RE: trouble with perl
I can't find his phone number to call him. -Original Message- From: Martin Gainty [mailto:mgai...@hotmail.com] Sent: Wednesday, August 08, 2012 12:22 PM To: elim@gmail.com Cc: mysql@lists.mysql.com Subject: RE: trouble with perl I know I had the same problem with PHP when mysql.dll was off my PATH..put the 2 mysql libraries on the first directory from your PATH 05/30/2008 08:17 PM 2,125,824 libmysql.dll 06/13/2012 06:31 PM34,304 php_mysql.dll be aware when things go wrong with DLL's you have no way to fix it except 1)grab the source 2)build it ..usually thru .\configure then .\make install 3)make sure the new binary gets installed to the first directory on your PATH Viel Gluck, Martin __ Verzicht und Vertraulichkeitanmerkung/Note de déni et de confidentialité Diese Nachricht ist vertraulich. Sollten Sie nicht der vorgesehene Empfaenger sein, so bitten wir hoeflich um eine Mitteilung. Jede unbefugte Weiterleitung oder Fertigung einer Kopie ist unzulaessig. Diese Nachricht dient lediglich dem Austausch von Informationen und entfaltet keine rechtliche Bindungswirkung. Aufgrund der leichten Manipulierbarkeit von E-Mails koennen wir keine Haftung fuer den Inhalt uebernehmen. Ce message est confidentiel et peut être privilégié. Si vous n'êtes pas le destinataire prévu, nous te demandons avec bonté que pour satisfaire informez l'expéditeur. N'importe quelle diffusion non autorisée ou la copie de ceci est interdite. Ce message sert à l'information seulement et n'aura pas n'importe quel effet légalement obligatoire. Étant donné que les email peuvent facilement être sujets à la manipulation, nous ne pouvons accepter aucune responsabilité pour le contenu fourni. Date: Wed, 8 Aug 2012 13:28:42 -0400 Subject: Re: trouble with perl From: per...@elem.com To: elim@gmail.com CC: mysql@lists.mysql.com On Wed, Aug 8, 2012 at 1:12 PM, Elim Qiu elim@gmail.com wrote: But when I use browser for the system testing (perl_test.cgi and forum.pl), both report me that DBD:mysql is not installed (or not available) It's possible that DBD::mysql is installed in a place where it's not in the library path for your CGI script, or that you have more than one Perl installed on your system. I'd suggest you get some help either from the group that makes mwforum or on the Perl Beginner's list, since this is not a MySQL issue. The Perl Beginners list is here: http://lists.perl.org/list/beginners.html - Perrin -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql
Re: order by numeric value
Try
order by CAST(Balance as decimal(8,2)) asc;
Cast will work in the order by.
Glenn Vaughn
- Original Message -
From: Keith Clark keithcl...@k-wbookworm.com
To: mysql@lists.mysql.com
Sent: Tuesday, April 27, 2010 3:52 PM
Subject: order by numeric value
I have the following statement:
select chart_of_accounts.accountname as Account,
concat('$',format(coalesce(sum(sales_journal_entries.debit),0),2)) as
Debit,
concat('$',format(coalesce(sum(sales_journal_entries.credit),0),2)) as
Credit,
concat('$',format(coalesce(sum(sales_journal_entries.credit),0)-coalesce(sum(sales_journal_entries.debit),0),2))
as Balance
from sales_journal_entries
left join sales_journal
on sales_journal.journalID=sales_journal_entries.journalID
left join chart_of_accounts
on chart_of_accounts.accountID=sales_journal_entries.accountID
where sales_journal.date '2008-12-31'
and sales_journal.date '2010-01-01'
group by sales_journal_entries.accountID
order by Balance asc;
and I'd like the output to be sorted by the Balance according to the
numberic value, but it is sorting by the string result. I tried
abs(Balance) but I get the following error:
1247 Reference 'Balance' not supported (reference to group function)
I'm not sure I understand the error.
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Re: Weeks
If all you want is the current week then the query is simple: SELECT * FROM orders where WEEK(orders.order_date) = WEEK(NOW()) The default is thje day starts on Sunday so the second value is not needed. WEEK(NOW(),7) is equivalent to WEEK(NOW(),0) - the valid values are 0 - 6. As for performance, I tested the query against a table I have with 199,826 rows - it returned the data in 0.016 seconds (selecting distinct week(date)) and selecting * returned 3,816 rows in 0.827 seconds. One concern will be when the data spans years - in that case you will need to also check for year: SELECT * FROM orders where WEEK(orders.date) = WEEK(NOW()) and YEAR(orders.order_date) = YEAR(NOW()) - Original Message - From: ML mailingli...@mailnewsrss.com To: mysql@lists.mysql.com Sent: Monday, December 28, 2009 5:14 PM Subject: Weeks Hi All, trying to write some SQL that will give me records for the CURRENT WEEK. Example, starting on a Sunday and going through Saturday. This week it would be Dec 27 - Jan 2. I am doing this so I can write a query that will show orders that are placed during the current week. Here is what I have, but this is showing from today for the next seven days. SELECT * FROM orders WHERE WEEK(NOW(), 7) = WEEK(orders.order_date, 7) AND DATEDIFF(NOW(),orders.order_date) 7; Would anyone have any advice? -Jason -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=my...@dawiz.net -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=arch...@jab.org
Re: Is there a better way than this?
This will work: select distinct X from a as a where Y in(25) and not exists (select X from a as b where a.X = b.X and b.Y in(24)) - Original Message - From: Tim Molter tim.mol...@gmail.com To: mysql@lists.mysql.com Sent: Sunday, December 27, 2009 4:04 PM Subject: Is there a better way than this? I'm new to MySQL and I'm looking for some guidance. I have a table A, with two columns X and Y with the following data: | X|Y| 1 24 1 25 2 25 2 26 3 27 I want my SQL query to return 2 following this verbose logic: SELECT DISTINCT X FROM A WHERE Y equals 25 and Y also does NOT equal 24. I came up with the following SQL, which gives me my desired result, but is there a better way to do it? Can it be achieved using MINUS or UNION somehow? BTW, I'm using IN here because I intend to replace the single numbers (24 and 25) with arrays that have 0 to N members. SELECT DISTINCT X FROM `A` WHERE X IN ( SELECT X FROM `A` WHERE Y IN (25) ) AND X NOT IN ( SELECT X FROM `A` WHERE Y IN (24) ) Thanks! -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=my...@dawiz.net -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=arch...@jab.org
Re: Query help
SELECT count(distinct trans_no) from SEARCHES WHERE comp_id=675 and result='o'; - Original Message - From: Richard Reina rich...@rushlogistics.com To: mysql@lists.mysql.com Cc: rich...@rushlogistics.com Sent: Sunday, December 13, 2009 11:36 AM Subject: Query help I was wondering if someone could lend a hand with the following query. I have table. SEARCHES |ID |trans_no|comp_id|result 13 | 455| 675| o 15 | 302| 675| o 16 | 455| 675| o 12 | 225| 629| y SELECT count(*) FROM SEARCHES WHERE comp_id=675 AND result='o' GROUP BY trans_no; gives me a count of 3. However, what I need is a count for how many different (unique) transactions company number 675 got a result 'o' which would be 2 (455 302). I have tried different group by columns but to no avail. Can someone help? Thanks, Richard -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=my...@dawiz.net -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=arch...@jab.org
Re: Distinct max() and separate unique value
I would try: select max(object_id), term_taxonomy_id group by term_taxonomy_id order by term_taxonomy_id; max(column) returns a single value so distinct is not needed. The group by and order by should only have columns thaqt are displayed and that are not aggregate columns. - Original Message - From: Eric Anderson e...@macandbumble.com To: mysql@lists.mysql.com Sent: Tuesday, October 20, 2009 3:42 PM Subject: Distinct max() and separate unique value I'm trying to formulate a query on a Wordpress database that will give me the highest 'object_id' with the highest 'term_taxonomy_id', something like: +-+--+ | max(distinct object_id) | term_taxonomy_id | +-+--+ |1503 | 127 | |1494 | 122 | +-+--+ But I just can't seem to get there? select max(distinct object_id), term_taxonomy_id from wp_term_relationships where term_taxonomy_id IN (122,127) group by term_taxonomy_id, object_id order by term_taxonomy_id desc, object_id desc +-+--+ | max(distinct object_id) | term_taxonomy_id | +-+--+ |1503 | 127 | |1481 | 127 | | 300 | 127 | |1503 | 122 | |1494 | 122 | |1470 | 122 | |1468 | 122 | |1205 | 122 | |1062 | 122 | | 316 | 122 | | 306 | 122 | | 228 | 122 | | 222 | 122 | | 216 | 122 | | 211 | 122 | | 184 | 122 | | 155 | 122 | | 149 | 122 | | 134 | 122 | | 128 | 122 | | 124 | 122 | | 119 | 122 | | 113 | 122 | | 109 | 122 | | 105 | 122 | | 93 | 122 | | 91 | 122 | | 87 | 122 | +-+--+ -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=my...@dawiz.net -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=arch...@jab.org
Re: Distinct max() and separate unique value
- Original Message - From: Eric Anderson ke...@on-e.com To: mysql@lists.mysql.com Sent: Tuesday, October 20, 2009 4:05 PM Subject: Re: Distinct max() and separate unique value I'm trying to formulate a query on a Wordpress database that will give me the highest 'object_id' with the highest 'term_taxonomy_id', something like: +-+--+ | max(distinct object_id) | term_taxonomy_id | +-+--+ |1503 | 127 | |1494 | 122 | +-+--+ But I just can't seem to get there? I confess I did not understand what you are trying to do. If what you actually want is the highest 'term_taxonomy_id' for each distinct objhect_id then the query would be: select object_id, max(term_taxonomy_id) where term_taxonomy_id IN (122,127)group by object_id order by object_id desc; This query will not take into consideration term_taxonomy_Id values other than 122 and 127, it also will not return object_id's without a term_taxonomy_Id value of 122 or 127. -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/mysql?unsub=arch...@jab.org
Fw: Weird problem with mysql_query
- Original Message - From: Darryle Steplight [EMAIL PROTECTED] To: MySql [EMAIL PROTECTED] Cc: mysql@lists.mysql.com Sent: Tuesday, September 09, 2008 6:59 PM Subject: Re: Weird problem with mysql_query Hi G, There is nothing weird about your results. When you do a Count(*) without a GROUP BY(someColumn) you are essentially asking MySQL how many rows are present in the table. But when you do use Group By someColum , you are asking MySql how many rows do I have of someColumn . It's just a good practice to use GROUP BY when you want to a count of a specific column . mysql select count(*) as 'Count' from logins GROUP BY dawiz I found my problem - it turned out to be a misconception on my part; I was using sprintf(buf,%d, row[i]) if it was a numeric field - this was printing the address rather than the value. Apparently even though the data is type MYSQL_TYPE_LONGLONG it should be treated as char. G Vaughn -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
