Re: Good color coded SQL editor for MySQL?
Mysql-front is v.good, www.mysqlfront.de i think. james Jerry wrote: Does anyone know of a good color coded SQL editor for MySQL that works in Windows? TIA, Jerry - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: lost root password trouble
Hi Nick It'll be something like: /usr/bin/safe_mysqld --defaults-file=/etc/my.cnf --skip-grant-tables Cheers james Nick Wilson wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi everyone, I have searched the archives and read the manual but am at a loss as to how to get my root password back (or change it) The trick appears to be to start mysqld with --skip-grant-tables but I can't seem to do it. Here is what I've done: (running on Linux) service mysqld stop /etc/init.d/mysqld --skip-grant-tables // no joy /usr/libexec/mysqld --skip-grant-tables // no joy service mysqld --skip-grant-tables start // no joy I'd appreciate a little help :-) - -- Nick Wilson // www.tioka.com -BEGIN PGP SIGNATURE- Version: GnuPG v1.0.6 (GNU/Linux) iD8DBQE8zsnVHpvrrTa6L5oRAlV8AJ49K4qam8eUlJRJVflSNxIohhZ5ZQCfeDyt ZyaEmEOvoQQZ1KUpffdIino= =+qj5 -END PGP SIGNATURE- - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php . - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: lost root password trouble
It's OK Nick - it started. It's just writing that to the terminal window. Hit enter to get the command prompt back (or ctrl-c if that doesn't work). james Nick Wilson wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 * and then James Carrier declared It'll be something like: /usr/bin/safe_mysqld --defaults-file=/etc/my.cnf --skip-grant-tables Well, that's certainly progress of sorts :-) It's just 'hanging' now. It says 'starting mysqld daemon with databases from /var/lib/mysql' and just hangs any ideas? thanks james.. - -- Nick Wilson // www.explodingnet.com -BEGIN PGP SIGNATURE- Version: GnuPG v1.0.6 (GNU/Linux) iD8DBQE8ztUxHpvrrTa6L5oRAlCrAKC3HOrhNL2XkeUB68EHuYExKzPMIQCdGdji khY4FsLiU4JeTj03OJzjNKw= =1fV6 -END PGP SIGNATURE- - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php . - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: lost root password trouble
Ah... Do you have permissions over the mysql directories? Can you start safe_mysqld as root? (purely for problem solving purposes ;) And of course - are your databases in /var/lib/mysql? james Nick Wilson wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 * and then Gerald Clark declared Well, that's certainly progress of sorts :-) It's just 'hanging' now. It says 'starting mysqld daemon with databases from /var/lib/mysql' and just hangs It just wrote that message over the command prompt. It is not hung. Just hit enter. Nope, it's hung, I get nothing and not even CTRL-C will stop it, I have to physically close the terminal. - -- Nick Wilson // www.explodingnet.com -BEGIN PGP SIGNATURE- Version: GnuPG v1.0.6 (GNU/Linux) iD8DBQE8zt6gHpvrrTa6L5oRAr9tAKCgye3ZUwPUPFiDTDRrKjdDe36KvACfU11m k/uExiiLSXzwOa6Odcdnyv8= =21I4 -END PGP SIGNATURE- - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php . - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: lost root password trouble
Try
GRANT ALL PRIVILEGES ON *.* TO root@'%'
IDENTIFIED BY 'mypassword' WITH GRANT OPTION;
Or you could always do a straight
INSERT INTO user VALUES('%','root',password('mypassword'),
'Y','Y','Y','Y','Y','Y','Y','Y','Y','Y','Y','Y','Y','Y');
james
---
Nick Wilson wrote:
Well, I'm in !! Now I'm having trouble updating the user table :-(
GRANT ALL PRIVILEGES ON * TO root IDENTIFIED BY 'my_password';
Read the manual, read my book, still a clueless twat. Can anyone help me
get it right?
many thanks everyone :-)
sql,query
-
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Re: Urgent Help!!!
Hi Stanley You can get mysql to tell you what an error means by doing perror error number In your case the result is 'Record was already deleted (or record file crashed)'. You should be able to recover your table with myisamchk -r james At 15:09 04/03/2002 +, Stanley Joseph wrote: Hi , When ever I am running my query it gives me 1030- got error 134 from table handler. has anybody come across it. Any help will be greatly appreciated. Thanks Stanley This email and any attachments are confidential. They may contain privileged information and are intended for the named addressee (s) only. They must not be distributed without our consent. If you are not the intended recipient, please notify us immediately and do not disclose, distribute, or retain this email or any part of it. Unless expressly stated, opinions in this email are those of the individual sender, and not of The mobile republic. We believe but do not warrant that this e-mail and any attachments are virus free. You must therefore take full responsibility for virus checking. The mobile republic reserves the right to monitor all email communications through their networks * - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php James Carrier Bullet Online :: Aim Higher [http://www.bulletonline.com] 41b Beavor Lane, London W6 9BL Tel +44 (0) 20 8834 3442 Fax +44 (0) 20 8741 2790 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: ERROR 2006: MySQL Server Has Gone Away
Hello Emil You need to increase the max packet size that mysql can handle... try putting this in your my.cnf file under [mysqld]: set-variable = max_allowed_packet=5M and restarting your server (obv. if you're starting mysql from the command line use the switch --max_allowed_packet) james At 10:35 04/03/2002 -0500, Diego, Emil wrote: I am having a problem reading a SQL script to recreate a database. I am runing mysql 3.23 on Redhat linux 7.2. The SQL file contains 35 megs worth of data. Everytime i try running it to recreate my database from a backup i get the following error: ERROR 2006: MySQL server has gone away. I beleive that it is failing in the same spot. I have one very large table that has over 1 meg worth of data in a single row. I beleive that is where the SQL is failing. Is there anything I can do to modify the configuration to allow large SQL statements like that to run. Emil Diego Web Coordinator University of Miami School of Business [EMAIL PROTECTED] ph: 305.284.5449 fx: 305.284.3404 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php James Carrier Bullet Online :: Aim Higher [http://www.bulletonline.com] 41b Beavor Lane, London W6 9BL Tel +44 (0) 20 8834 3442 Fax +44 (0) 20 8741 2790 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: How to store an Image on MySQL
PHP builder have a good article on this subject, most of which is language-neutral: http://www.phpbuilder.com/columns/florian19991014.php3 At 10:51 28/02/2002 -0700, Hector Rosas wrote: Hi Everybody, I have a problem with MySQL when I try to store image file on it. I use a Blob field but the info that must be stored there should be between quotations marks right? Like a string , i mean GIF89kjflH.. more binary symbols... but if the image file information have a quotation in the file the info would get truncate and MySQL will not store it. My Question is How can I store a Image on MySQL, and I know that is't bettter to use a path to the image but I can't do this in that way. Any help would be great Thanks. Hector. -- Get your free email from www.linuxmail.org Powered by Outblaze - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php James Carrier Bullet Online :: Aim Higher [http://www.bulletonline.com] 41b Beavor Lane, London W6 9BL Tel +44 (0) 20 8834 3442 Fax +44 (0) 20 8741 2790 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: MySQL with SSL support
Hi JC I know you said stunnel is not an option but how about SSLwrap? http://www.quiltaholic.com/rickk/sslwrap/ james At 18:49 19/02/2002 -0800, JC wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Hi All, Need: Communicate securely using PKI from a DBI perl script to MySQL where dozens of clients connect from multiple sites around the country (stunnel is not an option :( If I issue a grant command like such GRANT ALL PRIVILEGES ON test.* TO [EMAIL PROTECTED] IDENTIFIED BY goodsecret REQUIRE SUBJECT C=EE, ST=Some-State, L=Tallinn, O=MySQL demo client certificate, CN=Tonu [EMAIL PROTECTED] AND ISSUER C=FI, ST=Some-State, L=Helsinki, O=MySQL Finland AB, CN=Tonu [EMAIL PROTECTED] AND CIPHER EDH-RSA-DES-CBC3-SHA I am assuming that in order to make something like this work that you would also need to present your client certificate then the mysqld would check the issuer and the cn for the client, but reading through the documentation, and the change log for DBD:MYSQL I don't see anything that would allow me to specify the client certificate. Searching through google I did find http:[EMAIL PROTECTED]/msg00050.html which specs that you are supposed to use mysql_ssl=1 in the DSN but that only gets me half way there. I was wondering if any of you guys out there have found a way around this tid bit of a problem. Background: I have version 4.01 running on a Linux 7.1 machine the environment variables for SSL show up. Thanks in Advance, JC -BEGIN PGP SIGNATURE- Version: PGPfreeware 6.5.8 for non-commercial use http://www.pgp.com iQA/AwUBPHMOqnX+hJvt5DtWEQIFFgCfQDNuz4buG7JQp1iDVkGIzZIfAM0AnivJ t1do+xjkRMJiJVzoQl8PeBxC =P9HK -END PGP SIGNATURE- - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php James Carrier Bullet Online :: Aim Higher [http://www.bulletonline.com] 41b Beavor Lane, London W6 9BL Tel +44 (0) 20 8834 3442 Fax +44 (0) 20 8741 2790 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: design help
Hi dn, thanks for replying. I suspect you're right about my 'problem' - I'm probably misunderstanding some simple SQL construct :-) Let's say I have the following tables: parts (partid int, partname varchar(255)) cats(catid int, catname varchar(255)) parts_cats (id int, partid int, catid int) To track which categories are assigned to which parts. I can use the following query to return parts and associated categories: SELECT partid,catid,partname,catname FROM parts_cats LEFT JOIN parts ON parts_cats.partid=parts.partid LEFT JOIN cats ON parts_cats.catid=cats.catid However, as I won't know how many categories are assigned to a given part, how can I: a) Form a query that only returns a list of parts that match a specifc set of categories (i.e. parts_cats has records where catid=1, 3 and 7 for any given partid) b) Know how many unique records I'm dealing with. Using the SQL above, if a part has, say, 3 categories then 3 rows would be returned. 4 categories and 4 rows are returned, etc. - how can I tell how big my result set is so that I can page through it using LIMIT? Hope I've explained myself clearly! - thanks in advance, james ps Completely OT question - how do you find your HomeChoice service? Been thinking about getting it for a while. j. At 09:39 10/02/2002 +, you wrote: The separate table idea is standard relational theory. The tbl schema might involve (1) a unique Id column (with AUTO_INCREMENT), (2) a 'copy' of whatever data from the existing tbl(s) to sufficiently identify the particular response/select box, and (3) one of the select box return values - there would then be as many rows as there were responses in the select box (n=3 in this example). The second of these must be sufficient information to uniquely identify which table entry in the original table relates to the particular select-response - these are called Foreign Keys. To retrieve all of the select-responses, you would indeed issue a SELECT...JOIN and thus be able to reassemble the HTML select command, for example. Yes you are correct (in your example) such a SELECT will produce a resultset of 3 rows. This will allow you to search on a single, or multiple (concurrent) select-responses. As mentioned, this is SOP. You say you want multiple responses but not multiple entries, but not why. Perhaps most of the 'problem' lies hidden there? =dn - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php James Carrier Bullet Online :: Aim Higher [http://www.bulletonline.com] 41b Beavor Lane, London W6 9BL Tel +44 (0) 20 8834 3442 Fax +44 (0) 20 8741 2790 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Quick SQL design help
Hello MySQL users I was wondering if one of you could advise me on the best solution to a problem I'm having - I'm sure this has been done before but haven't found anything in the archives. Basically the problem I am having is how best to handle multiple values for a specific column, in this case the values in question are coming from an HTML SELECT MULTI box processed by PHP. The way I have been doing this so far is to have a delimited value stored in a varchar column, e.g. If my select box returns the values 2,4 and 7 I insert into my table the string '|2|4|7|'. Surely there must be a better way than this - but it escapes me. In this setup the only way to match a specifc value when searching is to use the query: SELECT dataid,title FROM table WHERE category LIKE '%|4|%' Which obviously has a huge performance penalty - and of course you can't JOIN against any of these values. The only other way I thought of was to use a separate table for the category entries: SELECT dataid,title,category FROM table LEFT JOIN table_categories ON table.dataid=table_categories.dataid But in the example above this would return 3 entries, which I don't want, and I can't select a particular dataid which satisfies more than category, e.g. has categories 4 and 7 (i.e. for the example above the LIKE statement would be: WHERE category LIKE '%|4|%' AND LIKE '%|7|%'). Any ideas? Please help! Cheers, james - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Another question - Re: Quick SQL design help
Hi Amer Thanks for replying - I wonder if you could clear up a point for me. I'm going to have many, many possible multi values - too many for a SET or ENUM column as some other people have suggested. I'm happy using the following tables: parts (partid int, partname varchar(255)) cats(catid int, catname varchar(255)) parts_cats (id int, partid int, catid int) To track which categories are assigned to which parts. I can use the following query to return parts and associated categories: SELECT partid,catid,partname,catname FROM parts_cats LEFT JOIN parts ON parts_cats.partid=parts.partid LEFT JOIN cats ON parts_cats.catid=cats.catid However, as I won't know how many categories are assigned to a given part, how can I: a) Form a query that only returns a list of parts that match a specifc set of categories (e.g. 1=CatA' AND 5='CatE' AND 26='CatZ' only) b) Know how many unique records I'm dealing with. Using the SQL above, if a part has, say, 3 categories then 3 rows would be returned. 4 categories and 4 rows are returned, etc. - how can I tell how big my result set is so that I can page through it using LIMIT? Thanks again- james At 22:43 10/02/2002 -0500, Amer Neely wrote: Hello MySQL users I was wondering if one of you could advise me on the best solution to a problem I'm having - I'm sure this has been done before but haven't found anything in the archives. Basically the problem I am having is how best to handle multiple values for a specific column, in this case the values in question are coming from an HTML SELECT MULTI box processed by PHP. The way I have been doing this so far is to have a delimited value stored in a varchar column, e.g. If my select box returns the values 2,4 and 7 I insert into my table the string '|2|4|7|'. Surely there must be a better way than this - but it escapes me. In this setup the only way to match a specifc value when searching is to use the query: SELECT dataid,title FROM table WHERE category LIKE '%|4|%' Which obviously has a huge performance penalty - and of course you can't JOIN against any of these values. The only other way I thought of was to use a separate table for the category entries: SELECT dataid,title,category FROM table LEFT JOIN table_categories ON table.dataid=table_categories.dataid But in the example above this would return 3 entries, which I don't want, and I can't select a particular dataid which satisfies more than category, e.g. has categories 4 and 7 (i.e. for the example above the LIKE statement would be: WHERE category LIKE '%|4|%' AND LIKE '%|7|%'). One thing you could do is add a little programming to split the entry into its parts, once retrieved, then run your select on those. But a better solution would be to re-design your table/s to accomodate multiple values. -- Amer Neely, Softouch Information Services W: www.softouch.on.ca E: [EMAIL PROTECTED] V: 519.438.5887 Perl | PHP | MySQL | CGI programming for shopping carts, data entry forms. We make web sites work! - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php James Carrier Bullet Online :: Aim Higher [http://www.bulletonline.com] 41b Beavor Lane, London W6 9BL Tel +44 (0) 20 8834 3442 Fax +44 (0) 20 8741 2790 - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Quick SQL design help
Hello MySQL users I was wondering if one of you could advise me on the best solution to a problem I'm having - I'm sure this has been done before but haven't found anything in the archives. Basically the problem I am having is how best to handle multiple values for a specific column, in this case the values in question are coming from an HTML SELECT MULTI box processed by PHP. The way I have been doing this so far is to have a delimited value stored in a varchar column, e.g. If my select box returns the values 2,4 and 7 I insert into my table the string '|2|4|7|'. Surely there must be a better way than this - but it escapes me. In this setup the only way to match a specifc value when searching is to use the query: SELECT dataid,title FROM table WHERE category LIKE '%|4|%' Which obviously has a huge performance penalty - and of course you can't JOIN against any of these values. The only other way I thought of was to use a separate table for the category entries: SELECT dataid,title,category FROM table LEFT JOIN table_categories ON table.dataid=table_categories.dataid But in the example above this would return 3 entries, which I don't want, and I can't select a particular dataid which satisfies more than category, e.g. has categories 4 and 7 (i.e. for the example above the LIKE statement would be: WHERE category LIKE '%|4|%' AND LIKE '%|7|%'). Any ideas? Please help! Cheers, james - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
