: mysqladmin -u root password newpassword and that failed
 with Access denied. I tried doing that as (computer) root and again I
 received that error.
 
 I just do not understand what it is that I am supposed to do.
 Can someone provide some light?
 
 Wade
 


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Re: Interesting Query Problem

2006-01-19 Thread Gleb Paharenko
Hello.

Perhaps this will work (depends on the version of MySQL you're using):

select question_id
, count(*)
from Records
group by question_id
having question_id not in (
select distinct question_id
from Records r
where member_id = @current_member_id);

@current_member_id equals to current_user

G G wrote:
 Hello,
 
 I have a simple Records table with two columns, member_id and question_id.  
 
  
 
 The object of the query is to retrieve the question_id, as well as how many
 times it's been answered - as long as the current user hasn't answered it
 (member_id).  So, the query shouldn't return any question_id's (and counts)
 if it has been answered by the current user.
 
  
 
  Right now I have this:
 
 SELECT question_id, COUNT(*) as times_answered FROM records GROUP BY
 question_id;
 
  
 
 I've tried throwing in different variants of 'WHERE member_id != X', but all
 that seems to return is the count of questions answered, minus the amount of
 times the particular user has answered them.  For example, if user X has
 answered a question that had been answered another 50 times, my query will
 still return that question_id, but with a count of 49.
 
  
 
 Your help is appreciated in advance.  Thanks!
 
  
 
  
 
 Kind Regards,
 
 Gerald Glickman
 
  
 
 G2 Innovations.com, Inc.
 
 http://www.g2innovations.com http://www.g2innovations.com/ 
 
  
 
 


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Re: Interesting Query Problem

2006-01-19 Thread Marco Neves
Hi,

An alternative for any MySQL version (from 3.23.??) would be:

SELECT r1.question_id,count(r1.member_id)
FROM Records r1
LEFT JOIN Records r2 ON r1.question_id=r2.question_id
AND r2.member_id=member_id
WHERE r2.question_id IS NULL;

member_id must be the member name.

mpneves

On Thursday 19 January 2006 11:18, Gleb Paharenko wrote:
 Hello.

 Perhaps this will work (depends on the version of MySQL you're using):

 select question_id
   , count(*)
 from Records
 group by question_id
 having question_id not in (
   select distinct question_id
   from Records r
   where member_id = @current_member_id);

 @current_member_id equals to current_user

 G G wrote:
  Hello,
 
  I have a simple Records table with two columns, member_id and
  question_id.
 
 
 
  The object of the query is to retrieve the question_id, as well as how
  many times it's been answered - as long as the current user hasn't
  answered it (member_id).  So, the query shouldn't return any
  question_id's (and counts) if it has been answered by the current user.
 
 
 
   Right now I have this:
 
  SELECT question_id, COUNT(*) as times_answered FROM records GROUP BY
  question_id;
 
 
 
  I've tried throwing in different variants of 'WHERE member_id != X', but
  all that seems to return is the count of questions answered, minus the
  amount of times the particular user has answered them.  For example, if
  user X has answered a question that had been answered another 50 times,
  my query will still return that question_id, but with a count of 49.
 
 
 
  Your help is appreciated in advance.  Thanks!
 
 
 
 
 
  Kind Regards,
 
  Gerald Glickman
 
 
 
  G2 Innovations.com, Inc.
 
  http://www.g2innovations.com http://www.g2innovations.com/

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Re: INSERT encrypted data

2006-01-19 Thread Gleb Paharenko
Hello.

What doesn't work? In case you want more help please, provide the
results you want obtain from your query and CREATE statement for you table.



sharif islam wrote:
 mysql insert into ccard values(AES_ENCRYPT(123453535,'uiwuerw'),'10/2003');
 Query OK, 1 row affected (0.00 sec)
 
 mysql select * from ccard
 - ;
 +--+-+
 | crypt| expire  |
 +--+-+
 | )\u\u\u\u\u\u\u  | 10/2003 |
 | )\u\u\u\u\u\u\u  | 10/2003 |
 | )\u\u\u\u\u\u\u  | 10/2003 |
 | )\u\u\u\u\u\u\u  | 10/2003 |
 +--+-+
 4 rows in set (0.00 sec)
 
 why doesn't this work?


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Import from another db....

2006-01-19 Thread ESV Media GmbH

Hi everyone,

how can i import a database export from another database.
I´ve got alway a permission error...
I used mysqlimport  mysqldump...

Thanks in advance

Marco Schierhorn

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Best Configuratuion ( my.cnf ) for a DB with many users and large columns ( Images in BLOB Columns ) on a Website

2006-01-19 Thread ESV Media GmbH

Hey,

what do you think is the best configuration ( my.cnf ) for running a 
database,

which many users access at the same time ( Website - Portal ).
We´ve also saved our Pictures ( nearly 3.500 rows ) in our database.
Every coloumn is round about 60-70 Kbyte, so i had to use mediumblob 
columns.
There are 116 Tables and we have a primary key and an index on every 
table and use them

in ( i hope so ;-)  ) every statement.
Here i´ve a my.cnf from another website.
Would that be an good configuration ?
Thanks in advance

Marco

My.cnf :

# The MySQL server
[mysqld]
port= 3307
socket  = /tmp/mysql.sock
skip-locking
key_buffer_size = 256M
max_allowed_packet = 1M
table_cache = 500
sort_buffer_size = 24M
net_buffer_length = 8K
read_buffer_size = 1M
read_rnd_buffer_size = 256K
myisam_sort_buffer_size = 24M
record_buffer=1M
log-slow-queries
long_query_time = 3
query_cache_size = 512M
max_connections = 500
join_buffer_size = 16M

[mysqldump]
quick
max_allowed_packet = 16M

[mysql]
no-auto-rehash
# Remove the next comment character if you are not familiar with SQL
#safe-updates

[isamchk]
key_buffer = 25M
sort_buffer_size = 25M
read_buffer = 6M
write_buffer = 6M

[myisamchk]
key_buffer = 25M
sort_buffer_size = 25M
read_buffer = 6M
write_buffer = 6M

[mysqlhotcopy]
interactive-timeout


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Re: question about CONTAINS SQL

2006-01-19 Thread Rhino
I am copying the rest of the list with this so that everyone may benefit 
from the discussion.


If your routine modifies data, in other words if it does SQL Update, Insert 
or Delete but your routine definition says only CONTAINS SQL, I would 
expect your routine to fail at runtime. I can't say this with certaintly 
because I don't have one of the newer versions of MySQL that supports these 
routines but I'm pretty sure that you will have a runtime failure. After 
all, CONTAINS SQL implies only that you are creating objects like tables 
within your routine; CONTAINS SQL does not permit the execution of Insert, 
Update, or Delete. Therefore, I expect that you will get a runtime error as 
soon as you do your first Insert, Update, or Delete. If you want to avoid 
the error, use MODIFIES SQL instead of CONTAINS SQL.


Of course the best way to be sure is to try this for yourself. Try the 
routine with CONTAINS SQL and see what happens at runtime. If it fails, as I 
strongly expect, change CONTAINS SQL to MODIFIES SQL DATA and your error 
will almost certainly go away.


Rhino

- Original Message - 
From: wangxu [EMAIL PROTECTED]

To: Rhino [EMAIL PROTECTED]
Sent: Thursday, January 19, 2006 2:54 AM
Subject: Re: question about CONTAINS SQL


  If I create a routine with modification operation and not spectify 
characteristic in CONTAINS SQL | NO SQL | READS SQL DATA | MODIFIES SQL 
DATA.
  In the maunal,the default value is CONTAINS SQL if i haven't spectify 
a values.
  If it's meaning that the routine with CONTAINS SQL  include 
modification operation?

  Should many problem happen?


- Original Message - 
From: Rhino [EMAIL PROTECTED]

To: wangxu [EMAIL PROTECTED]; mysql@lists.mysql.com
Sent: Thursday, January 19, 2006 12:21 AM
Subject:Re: question about CONTAINS SQL


If you are writing something that does INSERT, UPDATE, or DELETE, you 
need

to use the MODIFIES SQL DATA option.

Rhino

- Original Message - 
From: wangxu [EMAIL PROTECTED]

To: Rhino [EMAIL PROTECTED]; mysql@lists.mysql.com
Sent: Wednesday, January 18, 2006 3:05 AM
Subject: Re: question about CONTAINS SQL





 But what is  INSERT OR UPDATE need?

 - Original Message - 
 From: Rhino [EMAIL PROTECTED]

 To: wangxu [EMAIL PROTECTED]; mysql@lists.mysql.com
 Sent: Tuesday, January 17, 2006 9:49 PM
 Re: question about CONTAINS SQL


  - Original Message - 
  From: wangxu [EMAIL PROTECTED]

  To: mysql@lists.mysql.com
  Sent: Tuesday, January 17, 2006 12:35 AM
  Subject: question about CONTAINS SQL
 
 
  I notice there are one section in the manual:
  
   CONTAINS SQL indicates that the routine does not contain 
   statements

   that
   read or write data.
  
   And that the option is default.
  
   It's true?
  
   If i wouldn't do read or write in routine.What can i do yet?
  
 
  Commands like GRANT or REVOKE or CREATE TABLE don't read or write 
  data
  within tables but they involve SQL so commands like this need 
  CONTAINS

  SQL,
  rather than the NO SQL, READS SQL DATA or MODIFIES SQL DATA options.
 
  Rhino
 
 
 
 
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  16/01/2006
 
 
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Error from mysqldump

2006-01-19 Thread Rhino
I have an automated backup script that has been running daily for a couple 
of years now. It has never given me trouble until the last two days. For the 
last two days, I have been getting this message when backing up my newest 
database:


/usr/bin/mysqldump: Got error: 1064: You have an error in your SQL syntax. 
Check the manual that corresponds to your MySQL server version for the right 
syntax to use near 'References READ /*!32311 LOCAL */' at line 1 when using 
LOCK TABLES


This is the relevant portion of my backup script:

for ONE_DBNAME in `echo show databases | mysql -s -u $USERID -p$PASSWORD`
do
  echo
  echo Backing up database $ONE_DBNAME;
  /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME} -r ${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql

  echo  Deleting these old backups for this database...
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -print; #display old 
backups (if any)
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -exec rm '{}' ';' 
#delete old backups (if any)

done


I'm at a loss to see why I'm getting this error for only one database when 
the exact same logic is applied for each of my databases and works fine for 
all the others.


I've tried doing the backup manually from the command line and found that I 
got the same error when I tried to backup the Maximal database that way; a 
manual backup of another database worked fine.


The only idea I have that seems vaguely plausible is that there is something 
internally wrong with my database but I'm darned if I know what the problem 
could be. When I do 'select *' against each of the five small tables in this 
database, each returns exactly the right data and there are no errors or 
warnings of any kind.


Can anyone suggest queries or commands that would reveal the status of my 
database and its tables to make sure something is not messed up?


Any suggestions on resolving this problem would be greatly appreciated.

---
Rhino



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Re: Error from mysqldump

2006-01-19 Thread gerald_clark

Rhino wrote:

I have an automated backup script that has been running daily for a 
couple of years now. It has never given me trouble until the last two 
days. For the last two days, I have been getting this message when 
backing up my newest database:


/usr/bin/mysqldump: Got error: 1064: You have an error in your SQL 
syntax. Check the manual that corresponds to your MySQL server version 
for the right syntax to use near 'References READ /*!32311 LOCAL */' 
at line 1 when using LOCK TABLES


This is the relevant portion of my backup script:

for ONE_DBNAME in `echo show databases | mysql -s -u $USERID -p$PASSWORD`
do
  echo
  echo Backing up database $ONE_DBNAME;
  /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME} -r 
${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql


I would look here. This is a dangerous expansion. A space or ';' in any 
of these variables my generate unwanted commands.

Use quotes around the argument to -r.
Try.
 /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME} -r ${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql


or 
/usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME}   ${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql



  echo  Deleting these old backups for this database...
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -print; 
#display old backups (if any)
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -exec rm '{}' 
';' #delete old backups (if any)

done


I'm at a loss to see why I'm getting this error for only one database 
when the exact same logic is applied for each of my databases and 
works fine for all the others.


I've tried doing the backup manually from the command line and found 
that I got the same error when I tried to backup the Maximal database 
that way; a manual backup of another database worked fine.


The only idea I have that seems vaguely plausible is that there is 
something internally wrong with my database but I'm darned if I know 
what the problem could be. When I do 'select *' against each of the 
five small tables in this database, each returns exactly the right 
data and there are no errors or warnings of any kind.


Can anyone suggest queries or commands that would reveal the status of 
my database and its tables to make sure something is not messed up?


Any suggestions on resolving this problem would be greatly appreciated.

---
Rhino






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Group By over many colums

2006-01-19 Thread Critters
Hi
I have a table setup like this:

id, name1, name2, name3

Which has data like this:

1, Dave, Bob, Simon
2, Joe, Tim, Dave
3, Dave, Bob, Tom

I can run 

SELECT name, count(id) FROM tablename GROUP BY name1 ORDER BY count(id) DESC

Which would give me:

Dave, 2
Joe, 1

But how would I go about getting the following result:

Dave, 3
Bob, 2
Tom, 2
Joe, 1
Simon, 1

Where it groups by name1, name2 and name3? Is it possible?
-
David Scott

RE: Group By over many colums

2006-01-19 Thread Patrick Herber
I would suggest a union

SELECT name, count(*) 
FROM (SELECT name1 as name from mytable union select name2 as name from
mytable union select name3 as name from table) 
GROUP BY name

but perhaps there's a better way...

Regards,
Patrick


 -Original Message-
 From: Critters [mailto:[EMAIL PROTECTED] 
 Sent: Thursday, 19 January 2006 16:17
 To: mysql@lists.mysql.com
 Subject: Group By over many colums
 
 Hi
 I have a table setup like this:
 
 id, name1, name2, name3
 
 Which has data like this:
 
 1, Dave, Bob, Simon
 2, Joe, Tim, Dave
 3, Dave, Bob, Tom
 
 I can run 
 
 SELECT name, count(id) FROM tablename GROUP BY name1 ORDER 
 BY count(id) DESC
 
 Which would give me:
 
 Dave, 2
 Joe, 1
 
 But how would I go about getting the following result:
 
 Dave, 3
 Bob, 2
 Tom, 2
 Joe, 1
 Simon, 1
 
 Where it groups by name1, name2 and name3? Is it possible?
 -
 David Scott


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Re: Group By over many colums

2006-01-19 Thread Marco Neves
Hi,

To this on I just see a solution, that depends on sub-selects, so it's 
available from Mysql 4.1 forward:

SELECT name,count(*) from ((SELECT name1 name FROM tablename) UNION ALL 
(SELECT name2 name FROM tablename) UNION ALL (SELECT name3 name FROM 
tablename)) tab GROUP by name;

Hope this solves you problem.

mpneves

On Thursday 19 January 2006 15:16, Critters wrote:
 Hi
 I have a table setup like this:

 id, name1, name2, name3

 Which has data like this:

 1, Dave, Bob, Simon
 2, Joe, Tim, Dave
 3, Dave, Bob, Tom

 I can run

 SELECT name, count(id) FROM tablename GROUP BY name1 ORDER BY count(id)
 DESC

 Which would give me:

 Dave, 2
 Joe, 1

 But how would I go about getting the following result:

 Dave, 3
 Bob, 2
 Tom, 2
 Joe, 1
 Simon, 1

 Where it groups by name1, name2 and name3? Is it possible?
 -
 David Scott

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Re: Error from mysqldump

2006-01-19 Thread Rhino


- Original Message - 
From: gerald_clark [EMAIL PROTECTED]

To: Rhino [EMAIL PROTECTED]
Cc: mysql mysql@lists.mysql.com
Sent: Thursday, January 19, 2006 9:30 AM
Subject: Re: Error from mysqldump



Rhino wrote:

I have an automated backup script that has been running daily for a 
couple of years now. It has never given me trouble until the last two 
days. For the last two days, I have been getting this message when 
backing up my newest database:


/usr/bin/mysqldump: Got error: 1064: You have an error in your SQL 
syntax. Check the manual that corresponds to your MySQL server version 
for the right syntax to use near 'References READ /*!32311 LOCAL */' at 
line 1 when using LOCK TABLES


This is the relevant portion of my backup script:

for ONE_DBNAME in `echo show databases | mysql -s -u $USERID -p$PASSWORD`
do
  echo
  echo Backing up database $ONE_DBNAME;
  /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME} -r 
${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql


I would look here. This is a dangerous expansion. A space or ';' in any of 
these variables my generate unwanted commands.

Use quotes around the argument to -r.
Try.
 /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME} -r ${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql


or /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME}   ${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql




Okay, fair enough, I've never claimed to be a bash expert ;-) I think your 
proposed change is an improvement: it is clearer and easier to read. I'll 
give this version a try for the next few days and see if it works any 
better.


But I'm still not sure why this version might solve my problem. Wouldn't an 
expansion issue cause problems for all of my databases, not just one? I'm 
trying to understand why only one database is affected and why only the 
newest one when the script has worked fine for many months with the older 
databases.



  echo  Deleting these old backups for this database...
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -print; #display 
old backups (if any)
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -exec rm '{}' ';' 
#delete old backups (if any)

done


I'm at a loss to see why I'm getting this error for only one database 
when the exact same logic is applied for each of my databases and works 
fine for all the others.


I've tried doing the backup manually from the command line and found that 
I got the same error when I tried to backup the Maximal database that 
way; a manual backup of another database worked fine.


The only idea I have that seems vaguely plausible is that there is 
something internally wrong with my database but I'm darned if I know what 
the problem could be. When I do 'select *' against each of the five small 
tables in this database, each returns exactly the right data and there 
are no errors or warnings of any kind.


Can anyone suggest queries or commands that would reveal the status of my 
database and its tables to make sure something is not messed up?


Any suggestions on resolving this problem would be greatly appreciated.

---
Rhino 




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RE: Regarding the date values loading into the tables from a text file

2006-01-19 Thread lakshmi.narasimharao

Hi,

 From the front end I need to use double slashes i.e  (\\) to enter
one slash (\) into the MySQL database. I.e, if I enter Gelb\Paha, it
stores in the mySQL as GlebPaha,
If I enter S\\Greeen, it stores as S\Green in the database.

Is there any way in MySQL so that I can enter any number of slases
between the name with out escaping with another slash?.

If I retrive the same value with the slash (\), not able to display
properly in the GUI.
Do we need to use any MySQL specific functions to select such values?.

Please guide me for a solution here. Thanking you in advance.

Thanks,
Narasimha

   





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Re: Group By over many colums

2006-01-19 Thread Critters

The actual table is called sends and the data is like this:

| id  | f1 | f2 | f3 
|

|   3 |  foo.com  | yahoo.com|  |
|   4 |  dsl.pipex.com |  foo.com| foo.com|
|   5 |  vodafone.com| btinternet.com| co-op.co.uk  |

I tired:

SELECT domain, count(*)
FROM (
(SELECT f1 as domain from sends) union all
(SELECT f2 as domain from sends) union all
(SELECT f3 as domain from sends)
)
GROUP BY domain

But I get:

[localhost] ERROR 1064: You have an error in your SQL syntax.  Check the 
manual that corresponds to your MySQL
server version for the right syntax to use near 'SELECT f1 as domain from 
sends) union all (SELECT f2 as domain


Can you spot where I am going wrong?
-
David Scott


- Original Message - 
From: Marco Neves [EMAIL PROTECTED]

To: mysql@lists.mysql.com
Cc: Critters [EMAIL PROTECTED]
Sent: Thursday, January 19, 2006 3:34 PM
Subject: Re: Group By over many colums


Hi,

To this on I just see a solution, that depends on sub-selects, so it's
available from Mysql 4.1 forward:

SELECT name,count(*) from ((SELECT name1 name FROM tablename) UNION ALL
(SELECT name2 name FROM tablename) UNION ALL (SELECT name3 name FROM
tablename)) tab GROUP by name;

Hope this solves you problem.

mpneves

On Thursday 19 January 2006 15:16, Critters wrote:

Hi
I have a table setup like this:

id, name1, name2, name3

Which has data like this:

1, Dave, Bob, Simon
2, Joe, Tim, Dave
3, Dave, Bob, Tom

I can run

SELECT name, count(id) FROM tablename GROUP BY name1 ORDER BY count(id)
DESC

Which would give me:

Dave, 2
Joe, 1

But how would I go about getting the following result:

Dave, 3
Bob, 2
Tom, 2
Joe, 1
Simon, 1

Where it groups by name1, name2 and name3? Is it possible?
-
David Scott


--
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Especialistas em OpenSource
http://www.avidmind.net
OBC2BIP

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For list archives: http://lists.mysql.com/mysql
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Re: Group By over many colums

2006-01-19 Thread Marco Neves
Hi,

Before anything else I would verify that your mysql-server is 4.1 or 
superior, as before that MySQL didn't suported sub-selects.

It looks to me that the error should be that.

After that I only spot the missing table alias before the Group by.

mpneves

On Thursday 19 January 2006 16:01, Critters wrote:
 The actual table is called sends and the data is like this:
 | id  | f1 | f2 | f3
 |
 |   3 |  foo.com  | yahoo.com|  |
 |   4 |  dsl.pipex.com |  foo.com| foo.com|
 |   5 |  vodafone.com| btinternet.com| co-op.co.uk  |

 I tired:

 SELECT domain, count(*)
 FROM (
 (SELECT f1 as domain from sends) union all
 (SELECT f2 as domain from sends) union all
 (SELECT f3 as domain from sends)
 )
 GROUP BY domain

 But I get:

 [localhost] ERROR 1064: You have an error in your SQL syntax.  Check the
 manual that corresponds to your MySQL
 server version for the right syntax to use near 'SELECT f1 as domain from
 sends) union all (SELECT f2 as domain

 Can you spot where I am going wrong?
 -
 David Scott


 - Original Message -
 From: Marco Neves [EMAIL PROTECTED]
 To: mysql@lists.mysql.com
 Cc: Critters [EMAIL PROTECTED]
 Sent: Thursday, January 19, 2006 3:34 PM
 Subject: Re: Group By over many colums


 Hi,

 To this on I just see a solution, that depends on sub-selects, so it's
 available from Mysql 4.1 forward:

 SELECT name,count(*) from ((SELECT name1 name FROM tablename) UNION ALL
 (SELECT name2 name FROM tablename) UNION ALL (SELECT name3 name FROM
 tablename)) tab GROUP by name;

 Hope this solves you problem.

 mpneves

 On Thursday 19 January 2006 15:16, Critters wrote:
  Hi
  I have a table setup like this:
 
  id, name1, name2, name3
 
  Which has data like this:
 
  1, Dave, Bob, Simon
  2, Joe, Tim, Dave
  3, Dave, Bob, Tom
 
  I can run
 
  SELECT name, count(id) FROM tablename GROUP BY name1 ORDER BY count(id)
  DESC
 
  Which would give me:
 
  Dave, 2
  Joe, 1
 
  But how would I go about getting the following result:
 
  Dave, 3
  Bob, 2
  Tom, 2
  Joe, 1
  Simon, 1
 
  Where it groups by name1, name2 and name3? Is it possible?
  -
  David Scott

 --
 AvidMind, Consultadoria Informática, Unipessoal, Lda.
 Especialistas em OpenSource
 http://www.avidmind.net
 OBC2BIP

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Re: INSERT encrypted data

2006-01-19 Thread sharif islam
On 1/19/06, Gleb Paharenko [EMAIL PROTECTED] wrote:
 Hello.

 What doesn't work? In case you want more help please, provide the
 results you want obtain from your query and CREATE statement for you table.

Sorry for not being clear. The data is getting saved as NULL instead
of being encrypted.



 sharif islam wrote:
  mysql insert into ccard values(AES_ENCRYPT(123453535,'uiwuerw'),'10/2003');
  Query OK, 1 row affected (0.00 sec)
 
  mysql select * from ccard
  - ;
  +--+-+
  | crypt| expire  |
  +--+-+
  | )\u\u\u\u\u\u\u  | 10/2003 |
  | )\u\u\u\u\u\u\u  | 10/2003 |
  | )\u\u\u\u\u\u\u  | 10/2003 |
  | )\u\u\u\u\u\u\u  | 10/2003 |
  +--+-+
  4 rows in set (0.00 sec)
 
  why doesn't this work?


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Re: Group By over many colums

2006-01-19 Thread Critters

Thanks for the replies Marco...
mysql  Ver 12.22 Distrib 4.0.21

So that could be it?

By the way...

(SELECT f1 as 'domain' from sends) union
(SELECT f2 as 'domain' from sends) union
(SELECT f3 as 'domain' from sends) union
(SELECT f4 as 'domain' from sends)

Works, and returns a list where f1, f2, f3 and f4 are all in the column 
domain


But as soon as I add GROUP BY domain to the end it fails. I have also 
tried GROUP BY 'domain'

--
David Scott

- Original Message - 
From: Marco Neves [EMAIL PROTECTED]

To: mysql@lists.mysql.com
Cc: Critters [EMAIL PROTECTED]
Sent: Thursday, January 19, 2006 3:34 PM
Subject: Re: Group By over many colums


Hi,

To this on I just see a solution, that depends on sub-selects, so it's
available from Mysql 4.1 forward:

SELECT name,count(*) from ((SELECT name1 name FROM tablename) UNION ALL
(SELECT name2 name FROM tablename) UNION ALL (SELECT name3 name FROM
tablename)) tab GROUP by name;

Hope this solves you problem.

mpneves

On Thursday 19 January 2006 15:16, Critters wrote:

Hi
I have a table setup like this:

id, name1, name2, name3

Which has data like this:

1, Dave, Bob, Simon
2, Joe, Tim, Dave
3, Dave, Bob, Tom

I can run

SELECT name, count(id) FROM tablename GROUP BY name1 ORDER BY count(id)
DESC

Which would give me:

Dave, 2
Joe, 1

But how would I go about getting the following result:

Dave, 3
Bob, 2
Tom, 2
Joe, 1
Simon, 1

Where it groups by name1, name2 and name3? Is it possible?
-
David Scott


--
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Especialistas em OpenSource
http://www.avidmind.net
OBC2BIP

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Re: Error from mysqldump

2006-01-19 Thread Rhino
Just as a followup to my own remarks, I've tried running my backup script 
with the new syntax that Gerald suggested. I was going to wait for the 
normal daily backup but I was eager to see if the new version would work 
better so I just ran it from the command line.


Unfortunately, it came back with the same error. The new syntax is still 
cleaner and I'm going to keep it but I'm back to square one in determining 
why the mysqldump of this one database is giving me trouble.


Does anyone have any ideas?

Rhino

- Original Message - 
From: Rhino [EMAIL PROTECTED]

To: gerald_clark [EMAIL PROTECTED]
Cc: mysql mysql@lists.mysql.com
Sent: Thursday, January 19, 2006 10:53 AM
Subject: Re: Error from mysqldump




- Original Message - 
From: gerald_clark [EMAIL PROTECTED]

To: Rhino [EMAIL PROTECTED]
Cc: mysql mysql@lists.mysql.com
Sent: Thursday, January 19, 2006 9:30 AM
Subject: Re: Error from mysqldump



Rhino wrote:

I have an automated backup script that has been running daily for a 
couple of years now. It has never given me trouble until the last two 
days. For the last two days, I have been getting this message when 
backing up my newest database:


/usr/bin/mysqldump: Got error: 1064: You have an error in your SQL 
syntax. Check the manual that corresponds to your MySQL server version 
for the right syntax to use near 'References READ /*!32311 LOCAL */' at 
line 1 when using LOCK TABLES


This is the relevant portion of my backup script:

for ONE_DBNAME in `echo show databases | mysql -s -u 
$USERID -p$PASSWORD`

do
  echo
  echo Backing up database $ONE_DBNAME;
  /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME} -r 
${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql


I would look here. This is a dangerous expansion. A space or ';' in any 
of these variables my generate unwanted commands.

Use quotes around the argument to -r.
Try.
 /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME} -r ${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql


or /usr/bin/mysqldump --opt --verbose -u${USERID} -p${PASSWORD} 
${ONE_DBNAME}   ${BACKUP_PATH}/${ONE_DBNAME}.${BACKUP_TIMESTAMP}.sql




Okay, fair enough, I've never claimed to be a bash expert ;-) I think your 
proposed change is an improvement: it is clearer and easier to read. I'll 
give this version a try for the next few days and see if it works any 
better.


But I'm still not sure why this version might solve my problem. Wouldn't 
an expansion issue cause problems for all of my databases, not just one? 
I'm trying to understand why only one database is affected and why only 
the newest one when the script has worked fine for many months with the 
older databases.



  echo  Deleting these old backups for this database...
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -print; #display 
old backups (if any)
  /usr/bin/find ${BACKUP_PATH} -mtime 
+$NUMBER_OF_DAILY_BACKUPS_TO_KEEP -name $ONE_DBNAME'*' -exec rm '{}' ';' 
#delete old backups (if any)

done


I'm at a loss to see why I'm getting this error for only one database 
when the exact same logic is applied for each of my databases and works 
fine for all the others.


I've tried doing the backup manually from the command line and found 
that I got the same error when I tried to backup the Maximal database 
that way; a manual backup of another database worked fine.


The only idea I have that seems vaguely plausible is that there is 
something internally wrong with my database but I'm darned if I know 
what the problem could be. When I do 'select *' against each of the five 
small tables in this database, each returns exactly the right data and 
there are no errors or warnings of any kind.


Can anyone suggest queries or commands that would reveal the status of 
my database and its tables to make sure something is not messed up?


Any suggestions on resolving this problem would be greatly appreciated.

---

Rhino


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Version: 7.1.375 / Virus Database: 267.14.20/234 - Release Date: 
18/01/2006







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Re: Group By over many colums

2006-01-19 Thread Marco Neves
Hi Critters,

The problem is that as your MySQL is 4.0.21 don't suport the subselect 
you 
would need to do the group.

I was thinking and you have another alternative:

CREATE TEMPORARY table tdata
(SELECT f1 as 'domain' from sends) union all
(SELECT f2 as 'domain' from sends) union all
(SELECT f3 as 'domain' from sends) union all
(SELECT f4 as 'domain' from sends);

-- This would create an temporary table with all the data

SELECT domain,count(*) from tdata GROUP by domain;

-- This sould do the trick.

mpneves

On Thursday 19 January 2006 16:14, Critters wrote:
 Thanks for the replies Marco...
 mysql  Ver 12.22 Distrib 4.0.21

 So that could be it?

 By the way...

 (SELECT f1 as 'domain' from sends) union
 (SELECT f2 as 'domain' from sends) union
 (SELECT f3 as 'domain' from sends) union
 (SELECT f4 as 'domain' from sends)

 Works, and returns a list where f1, f2, f3 and f4 are all in the column
 domain

 But as soon as I add GROUP BY domain to the end it fails. I have also
 tried GROUP BY 'domain'
 --
 David Scott
-- 
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Especialistas em OpenSource
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Show Description options??

2006-01-19 Thread Mike OK
Hi

I was looking for a command that will list the names of my columns only.
I have investigated show columns but there seems to be no way to return just
the names.  Any suggestions??  Thanks Mike


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Re: Group By over many colums

2006-01-19 Thread Critters

Thanks!
I wrote:


DELETE FROM t_sends;

CREATE TEMPORARY table IF NOT EXISTS t_sends
(SELECT f1 as 'domain' from sends WHERE gameID = 1) union all
(SELECT f2 as 'domain' from sends WHERE gameID = 1) union all
(SELECT f3 as 'domain' from sends WHERE gameID = 1) union all
(SELECT f4 as 'domain' from sends WHERE gameID = 1) ;

SELECT MID(domain,INSTR(domain,'@')+1) AS 'domain' , count(*) from t_sends 
GROUP by 'domain'



And that does the trick

Is there any way to destroy the t_sends table?
--
Dave


- Original Message - 
From: Marco Neves [EMAIL PROTECTED]

To: Critters [EMAIL PROTECTED]
Cc: mysql@lists.mysql.com
Sent: Thursday, January 19, 2006 4:20 PM
Subject: Re: Group By over many colums


Hi Critters,

The problem is that as your MySQL is 4.0.21 don't suport the subselect you
would need to do the group.

I was thinking and you have another alternative:

CREATE TEMPORARY table tdata
(SELECT f1 as 'domain' from sends) union all
(SELECT f2 as 'domain' from sends) union all
(SELECT f3 as 'domain' from sends) union all
(SELECT f4 as 'domain' from sends);

-- This would create an temporary table with all the data

SELECT domain,count(*) from tdata GROUP by domain;

-- This sould do the trick.

mpneves

On Thursday 19 January 2006 16:14, Critters wrote:

Thanks for the replies Marco...
mysql  Ver 12.22 Distrib 4.0.21

So that could be it?

By the way...

(SELECT f1 as 'domain' from sends) union
(SELECT f2 as 'domain' from sends) union
(SELECT f3 as 'domain' from sends) union
(SELECT f4 as 'domain' from sends)

Works, and returns a list where f1, f2, f3 and f4 are all in the column
domain

But as soon as I add GROUP BY domain to the end it fails. I have also
tried GROUP BY 'domain'
--
David Scott

--
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Re: Group By over many colums

2006-01-19 Thread Marco Neves
Hi,

If it didn't existed and was created with the create temporary table it will 
desapear when you close your corrent session.

otherwise you can drop it with

DROP TABLE t_sends;

mpneves

On Thursday 19 January 2006 16:35, Critters wrote:
 Thanks!
 I wrote:


 DELETE FROM t_sends;

 CREATE TEMPORARY table IF NOT EXISTS t_sends
 (SELECT f1 as 'domain' from sends WHERE gameID = 1) union all
 (SELECT f2 as 'domain' from sends WHERE gameID = 1) union all
 (SELECT f3 as 'domain' from sends WHERE gameID = 1) union all
 (SELECT f4 as 'domain' from sends WHERE gameID = 1) ;

 SELECT MID(domain,INSTR(domain,'@')+1) AS 'domain' , count(*) from t_sends
 GROUP by 'domain'


 And that does the trick

 Is there any way to destroy the t_sends table?
 --
 Dave


 - Original Message -
 From: Marco Neves [EMAIL PROTECTED]
 To: Critters [EMAIL PROTECTED]
 Cc: mysql@lists.mysql.com
 Sent: Thursday, January 19, 2006 4:20 PM
 Subject: Re: Group By over many colums


 Hi Critters,

 The problem is that as your MySQL is 4.0.21 don't suport the subselect you
 would need to do the group.

 I was thinking and you have another alternative:

 CREATE TEMPORARY table tdata
 (SELECT f1 as 'domain' from sends) union all
 (SELECT f2 as 'domain' from sends) union all
 (SELECT f3 as 'domain' from sends) union all
 (SELECT f4 as 'domain' from sends);

 -- This would create an temporary table with all the data

 SELECT domain,count(*) from tdata GROUP by domain;

 -- This sould do the trick.

 mpneves

 On Thursday 19 January 2006 16:14, Critters wrote:
  Thanks for the replies Marco...
  mysql  Ver 12.22 Distrib 4.0.21
 
  So that could be it?
 
  By the way...
 
  (SELECT f1 as 'domain' from sends) union
  (SELECT f2 as 'domain' from sends) union
  (SELECT f3 as 'domain' from sends) union
  (SELECT f4 as 'domain' from sends)
 
  Works, and returns a list where f1, f2, f3 and f4 are all in the column
  domain
 
  But as soon as I add GROUP BY domain to the end it fails. I have also
  tried GROUP BY 'domain'
  --
  David Scott

 --
 AvidMind, Consultadoria Informática, Unipessoal, Lda.
 Especialistas em OpenSource
 http://www.avidmind.net
 OBC2BIP

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RE: Show Description options??

2006-01-19 Thread ISC Edwin Cruz
If you are using mysql 5.x you must be able to retrieve that you want using
information_schema database
Look:

mysql select version();
+-+
| version()   |
+-+
| 5.0.16-standard |
+-+
1 row in set (0.00 sec)

mysql use information_schema;
Database changed
mysql SELECT column_name,data_type FROM COLUMNS C where table_schema =
'erp' and table_name='TAnticipo';
+-+---+
| column_name | data_type |
+-+---+
| idTAnticipo | int   |
| TEmpleado_idTEmpleado   | int   |
| TViaje_idTViaje | int   |
| TTipoGasto_idTTipoGasto | int   |
| no_vale | char  |
| fecha   | date  |
| tipo| char  |
| cantidad| tinyint   |
| importe | double|
| iva | double|
| observacion | char  |
| activo  | char  |
+-+---+
12 rows in set (0.01 sec)

mysql


Regards!

++
| ISC Edwin Cruz [EMAIL PROTECTED]|
| Desk:  52 (449) 910 30 90 x3054|
| MX Mobile: 52 (449) 111 29 03  |
| Skype: e-cruz  |
++



-Mensaje original-
De: Mike OK [mailto:[EMAIL PROTECTED] 
Enviado el: Jueves, 19 de Enero de 2006 10:34 a.m.
Para: mysql@lists.mysql.com
Asunto: Show Description options??


Hi

I was looking for a command that will list the names of my columns only.
I have investigated show columns but there seems to be no way to return just
the names.  Any suggestions??  Thanks Mike


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Best Configuratuion ( my.cnf ) for a DB with many users and large columns ( Images in BLOB Columns ) on a Website]

2006-01-19 Thread ESV Media GmbH

Hey,

what do you think is the best configuration ( my.cnf ) for running a 
database,

which many users access at the same time ( Website - Portal ).
We´ve also saved our Pictures ( nearly 3.500 rows ) in our database.
Every coloumn is round about 60-70 Kbyte, so i had to use mediumblob 
columns.
There are 116 Tables and we have a primary key and an index on every 
table and use them

in ( i hope so ;-)  ) every statement.
Here i´ve a my.cnf from another website.
Would that be an good configuration ?
Thanks in advance

Marco

My.cnf :

# The MySQL server
[mysqld]
port= 3307
socket  = /tmp/mysql.sock
skip-locking
key_buffer_size = 256M
max_allowed_packet = 1M
table_cache = 500
sort_buffer_size = 24M
net_buffer_length = 8K
read_buffer_size = 1M
read_rnd_buffer_size = 256K
myisam_sort_buffer_size = 24M
record_buffer=1M
log-slow-queries
long_query_time = 3
query_cache_size = 512M
max_connections = 500
join_buffer_size = 16M

[mysqldump]
quick
max_allowed_packet = 16M

[mysql]
no-auto-rehash
# Remove the next comment character if you are not familiar with SQL
#safe-updates

[isamchk]
key_buffer = 25M
sort_buffer_size = 25M
read_buffer = 6M
write_buffer = 6M

[myisamchk]
key_buffer = 25M
sort_buffer_size = 25M
read_buffer = 6M
write_buffer = 6M

[mysqlhotcopy]
interactive-timeout




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Select records added in last hour

2006-01-19 Thread Russell Horn
I have a table containing a timestamp field, `insert_time`

The manual is clear when it comes to selecting records from the past
week or month, I can use:

  SELECT COUNT(*) FROM statistics 
  WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) = `insert_time`;

What I am less sure about is how I would select records that had been
inserted to thee table in the previous hour.

I understand the date functions will ignore the hh:mm:ss - will the time
functions ignore the date? Can anyone suggest what function I need for
this select?

Thanks,

Russell.



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Re: Select records added in last hour

2006-01-19 Thread gerald_clark

Russell Horn wrote:


I have a table containing a timestamp field, `insert_time`

The manual is clear when it comes to selecting records from the past
week or month, I can use:

 SELECT COUNT(*) FROM statistics 
 WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) = `insert_time`;


What I am less sure about is how I would select records that had been
inserted to thee table in the previous hour.

I understand the date functions will ignore the hh:mm:ss - will the time
functions ignore the date? Can anyone suggest what function I need for
this select?

 


Have you tried any of the functions in the manual?

select NOW();
select DATE_SUB(NOW(),INTERVAL 60 MINUTE);
select DATE_SUB(NOW(),INTERVAL 60 MINUTE)+0;
select DATE_SUB(NOW(),INTERVAL 1 HOUR);
select DATE_SUB(NOW(),INTERVAL 60 HOUR)+0;


Thanks,

Russell.



 




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Re: Select records added in last hour

2006-01-19 Thread Devananda

Russell Horn wrote:

I have a table containing a timestamp field, `insert_time`

The manual is clear when it comes to selecting records from the past
week or month, I can use:

  SELECT COUNT(*) FROM statistics 
  WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) = `insert_time`;


What I am less sure about is how I would select records that had been
inserted to thee table in the previous hour.

I understand the date functions will ignore the hh:mm:ss - will the time
functions ignore the date? Can anyone suggest what function I need for
this select?

Thanks,

Russell.





Rather than the CURDATE() function, just use NOW().

Ex.:

mysql select now();
+-+
| now()   |
+-+
| 2006-01-19 14:47:50 |
+-+
1 row in set (0.00 sec)

mysql select date_sub(now(), interval 1 hour);
+--+
| date_sub(now(), interval 1 hour) |
+--+
| 2006-01-19 13:47:53  |
+--+
1 row in set (0.00 sec)


Cheers :)


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Re: Select records added in last hour

2006-01-19 Thread Russell Horn
On Thu, 2006-01-19 at 11:49 -0800, Devananda wrote:

 
 Rather than the CURDATE() function, just use NOW().

This is perfect. Thanks.

Russell


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is UNION allowed in a MySQL stored procedure?

2006-01-19 Thread Gordon Bruce
I have a simple stored procedure which works as intended.

As soon as I add a UNION in the SELECT I get the error message 
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'select phon_Lvl INTO Lvl

Are UNION's currently not allowed in a stored procedure? 


mysql delimiter //
mysql create procedure ph()
- BEGIN
-   DECLARE LVL Char(10);
-   select phon_Lvl INTO Lvl
-   FROM   phones
-
-   limit 1;
-   SET @Lvl:=Lvl;
- END//
Query OK, 0 rows affected (0.00 sec)

mysql delimiter ;
mysql
mysql call ph();
Query OK, 0 rows affected (0.00 sec)

mysql
mysql Select @Lvl;
+--+
| @Lvl |
+--+
| locn |
+--+
1 row in set (0.00 sec)

mysql
mysql drop procedure if exists ph;
Query OK, 0 rows affected (0.01 sec)

mysql delimiter //
mysql create procedure ph()
- BEGIN
-   DECLARE LVL Char(10);
-   select phon_Lvl INTO Lvl
-   FROM   phones
-   UNION
-   Select a into LVL
-   limit 1;
-   SET @Lvl:=Lvl;
- END//
ERROR 1064 (42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near 'select phon_Lvl INTO Lvl
  FROM   phones
  UNION
  Select a into LVL
  limi' at line 4
mysql delimiter ;
mysql


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RE: Show Description options??

2006-01-19 Thread Gordon Bruce
If you are on 5.0.x you can use 

SELECT column_Name 
FROM   INFORMATION_SCHEMA.columns;


INFORMATION_SCHEMA is a set of VIEWS that lets you access the database
structure. See 

http://dev.mysql.com/doc/refman/5.0/en/information-schema.html

-Original Message-
From: Mike OK [mailto:[EMAIL PROTECTED] 
Sent: Thursday, January 19, 2006 10:34 AM
To: mysql@lists.mysql.com
Subject: Show Description options??

Hi

I was looking for a command that will list the names of my columns
only.
I have investigated show columns but there seems to be no way to return
just
the names.  Any suggestions??  Thanks Mike


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convert help

2006-01-19 Thread David Godsey

I am trying to convert binary data to a bigint so I can do bitwise
operations on the data, and I'm having trouble doing it.

I noticed that if I have binary data and I:
select data1; I get 0 (not what I'm expecting).

Here is a test procedure I wrote:

create procedure test20 ()
   BEGIN
DECLARE fdata BLOB;
  DECLARE foffset INT UNSIGNED;
  DECLARE flength INT UNSIGNED;
DECLARE tmp_int BIGINT UNSIGNED;

SELECT 0xABCDEF0123456789 INTO fdata;
SELECT 14 INTO foffset;
SELECT 7 INTO flength;

SELECT SUBSTR(BINARY(fdata),
FLOOR(foffset/8)+1,
CEIL((flength + (foffset %8 ))%8))
INTO fdata;

SELECT HEX(fdata);
SELECT CONVERT(fdata,BIGINT) INTO tmp_int;
SELECT HEX(tmp_int);
END
The last two selects are added to show what I would like to do, but have
not been able to get it to work.

Any help would be great.  Thanks in advance.

Accomplishing the impossible means only that the boss will add it to your
regular duties.

David Godsey

Accomplishing the impossible means only that the boss will add it to your
regular duties.

David Godsey


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RE: [SPAM] - convert help - Bayesian Filter detected spam

2006-01-19 Thread Gordon Bruce
I just added a user variable @fdata to get visabilility outside of the 
procedure and this is what I get.

mysql delimiter //
mysql create procedure test20 ()
-BEGIN
-   DECLARE fdata BLOB;
-   DECLARE foffset INT UNSIGNED;
-   DECLARE flength INT UNSIGNED;
- DECLARE tmp_int BIGINT UNSIGNED;
-
- SELECT 0xABCDEF0123456789 INTO fdata;
- SELECT 14 INTO foffset;
- SELECT 7 INTO flength;
-
- SELECT SUBSTR(BINARY(fdata),
- FLOOR(foffset/8)+1,
- CEIL((flength + (foffset %8 ))%8))
- INTO fdata;
-   set @fdata:=fdata;
- END//
Query OK, 0 rows affected (0.00 sec)

mysql
mysql delimiter ;
mysql
mysql call test20();
Query OK, 0 rows affected (0.00 sec)

mysql
mysql select @fdata, hex(@fdata)
-
- ;
++-+
| @fdata | hex(@fdata) |
++-+
| ═∩☺#E  | CDEF012345  |
++-+
1 row in set (0.00 sec)

-Original Message-
From: David Godsey [mailto:[EMAIL PROTECTED] 
Sent: Thursday, January 19, 2006 3:33 PM
To: mysql@lists.mysql.com
Subject: [SPAM] - convert help - Bayesian Filter detected spam


I am trying to convert binary data to a bigint so I can do bitwise
operations on the data, and I'm having trouble doing it.

I noticed that if I have binary data and I:
select data1; I get 0 (not what I'm expecting).

Here is a test procedure I wrote:

create procedure test20 ()
   BEGIN
DECLARE fdata BLOB;
  DECLARE foffset INT UNSIGNED;
  DECLARE flength INT UNSIGNED;
DECLARE tmp_int BIGINT UNSIGNED;

SELECT 0xABCDEF0123456789 INTO fdata;
SELECT 14 INTO foffset;
SELECT 7 INTO flength;

SELECT SUBSTR(BINARY(fdata),
FLOOR(foffset/8)+1,
CEIL((flength + (foffset %8 ))%8))
INTO fdata;

SELECT HEX(fdata);
SELECT CONVERT(fdata,BIGINT) INTO tmp_int;
SELECT HEX(tmp_int);
END
The last two selects are added to show what I would like to do, but have
not been able to get it to work.

Any help would be great.  Thanks in advance.

Accomplishing the impossible means only that the boss will add it to your
regular duties.

David Godsey

Accomplishing the impossible means only that the boss will add it to your
regular duties.

David Godsey


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Selecting based on serialized field...

2006-01-19 Thread Subscriptions
I'm not sure if this falls under a PHP topic or a MySQL topic, but I have a 
table that contains a field that stores serialized data.  Is there a way to 
order a recordset by a piece of the serialized data?  For example, if a 
field called data contains serialized data that looks like this:


a:11:{s:7:company;s:12:Some Company;s:8:jobtitle;s:17:Assistant 
Manager;s:5:phone;s:12:123-456-7890;s:3:fax;s:12:987-654-3210;s:7:bf_time;i:1135221050;s:8:bf_value;d:2.416246843777560382449109965818934142589569091796875E-5;s:17:signup_email_sent;i:1;s:6:status;a:2:{i:2;i:0;i:1;i:1;}s:9:is_active;i:1;s:9:is_locked;s:0:;s:11:affiliation;s:1:1;}


is there a way to select a recordset ordered by company?  Kind of like, 
but not quite:  SELECT * FROM mytable ORDER BY companyname


(where the companyname is some function that pulls out the company name)

Jenifer


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differences between varchar and text fields

2006-01-19 Thread Tucker Cunningham

hi all -
  I was looking for some clarification about the difference between 
varchar and the text types in MySQL 5.0.18.  It seems to me that varchar 
and text both hold text data, are variable length, and have the same 
storage requirements (4 + L bytes).  Also, longtext adds the ability to 
hold ~4G of data at the cost of only 2 extra storage bytes?  Also, it 
looks like text data is stored externally from the table, where varchar 
is stored within its row.


So, my question is:  what are the pros and cons of using varchar vs. 
text/longtext?  Right now, longtext seems to be the best option (it 
provides most flexibility in data that can be stored, at only a 
2-byte-per-row storage premium) There must be some drawback, what am I 
missing?  Thanks for your help


-tucker

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Re: Selecting based on serialized field...

2006-01-19 Thread Peter Brawley




is there a way to select a recordset ordered by "company"? Kind
of like, 
but not quite: SELECT * FROM mytable ORDER BY companyname


(where the "companyname" is some function that pulls out the
company name)



Yes you can ORDER BY a function result.

PB

-

Subscriptions wrote:
I'm
not sure if this falls under a PHP topic or a MySQL topic, but I have a
table that contains a field that stores serialized data. Is there a
way to order a recordset by a piece of the serialized data? For
example, if a field called "data" contains serialized data that looks
like this:
  
  
a:11:{s:7:"company";s:12:"Some Company";s:8:"jobtitle";s:17:"Assistant
Manager";s:5:"phone";s:12:"123-456-7890";s:3:"fax";s:12:"987-654-3210";s:7:"bf_time";i:1135221050;s:8:"bf_value";d:2.416246843777560382449109965818934142589569091796875E-5;s:17:"signup_email_sent";i:1;s:6:"status";a:2:{i:2;i:0;i:1;i:1;}s:9:"is_active";i:1;s:9:"is_locked";s:0:"";s:11:"affiliation";s:1:"1";}
  
  
is there a way to select a recordset ordered by "company"? Kind of
like, but not quite: SELECT * FROM mytable ORDER BY companyname
  
  
(where the "companyname" is some function that pulls out the company
name)
  
  
Jenifer
  
  
  



No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.1.375 / Virus Database: 267.14.21/235 - Release Date: 1/19/2006


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problem with using CONSTRAINT declaration

2006-01-19 Thread Ferindo Middleton Jr
I have the following table where I have a CHECK CONSTRAINT to check for 
logical data values but for some reason it's not working on INSERTs to 
the table. MySQL doesn't give any error message when I CREATE TABLE. Any 
ideas what I'm doing wrong?... or Is this type of declaration not 
supported... What command can you issue from the command line to check 
the existence of CONTRAINT declarations such as this?


CREATE TABLE schedules (
id   SERIAL NOT NULL UNIQUE,
start_date DATE NOT NULL,
end_date   DATE NOT NULL,
start_time TIME,
end_time   TIME,

CONSTRAINT end_date_cannot_be_before_start_date CHECK (end_date = 
start_date),
CONSTRAINT end_time_cannot_be_before_start_time CHECK (end_time = 
start_time),


PRIMARY KEY (class_id, start_date, end_date, start_time, end_time)
);

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Re: [SPAM] - convert help - Bayesian Filter detected spam

2006-01-19 Thread Peter Brawley




Gordon,

...
SELECT CONVERT(fdata,BIGINT) INTO tmp_int;
SELECT HEX(tmp_int);
...

Are you looking for...

SELECT CAST(0xABCDEF0123456789 AS UNSIGNED);
+--+
| CAST(0xABCDEF0123456789 AS UNSIGNED) |
+--+
| 12379813738877118345 |
+--+
SELECT HEX(12379813738877118345);
+---+
| HEX(12379813738877118345) |
+---+
| ABCDEF0123456789  |
+---+

PB

-

Gordon Bruce wrote:

  I just added a user variable @fdata to get visabilility outside of the procedure and this is what I get.

mysql delimiter //
mysql create procedure test20 ()
-BEGIN
-   DECLARE fdata BLOB;
-   DECLARE foffset INT UNSIGNED;
-   DECLARE flength INT UNSIGNED;
- DECLARE tmp_int BIGINT UNSIGNED;
-
- SELECT 0xABCDEF0123456789 INTO fdata;
- SELECT 14 INTO foffset;
- SELECT 7 INTO flength;
-
- SELECT SUBSTR(BINARY(fdata),
- FLOOR(foffset/8)+1,
- CEIL((flength + (foffset %8 ))%8))
- INTO fdata;
-   set @fdata:=fdata;
- END//
Query OK, 0 rows affected (0.00 sec)

mysql
mysql delimiter ;
mysql
mysql call test20();
Query OK, 0 rows affected (0.00 sec)

mysql
mysql select @fdata, hex(@fdata)
-
- ;
++-+
| @fdata | hex(@fdata) |
++-+
| ═∩☺#E  | CDEF012345  |
++-+
1 row in set (0.00 sec)

-Original Message-
From: David Godsey [mailto:[EMAIL PROTECTED]] 
Sent: Thursday, January 19, 2006 3:33 PM
To: mysql@lists.mysql.com
Subject: [SPAM] - convert help - Bayesian Filter detected spam


I am trying to convert binary data to a bigint so I can do bitwise
operations on the data, and I'm having trouble doing it.

I noticed that if I have binary data and I:
select data1; I get 0 (not what I'm expecting).

Here is a test procedure I wrote:

create procedure test20 ()
   BEGIN
DECLARE fdata BLOB;
  DECLARE foffset INT UNSIGNED;
  DECLARE flength INT UNSIGNED;
DECLARE tmp_int BIGINT UNSIGNED;

SELECT 0xABCDEF0123456789 INTO fdata;
SELECT 14 INTO foffset;
SELECT 7 INTO flength;

SELECT SUBSTR(BINARY(fdata),
FLOOR(foffset/8)+1,
CEIL((flength + (foffset %8 ))%8))
INTO fdata;

SELECT HEX(fdata);
SELECT CONVERT(fdata,BIGINT) INTO tmp_int;
SELECT HEX(tmp_int);
END
The last two selects are added to show what I would like to do, but have
not been able to get it to work.

Any help would be great.  Thanks in advance.

Accomplishing the impossible means only that the boss will add it to your
regular duties.

David Godsey

Accomplishing the impossible means only that the boss will add it to your
regular duties.

David Godsey


  
  

No virus found in this incoming message.
Checked by AVG Free Edition.
Version: 7.1.375 / Virus Database: 267.14.21/235 - Release Date: 1/19/2006
  



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To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]

Can MySQL jobs be posted to this list?

2006-01-19 Thread Beau Gould
Thank you,
Beau Gould

Superior Staffing Solutions
http://www.superiorss.com/jobs.htm


Ruby/Rails Jobs Yahoo Group: http://groups.yahoo.com/group/rubyrails
Human-Computer Interaction Jobs: http://groups.yahoo.com/group/HCIJobs
Python, Zope Jobs: http://groups.yahoo.com/group/pythonzopejobs
Open Source Jobs: http://groups.yahoo.com/group/opensourcejobs
LAMP Jobs: http://groups.yahoo.com/group/LAMPjobs 
Video Game Jobs: http://groups.yahoo.com/group/gamejobz 
Cold Fusion Jobs: http://groups.yahoo.com/group/coldfusionjobs
Wireless Jobs: http://groups.yahoo.com/group/wirelessjobz 

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Re: [SPAM] - convert help - Bayesian Filter detected spam

2006-01-19 Thread David Godsey
I forgot to do reply all, sorry peter for the duplicate:

Thank you for the responses to my question, however with a little poking
around after the suggestions, I still am unable to do the conversion.

mysql select 0xABCDEF0123456789 into @fdata;
Query OK, 1 row affected (0.00 sec)

mysql select hex(@fdata);
+--+
| hex(@fdata)  |
+--+
| ABCDEF0123456789 |
+--+
1 row in set (0.00 sec)

mysql select cast(@fdata AS UNSIGNED);
+--+
| cast(@fdata AS UNSIGNED) |
+--+
|0 |
+--+
1 row in set, 1 warning (0.00 sec)

mysql

Essentially what I am trying to accomplish is I have a BLOB column that
can have arbitrarily large data, and I am using SUBSTR to pull out
sections of it, and some of it needs to be masked and bit shifted.  I can
pull out the data I'm interested in, however to do the masking and bit
shifting it appears I need it to be an integer of some kind.  So I am
taking blob data and trying to convert it to an integer type (unsigned) so
I can do those bitwise operations.  So I am putting the data into a
variable like:
SELECT SUBSTR(BINARY(blob_col),offset,length)) into fdata; //example

This works fine.  I can view this data.  The problem I am having is I
can't convert it to UNSIGNED to do some further bitwise operations on the
data.

Thanks for any further help.

 Gordon,

...
SELECT CONVERT(fdata,BIGINT) INTO tmp_int;
SELECT HEX(tmp_int);
 ...

 Are you looking for...

 SELECT CAST(0xABCDEF0123456789 AS UNSIGNED);
 +--+
 | CAST(0xABCDEF0123456789 AS UNSIGNED) |
 +--+
 | 12379813738877118345 |
 +--+
 SELECT HEX(12379813738877118345);
 +---+
 | HEX(12379813738877118345) |
 +---+
 | ABCDEF0123456789  |
 +---+

 PB

 -

 Gordon Bruce wrote:
 I just added a user variable @fdata to get visabilility outside of the
 procedure and this is what I get.

 mysql delimiter //
 mysql create procedure test20 ()
 -BEGIN
 -   DECLARE fdata BLOB;
 -   DECLARE foffset INT UNSIGNED;
 -   DECLARE flength INT UNSIGNED;
 - DECLARE tmp_int BIGINT UNSIGNED;
 -
 - SELECT 0xABCDEF0123456789 INTO fdata;
 - SELECT 14 INTO foffset;
 - SELECT 7 INTO flength;
 -
 - SELECT SUBSTR(BINARY(fdata),
 - FLOOR(foffset/8)+1,
 - CEIL((flength + (foffset %8 ))%8))
 - INTO fdata;
 -   set @fdata:=fdata;
 - END//
 Query OK, 0 rows affected (0.00 sec)

 mysql
 mysql delimiter ;
 mysql
 mysql call test20();
 Query OK, 0 rows affected (0.00 sec)

 mysql
 mysql select @fdata, hex(@fdata)
 -
 - ;
 ++-+
 | @fdata | hex(@fdata) |
 ++-+
 | ═∩☺#E  | CDEF012345  |
 ++-+
 1 row in set (0.00 sec)

 -Original Message-
 From: David Godsey [mailto:[EMAIL PROTECTED]
 Sent: Thursday, January 19, 2006 3:33 PM
 To: mysql@lists.mysql.com
 Subject: [SPAM] - convert help - Bayesian Filter detected spam


 I am trying to convert binary data to a bigint so I can do bitwise
 operations on the data, and I'm having trouble doing it.

 I noticed that if I have binary data and I:
 select data1; I get 0 (not what I'm expecting).

 Here is a test procedure I wrote:

 create procedure test20 ()
BEGIN
 DECLARE fdata BLOB;
   DECLARE foffset INT UNSIGNED;
   DECLARE flength INT UNSIGNED;
 DECLARE tmp_int BIGINT UNSIGNED;

 SELECT 0xABCDEF0123456789 INTO fdata;
 SELECT 14 INTO foffset;
 SELECT 7 INTO flength;

 SELECT SUBSTR(BINARY(fdata),
 FLOOR(foffset/8)+1,
 CEIL((flength + (foffset %8 ))%8))
 INTO fdata;

 SELECT HEX(fdata);
 SELECT CONVERT(fdata,BIGINT) INTO tmp_int;
 SELECT HEX(tmp_int);
 END
 The last two selects are added to show what I would like to do, but have
 not been able to get it to work.

 Any help would be great.  Thanks in advance.

 Accomplishing the impossible means only that the boss will add it to
 your
 regular duties.

 David Godsey

 Accomplishing the impossible means only that the boss will add it to
 your
 regular duties.

 David Godsey



 

 No virus found in this incoming message.
 Checked by AVG Free Edition.
 Version: 7.1.375 / Virus Database: 267.14.21/235 - Release Date:
 1/19/2006

 No virus found in this outgoing message.
 Checked by AVG Free Edition.
 Version: 7.1.375 / Virus Database: 267.14.21/235 - Release Date: 1/19/2006


 --
 

Re: question about recovery with binlog

2006-01-19 Thread wangxu
My mysql version is 5.0.16.

My problem is similar to the bug.

My sql mode is ANSI and TRADITIONAL

If mysql can't do recovery with mysqlbinlog at my sql mode  until the bug will 
be fixed?

Follow is the information of my binlog.

--
/*!40019 SET @@session.max_insert_delayed_threads=0*/;
/*!50003 SET @OLD_COMPLETION_TYPE=@@COMPLETION_TYPE,COMPLETION_TYPE=0*/;
# at 4
#060119 13:55:30 server id 1  end_log_pos 98Start: binlog v 4, server v 
5.0.16-standard-log created 060119 13:55:30
# Warning: this binlog was not closed properly. Most probably mysqld crashed 
writing it.
# at 98
#060119 13:57:41 server id 1  end_log_pos 165   Query   thread_id=4 
exec_time=0 error_code=0
use wangxu;
SET TIMESTAMP=1137650261;
SET @@session.foreign_key_checks=1, @@session.sql_auto_is_null=1, 
@@session.unique_checks=1;
SET @@session.sql_mode=501481487;
SET 
@@session.character_set_client=33,@@session.collation_connection=33,@@session.collation_server=33;
insert ht_detail 
values('79NK0006','79NK0006',1),('79NK0007','79NK0007',1),('79NK0008','79NK0008',1);
# at 263
#060119 13:57:41 server id 1  end_log_pos 290   Xid = 215
COMMIT;
# at 290
#060119 14:08:30 server id 1  end_log_pos 445   Query   thread_id=7 
exec_time=0 error_code=0
SET TIMESTAMP=1137650910;
SET @@session.foreign_key_checks=0, @@session.unique_checks=0;
SET @@session.sql_mode=524288;
CREATE DATABASE /*!32312 IF NOT EXISTS*/ `wangxu` /*!40100 DEFAULT CHARACTER 
SET latin1 */;
# at 445
#060119 14:08:30 server id 1  end_log_pos 542   Query   thread_id=7 
exec_time=0 error_code=0
SET TIMESTAMP=1137650910;
DROP TABLE IF EXISTS `ht_detail`;
# at 542
#060119 14:08:40 server id 1  end_log_pos 639   Query   thread_id=8 
exec_time=0 error_code=0
SET TIMESTAMP=1137650920;
DROP TABLE IF EXISTS `ht_detail`;
# at 639
#060119 14:23:13 server id 1  end_log_pos 733   Query   thread_id=11
exec_time=0 error_code=0
SET TIMESTAMP=1137651793;
SET @@session.foreign_key_checks=1, @@session.unique_checks=1;
SET @@session.sql_mode=501481487;
create table ht_header(a int);
# at 733
#060119 14:23:53 server id 1  end_log_pos 818   Query   thread_id=12
exec_time=0 error_code=0
SET TIMESTAMP=1137651833;
drop table ht_header;
# at 818
#060119 14:28:10 server id 1  end_log_pos 915   Query   thread_id=15
exec_time=0 error_code=0
SET TIMESTAMP=1137652090;
SET @@session.foreign_key_checks=0, @@session.unique_checks=0;
SET @@session.sql_mode=524288;
DROP TABLE IF EXISTS `ht_detail`;
# at 915
#060119 14:29:44 server id 1  end_log_pos 998   Query   thread_id=16
exec_time=0 error_code=0
use test;
SET TIMESTAMP=1137652184;
SET @@session.foreign_key_checks=1, @@session.unique_checks=1;
SET @@session.sql_mode=501481487;
drop table ht_detail;
# at 998
#060119 14:30:29 server id 1  end_log_pos 1160  Query   thread_id=16
exec_time=0 error_code=0
SET TIMESTAMP=1137652229;
create table ht_detail(hth varchar(30),sbh varchar(15),sbsl int,primary 
key(hth,sbh)) type = innodb;
# at 1160
#060119 14:54:50 server id 1  end_log_pos 1243  Query   thread_id=20
exec_time=0 error_code=0
SET TIMESTAMP=1137653690;
drop schema wangxu;
# at 1243
#060119 14:54:57 server id 1  end_log_pos 1328  Query   thread_id=20
exec_time=0 error_code=0
SET TIMESTAMP=1137653697;
create schema wangxu;
# at 1328
#060119 14:55:17 server id 1  end_log_pos 1422  Query   thread_id=20
exec_time=0 error_code=0
use wangxu;
SET TIMESTAMP=1137653717;
create table ht_detail(a int);
# at 1422
#060119 17:10:13 server id 1  end_log_pos 1505  Query   thread_id=24
exec_time=0 error_code=0
SET TIMESTAMP=1137661813;
drop schema wangxu;
# at 1505
#060119 17:10:17 server id 1  end_log_pos 1590  Query   thread_id=24
exec_time=0 error_code=0
SET TIMESTAMP=1137661817;
create schema wangxu;
# at 1590
#060119 17:10:47 server id 1  end_log_pos 1687  Query   thread_id=25
exec_time=0 error_code=0
SET TIMESTAMP=1137661847;
SET @@session.foreign_key_checks=0, @@session.unique_checks=0;
SET @@session.sql_mode=524288;
DROP TABLE IF EXISTS `ht_detail`;
# at 1687
#060119 17:10:47 server id 1  end_log_pos 1959  Query   thread_id=25
exec_time=0 error_code=0
SET TIMESTAMP=1137661847;
CREATE TABLE `ht_detail` (
  `hth` varchar(30) NOT NULL default '',
  `sbh` varchar(15) NOT NULL default '',
  `sbsl` int(11) default NULL,
  PRIMARY KEY  (`hth`,`sbh`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
# at 1959
#060119 17:10:47 server id 1  end_log_pos 2072  Query   thread_id=25
exec_time=0 error_code=0
SET TIMESTAMP=1137661847;
/*!4 ALTER TABLE `ht_detail` DISABLE KEYS */;
# at 2072
#060119 17:10:47 server id 1  end_log_pos 188   Query   thread_id=25
exec_time=0 error_code=0
SET TIMESTAMP=1137661847;
INSERT INTO `ht_detail` VALUES 
('79NK0001/0003','79NK0001',1),('79NK0001/0003','79NK0002',1),('79NK0001/0003','79NK0003',1);
# at 2260
#060119 17:10:47 server id 

Re: question about CONTAINS SQL

2006-01-19 Thread wangxu
Thank you Rhino.

Your description is very detailed.

But my try was fail.No error has been throw out.

Follow is the process.

Please help me to analyse the result.

--
[EMAIL PROTECTED] bin]# mysql -uroot
Welcome to the MySQL monitor.  Commands end with ; or \g.
Your MySQL connection id is 2 to server version: 5.0.16-standard-log

Type 'help;' or '\h' for help. Type '\c' to clear the buffer.

mysql show databases;
++
| Database   |
++
| information_schema |
| db1|
| db2|
| mysql  |
| test   |
| wangxu |
++
6 rows in set (0.03 sec)

mysql use wangxu;
Reading table information for completion of table and column names
You can turn off this feature to get a quicker startup with -A

Database changed
mysql show tables;
+--+
| Tables_in_wangxu |
+--+
| ht_detail|
+--+
1 row in set (0.00 sec)

mysql select * from ht_detail;
+---+--+--+
| hth   | sbh  | sbsl |
+---+--+--+
| 79NK0001/0003 | 79NK0001 |1 |
| 79NK0001/0003 | 79NK0002 |1 |
| 79NK0001/0003 | 79NK0003 |1 |
+---+--+--+
3 rows in set (0.01 sec)

mysql delimiter //
mysql create procedure test()
- deterministic
- contains sql
- begin
-   insert ht_detail values('sdf','ser',4);
- end
- //
Query OK, 0 rows affected (0.02 sec)

mysql delimiter ;

mysql show create procedure test \G
*** 1. row ***
   Procedure: test
sql_mode: 
REAL_AS_FLOAT,PIPES_AS_CONCAT,ANSI_QUOTES,IGNORE_SPACE,ANSI,STRICT_TRANS_TABLES,STRICT_ALL_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,TRADITIONAL,NO_AUTO_CREATE_USER
Create Procedure: CREATE PROCEDURE test()
DETERMINISTIC
begin
  insert ht_detail values('sdf','ser',4);
end
1 row in set (0.00 sec)


mysql call test();
Query OK, 1 row affected (0.00 sec)

mysql select * from ht_detail;
+---+--+--+
| hth   | sbh  | sbsl |
+---+--+--+
| 79NK0001/0003 | 79NK0001 |1 |
| 79NK0001/0003 | 79NK0002 |1 |
| 79NK0001/0003 | 79NK0003 |1 |
| sdf   | ser  |4 |
+---+--+--+
4 rows in set (0.00 sec)

mysql 
--


- Original Message - 
From: Rhino [EMAIL PROTECTED]
To: wangxu [EMAIL PROTECTED]
Cc: mysql mysql@lists.mysql.com
Sent: Thursday, January 19, 2006 9:29 PM
Subject:Re: question about CONTAINS SQL


 I am copying the rest of the list with this so that everyone may benefit 
 from the discussion.
 
 If your routine modifies data, in other words if it does SQL Update, Insert 
 or Delete but your routine definition says only CONTAINS SQL, I would 
 expect your routine to fail at runtime. I can't say this with certaintly 
 because I don't have one of the newer versions of MySQL that supports these 
 routines but I'm pretty sure that you will have a runtime failure. After 
 all, CONTAINS SQL implies only that you are creating objects like tables 
 within your routine; CONTAINS SQL does not permit the execution of Insert, 
 Update, or Delete. Therefore, I expect that you will get a runtime error as 
 soon as you do your first Insert, Update, or Delete. If you want to avoid 
 the error, use MODIFIES SQL instead of CONTAINS SQL.
 
 Of course the best way to be sure is to try this for yourself. Try the 
 routine with CONTAINS SQL and see what happens at runtime. If it fails, as I 
 strongly expect, change CONTAINS SQL to MODIFIES SQL DATA and your error 
 will almost certainly go away.
 
 Rhino
 
 - Original Message - 
 From: wangxu [EMAIL PROTECTED]
 To: Rhino [EMAIL PROTECTED]
 Sent: Thursday, January 19, 2006 2:54 AM
 Subject: Re: question about CONTAINS SQL
 
 
If I create a routine with modification operation and not spectify 
  characteristic in CONTAINS SQL | NO SQL | READS SQL DATA | MODIFIES SQL 
  DATA.
In the maunal,the default value is CONTAINS SQL if i haven't spectify 
  a values.
If it's meaning that the routine with CONTAINS SQL  include 
  modification operation?
Should many problem happen?
 
 
  - Original Message - 
  From: Rhino [EMAIL PROTECTED]
  To: wangxu [EMAIL PROTECTED]; mysql@lists.mysql.com
  Sent: Thursday, January 19, 2006 12:21 AM
  Subject:Re: question about CONTAINS SQL
 
 
  If you are writing something that does INSERT, UPDATE, or DELETE, you 
  need
  to use the MODIFIES SQL DATA option.
 
  Rhino
 
  - Original Message - 
  From: wangxu [EMAIL PROTECTED]
  To: Rhino [EMAIL PROTECTED]; mysql@lists.mysql.com
  Sent: Wednesday, January 18, 2006 3:05 AM
  Subject: Re: question about CONTAINS SQL
 
 
  
  
  
   But what is  

Re: question about CONTAINS SQL

2006-01-19 Thread Paul DuBois

At 8:29 -0500 1/19/06, Rhino wrote:
I am copying the rest of the list with this so that everyone may 
benefit from the discussion.


If your routine modifies data, in other words if it does SQL Update, 
Insert or Delete but your routine definition says only CONTAINS 
SQL, I would expect your routine to fail at runtime. I can't say 
this with certaintly because I don't have one of the newer versions 
of MySQL that supports these routines but I'm pretty sure that you 
will have a runtime failure. After all, CONTAINS SQL implies only 
that you are creating objects like tables within your routine; 
CONTAINS SQL does not permit the execution of Insert, Update, or 
Delete. Therefore, I expect that you will get a runtime error as 
soon as you do your first Insert, Update, or Delete. If you want to 
avoid the error, use MODIFIES SQL instead of CONTAINS SQL.


Of course the best way to be sure is to try this for yourself. Try 
the routine with CONTAINS SQL and see what happens at runtime. If it 
fails, as I strongly expect, change CONTAINS SQL to MODIFIES SQL 
DATA and your error will almost certainly go away.


No, these characteristics are merely advisory.  The server doesn't
impose any restraints based on them.



Rhino

- Original Message - From: wangxu [EMAIL PROTECTED]
To: Rhino [EMAIL PROTECTED]
Sent: Thursday, January 19, 2006 2:54 AM
Subject: Re: question about CONTAINS SQL

  If I create a routine with modification operation and not 
spectify characteristic in CONTAINS SQL | NO SQL | READS SQL DATA | 
MODIFIES SQL DATA.
  In the maunal,the default value is CONTAINS SQL if i haven't 
spectify a values.
  If it's meaning that the routine with CONTAINS SQL  include 
modification operation?

  Should many problem happen?


- Original Message - From: Rhino [EMAIL PROTECTED]
To: wangxu [EMAIL PROTECTED]; mysql@lists.mysql.com
Sent: Thursday, January 19, 2006 12:21 AM
Subject:Re: question about CONTAINS SQL


If you are writing something that does INSERT, UPDATE, or DELETE, you need
to use the MODIFIES SQL DATA option.

Rhino

- Original Message - From: wangxu [EMAIL PROTECTED]
To: Rhino [EMAIL PROTECTED]; mysql@lists.mysql.com
Sent: Wednesday, January 18, 2006 3:05 AM
Subject: Re: question about CONTAINS SQL






 But what is  INSERT OR UPDATE need?


 - Original Message -  From: Rhino [EMAIL PROTECTED]
 To: wangxu [EMAIL PROTECTED]; mysql@lists.mysql.com
 Sent: Tuesday, January 17, 2006 9:49 PM
 Re: question about CONTAINS SQL


  - Original Message -   From: wangxu [EMAIL PROTECTED]
  To: mysql@lists.mysql.com
  Sent: Tuesday, January 17, 2006 12:35 AM
  Subject: question about CONTAINS SQL
 
 
  I notice there are one section in the manual:
  
   CONTAINS SQL indicates that the routine does not 
containstatements

   that
   read or write data.
  
   And that the option is default.
  
   It's true?
  
   If i wouldn't do read or write in routine.What can i do yet?
  
 
  Commands like GRANT or REVOKE or CREATE TABLE don't read or 
write   data
  within tables but they involve SQL so commands like this 
need   CONTAINS

  SQL,
  rather than the NO SQL, READS SQL DATA or MODIFIES SQL DATA options.
 
  Rhino
 
 
 
 
  --   No virus found in this outgoing message.
  Checked by AVG Free Edition.
  Version: 7.1.375 / Virus Database: 267.14.19/231 - Release Date:
  16/01/2006
 
 
  --   MySQL General Mailing List
  For list archives: http://lists.mysql.com/mysql
  To unsubscribe:
  http://lists.mysql.com/[EMAIL PROTECTED]
 
 






No virus found in this incoming message.
Checked by AVG Free Edition.
Version: 7.1.375 / Virus Database: 267.14.20/233 - Release Date: 18/01/2006



--
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.1.375 / Virus Database: 267.14.20/233 - Release Date: 18/01/2006


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To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]







No virus found in this incoming message.
Checked by AVG Free Edition.
Version: 7.1.375 / Virus Database: 267.14.20/233 - Release Date: 18/01/2006



--
No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.1.375 / Virus Database: 267.14.20/234 - Release Date: 18/01/2006


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To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]



--
Paul DuBois, MySQL Documentation Team
Madison, Wisconsin, USA
MySQL AB, www.mysql.com

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union/collation problem, error 1267: feature or bug?

2006-01-19 Thread schlubediwup

Hi mysqllers,

1. following installation


localhost.addresses2 show global variables like version%;
+-+--+
| Variable_name   | Value|
+-+--+
| version | 4.1.14-standard  |
| version_comment | MySQL Community Edition - Standard (GPL) |
| version_compile_machine | i686 |
| version_compile_os  | pc-linux-gnu |
+-+--+
4 rows in set (0.00 sec)

localhost.addresses2



2. following two tables are involved:

localhost.addresses2 describe contacts2;
+--+--+--+-+---++
| Field| Type | Null | Key | Default   | 
Extra  |

+--+--+--+-+---++
| name | text | YES  | | NULL  
||
| firm | text | YES  | | NULL  
||
| title| text | YES  | | NULL  
||
| phone| text | YES  | | NULL  
||
| mail | text | YES  | | NULL  
||
| comment  | text | YES  | | NULL  
||
| status   | text | YES  | | NULL  
||
| url  | text | YES  | | NULL  
||
| businesscategory | text | YES  | | NULL  
||
| address  | text | YES  | | NULL  
||
| kanton   | text | YES  | | NULL  
||
| addon| text | YES  | | NULL  
||
| givenname| text | YES  | | NULL  
||
| history  | text | YES  | | NULL  
||
| favorit  | text | YES  | | NULL  
||
| last_update  | timestamp| YES  | | CURRENT_TIMESTAMP 
||
| counter  | int(10) unsigned |  | PRI | NULL  | 
auto_increment |

+--+--+--+-+---++
17 rows in set (0.00 sec)

localhost.addresses2


localhost.addresses2 describe tasks2;
+--+--+--+-+---++
| Field| Type | Null | Key | Default   | 
Extra  |

+--+--+--+-+---++
| task_name| text | YES  | | NULL  
||
| actiony  | text | YES  | | NULL  
||
| date_start   | date | YES  | | NULL  
||
| date_end | date | YES  | | NULL  
||
| date_last_action | date | YES  | | NULL  
||
| date_next_action | date | YES  | | NULL  
||
| start_time   | time | YES  | | NULL  
||
| end_time | time | YES  | | NULL  
||
| task_address | text | YES  | | NULL  
||
| task_comment | text | YES  | | NULL  
||
| task_responsible | text | YES  | | NULL  
||
| project  | text | YES  | | NULL  
||
| task_history | text | YES  | | NULL  
||
| task_last_update | timestamp| YES  | | CURRENT_TIMESTAMP 
||
| contact_link | int(11)  | YES  | | NULL  
||
| task_counter | int(10) unsigned |  | PRI | NULL  | 
auto_increment |

+--+--+--+-+---++
16 rows in set (0.00 sec)

localhost.addresses2



3. following character-sets and collations:

localhost.addresses2 show session variables like character%;
+--++
| Variable_name| Value  |
+--++
| character_set_client | utf8