Re: Milliseconds to date string
Hi Rafal, binary is a reserved word, you need to quote it with back-ticks ` if you want to use it: SELECT s2u.valus as `binary` FROM ... /Johan Rafal Kedziorski wrote: Hi, I get this: You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '(cast(from_unixtime(cast(s2u.value as binary) div 1000 ) as dat I think, the problem is here: select s2u.value as binary from users u, setting_2_user s2u where s2u.setting_id = 150 and u.user_id = s2u.user_id; You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near 'binary from users u, setting_2_user s2u where s2u.setting_id = -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Maximum row size for MyISAM table type
Hi Joshua, the BLOB or TEXT is stored separately from the row. What is stored is a pointer to where the BLOB/TEXT is located. /Johan Joshua Beall wrote: Hi All, I am a bit confused by the MySQL documentation on this subject. From http://dev.mysql.com/doc/mysql/en/Storage_requirements.html The maximum size of a row in a MyISAM table is 65,534 bytes. Each BLOB and TEXT column accounts for only five to nine bytes toward this size. So, the maximum size is 64k, but you can go over that limit by using BLOB or TEXT types, because although they can hold up to 4gb (2^32 bytes for LONGBLOB/LONGTEXT types), they still only contribue 5 to 9 bytes? What? Am I reading that correctly? Thanks for any clarification, -Josh -- Johan Hk, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: PRODUCT() function - calculating the product of grouped numeric values
Hi, you might take a look at this thread: http://lists.mysql.com/mysql/166184 /Johan Hi, I'm searching for a function that enables me to calculate the product of a group of values, like SUM() does. MySQL server version is at least 4.0.14. For example, a query like SELECT id, PRODUCT(value) AS 'product' FROM table GROUP BY id for this table -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Select non-matching rows
Hi, you could try: SELECT tbl1.id FROM tbl1 LEFT JOIN tbl2 ON tbl2.another_id = tbl1.id WHERE tbl2.id IS NULL /Johan Manish wrote: This should be simple but I am stuck here. I need to select rows from table 1, which do not have matching ID in table 2. Say each table has 100 rows each, and 90 rows from table 1 have matching 90 rows in table 2. SO I want to find remaining 10 rows. Simple query such as select tbl1.id from tbl1, tbl2 where tbl1..id = tbl2.another_id; returns me the matching 90 rows, but my job is now to find out remaining 10 rows, how do I do it. I have done this before but can't recall it now, simply replacing = with naturally returns Cartesian product. Any help will be highly appreciated. TIA, - Manish -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Group Query
Shaun, when you add WHERE B.Project_ID = '10' you, in a way, change your LEFT JOIN to an INNER JOIN. You need to do it like: LEFT OUTER JOIN Bookings B ON U.User_ID = B.Rep_ID AND B.Project_ID = '8' /Johan shaun thornburgh wrote: Thanks for your reply, This works great, but when I add a constraint such as WHERE B.Project_ID = '10' I dont get the NULL values from the User table which I need: SELECT COUNT(B.Booking_ID), U.User_Location FROM Users U LEFT OUTER JOIN Bookings B ON U.User_ID = B.Rep_ID WHERE B.Project_ID = '8' GROUP BY(U.User_Location); Any ideas, do I need to do a double join, or do I need to join the projects table also? Thanks for your help From: Paul McNeil [EMAIL PROTECTED] To: [EMAIL PROTECTED] Subject: RE: Group Query Date: Fri, 18 Jun 2004 08:20:10 -0400 You can use a Left Outer Join. Left Outer Join will include all that matches as well as that which doesn't. The resulting NULL entries for the count will evaluate to 0. SELECT COUNT(B.Booking_ID), U.User_Location FROM Users U LEFT OUTER JOIN Bookings B ON U.User_ID = B.User_ID GROUP BY(U.User_Location); God Bless Paul C. McNeil Developer in Java, MS-SQL, MySQL, and web technologies. GOD BLESS AMERICA! To God Be The Glory! -Original Message- From: shaun thornburgh [mailto:[EMAIL PROTECTED] Sent: Friday, June 18, 2004 7:54 AM To: [EMAIL PROTECTED] Subject: Group Query Hi, The following table produces a query that shows all bookings that user has made and groups the number of bookings by the users location code. mysql SELECT COUNT(B.Booking_ID), User_Location FROM Bookings B, Users U WHERE U.User_ID = B.User_ID GROUP BY(U.User_Location); At the momnet if no bookings are made by a particular user then their location isnt included in the result. Is it possible to modify this query so that if no bookings are made for a particlar location then the location is still included in the result i.e. +-+---+ | COUNT(B.Booking_ID) | User_Location | +-+---+ | 1 | 01| | 8 | 02 | | 9 | 03 | | 1 | 04 | | 1 | 05 | | 2 | 06 | | 1 | 07 | ... Many thanks for your help _ It's fast, it's easy and it's free. Get MSN Messenger today! http://www.msn.co.uk/messenger -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] _ It's fast, it's easy and it's free. Get MSN Messenger today! http://www.msn.co.uk/messenger -- Johan Hk, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Group Query
Hi, you can use: SELECT COUNT(B.Booking_ID), User_Location FROM Users U LEFT JOIN Bookings B ON U.User_ID = B.User_ID GROUP BY(U.User_Location); /Johan shaun thornburgh wrote: Hi, The following table produces a query that shows all bookings that user has made and groups the number of bookings by the users location code. mysql SELECT COUNT(B.Booking_ID), User_Location FROM Bookings B, Users U WHERE U.User_ID = B.User_ID GROUP BY(U.User_Location); At the momnet if no bookings are made by a particular user then their location isnt included in the result. Is it possible to modify this query so that if no bookings are made for a particlar location then the location is still included in the result i.e. +-+---+ | COUNT(B.Booking_ID) | User_Location | +-+---+ | 1 | 01| | 8 | 02 | | 9 | 03 | | 1 | 04 | | 1 | 05 | | 2 | 06 | | 1 | 07 | ... Many thanks for your help _ It's fast, it's easy and it's free. Get MSN Messenger today! http://www.msn.co.uk/messenger -- Johan Hk, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Using IF
Hi Keith, I think your problem comes down to the fact that IF() is a function that must return one value, when you put in your '*' you might be specifying more then one value to return. /Johan Keith wrote: g'day, Am having a bit of a problem with using IF. This is the error message I get: - SELECT rac.name AS race, IF ( el.entityType =1, ch. * , npc. * )charData FROM characters AS ch, entityLocation AS el, races AS rac, npc AS npc WHERE el.entityType IN ( 1, 10 ) AND el.containerType =6 AND el.containerID =75402 AND IF ( el.entityType =1, el.entityID = ch.characterID AND el.visibility =60 AND ch.raceID = rac.raceID AND ch.handle 'Khan', el.entityID = npc.npcID AND el.visibility =60 AND npc.raceID = rac.raceID ) LIMIT 0 , 30 MySQL said: #1064 - You have an error in your SQL syntax. Check the manual that corresponds to your MySQL server version for the right syntax to use near '* , npc. * )charData FROM characters AS ch, entityLocation AS - What I want to do is select everything from characters if the el.entityType is 1, else I want to select everything from npc table. Cheers, Keith -- Johan Hk, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: (might be off list) MySQL AB
Hi, yes it is something like limited or incorporated, it stands for Aktiebolag, which is a swedish word meaning literally Sharecompany. It is related to the fact, I suppose, that MySQL is Swedish/Finnish in origin. /Johan mc wrote: Hi, I would like to know what does the 'AB' in MySQL AB stand for? Is it something like limited or incorporated? If yes, is this something related to the origin of MySQL? I am a subscriber from Hong Kong. Thanks. mc. -- Johan Hook, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPA*NGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: ORDER BY Question
Hi Dirk, from the excellent on-line manual: http://dev.mysql.com/doc/mysql/en/SELECT.html Columns selected for output can be referred to in ORDER BY and GROUP BY clauses using column names, column aliases, or column positions. Column positions are integers and begin with 1: mysql SELECT college, region, seed FROM tournament - ORDER BY region, seed; mysql SELECT college, region AS r, seed AS s FROM tournament - ORDER BY r, s; mysql SELECT college, region, seed FROM tournament - ORDER BY 2, 3; /Johan Dirk Bremer (NISC) wrote: (The count(*) expression is the second column of the result set so you replace it with a 2). This saves you from having to use an 'As' expression for 'count(*)' although it makes the query less clear too. (It won't be apparent to some people what the effect of the '2' in the 'order by' is.) Rhino Thanks for all of the suggestions, the 'order by count' worked like a charm. Concerning Rhino's suggestion quoted above, it this method of using numbers to represent the columns documented anywhere? -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: ORDER BY Question
Hi Dirk, you should be able to just add on ORDER BY Count after your groub clause. /Johan Dirk Bremer (NISC) wrote: The following query produces the following results: select job_coop as 'Job/Coop', count(*) as Count from queue group by job_coop; -- snip Is there a way to use the ORDER BY clause to order the results by the numeric value of the count(*), i.e. so that the results would be sorted by the result of the count(*)? Dirk Bremer - Systems Programmer II - ESS/AMS - NISC St. Peters USA Central Time Zone 636-922-9158 ext. 8652 fax 636-447-4471 [EMAIL PROTECTED] www.nisc.cc -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: first LIMIT then ORDER
Assuming you want to order your arbitrary selection you could do something like: (SELECT t.Id FROM tab t LIMIT 10) UNION ALL (SELECT t.Id FROM tab t WHERE 1 0) ORDER BY t.Id /Johan Harald Fuchs wrote: In article [EMAIL PROTECTED], Paul DuBois [EMAIL PROTECTED] writes: At 18:51 +0200 4/21/04, Jacek Jaroczynski wrote: Is there possibility to first LIMIT and then ORDER records? Not with a single SELECT. ORDER BY occurs before LIMIT. You could use LIMIT and select into a temporary table, then select from the temporary table with ORDER BY. Except that LIMIT without ORDER BY doesn't make much sense: LIMIT 10 gives you the first 10 records according to some arbitrary order criterion. -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: What Is LIMIT? and How to Use LIMIT?
Hi, I guess this is for a java.sql.PreparedStatement as the '?' seem to indicate that. LIMIT limits ;-) the number of rows retrieved, i.e. LIMIT 10, 20 gives you 20 rows starting at row 20 in the resultset and LIMIT 10 gives you the first 10 rows. See: http://www.mysql.com/doc/en/SELECT.html /Johan Caroline Jen wrote: I saw somebody has MySQL statement this way: StringBuffer sql = new StringBuffer(512); sql.append(SELECT ThreadID, ForumID, MemberName, LastPostMemberName, ThreadTopic, ThreadBody); sql.append( FROM + TABLE_NAME); sql.append( ORDER BY + sort + + order); sql.append( LIMIT ?, ?); What is LIMIT? What those question marks stand for? __ Do you Yahoo!? Yahoo! Small Business $15K Web Design Giveaway http://promotions.yahoo.com/design_giveaway/ -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: select from two tables
Hi, if you are using 4.x or later you can use: (select * from helpdesk where month(helpdesk.hdcreatedate) = 3) UNION ALL (select * from archived where month(archived.hdcreatedate) = 3) LIMIT 0, 30; /Johan rmck wrote: Hi I have two tables in the same Db : table 1: helpdesk | CREATE TABLE `helpdesk` ( `wcalledname` varchar(50) default NULL, `wcalledphone` varchar(50) default NULL, `wcalledemail` varchar(50) default NULL, `typeof` varchar(50) default NULL, `status` varchar(25) default NULL, `reasoncall` text, `reasoncalls` varchar(128) default NULL, `whorespond` varchar(128) default NULL, `datecallin` varchar(50) default NULL, `passedon` varchar(15) default NULL, `datetimetores` varchar(128) default NULL, `wresponded` varchar(128) default NULL, `resol` text, `dateclosed` varchar(25) default NULL, `hdcreatedate` datetime default NULL, `hdupdate` datetime default NULL, `hdid` int(10) NOT NULL auto_increment, PRIMARY KEY (`hdid`) ) TYPE=MyISAM table 2: archived | CREATE TABLE `archived` ( `wcalledname` varchar(50) default NULL, `wcalledphone` varchar(50) default NULL, `wcalledemail` varchar(50) default NULL, `typeof` varchar(50) default NULL, `status` varchar(25) default NULL, `reasoncall` text, `reasoncalls` varchar(128) default NULL, `whorespond` varchar(128) default NULL, `datecallin` varchar(50) default NULL, `passedon` varchar(15) default NULL, `datetimetores` varchar(128) default NULL, `wresponded` varchar(128) default NULL, `resol` text, `dateclosed` varchar(25) default NULL, `hdcreatedate` datetime default NULL, `hdupdate` datetime default NULL, `hdid` int(10) NOT NULL default '0', PRIMARY KEY (`hdid`) ) TYPE=MyISAM Once a month I archive records from the helpdesk table to the archived one if the record is closed, but sometimes a record is still open so some records for the last month are still in helpdesk while all the closed are in archived. My issue is I want to know how to query both tables for a list of all records that are created for a certain month weather closed or not. This works fine for one table: select * from `helpdesk` where month(hdcreatedate) = 3 order by `hdcreatedate` limit 0 , 30; I was trying to use this but it lists the records more than once: Help: select * from helpdesk,archived where month(helpdesk.hdcreatedate) = 3 and month(archived.hdcreatedate) = 3 LIMIT 0, 30; But it seems to list records over and over again. Please help if this type of query I'm trying to do can work. Thanks, Rob -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: insert field from another table
Hi, you could try something like: INSERT INTO articles_multi(article,author,text_ru,text_en ) SELECT e.article,e.authoer,r.text,e.text FROM articles_en e, articles_ru r WHERE e.article = r.article AND e.author = r.article /Johan nullevent wrote: Hello mysql, I have two tables - articles_en and articles_ru. Its fields is 'article', 'author', 'text'. The difference is - field 'text' in articles_en has english text of article and field 'text' in articles_ru has russian text of article. Fields 'article' and 'author' are identical. The tables were filled simultaneously. I want create table articles_multi which will have fields 'article', 'author', 'text_ru', 'text_en' with data from articles_en and articles_ru. How can i do it? - bye, nullevent Wednesday, March 24, 2004 -- Johan Höök, Pythagoras Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Using OR
Hi Keith,
you can use:
pla.type IN ('1','2','3','4');
/Johan
Keith wrote:
is there any alternative to using OR for selecting between values?
ie: pla.type='1' OR pla.type='2' OR pla.type='3' OR pla.type='4'
Cheers,
Keith
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Re: Newbie: Rewriting A Query- How?
Hi Ken, you might try: SELECT s.PROJID,s.PROJECTNAME FROM S_PROJECTREGISTER s INNER JOIN SL_PROGPROJ l ON s.PROJID = l.PROJID AND l.SNAPSHOTID = 56 INNER JOIN SL_PORTPROG p ON l.PROGID = p.PROGID AND p.SNAPSHOTID = 56 AND p.PORTID IN (100994,100996) WHERE s.SNAPSHOTID = 56 AND s.PROJECTSTATUS 'Potential' Hope this helps, /Johan Ken Brown wrote: Anyone any idea how I could rewrite this as a join - all the indexes are in place and each of the components of this work fine - its only when the combined subqueries are passed to the root query does it appear to go wrong (Takes around 1.5 mins to complete and causes 100% processor utilisation while executing). (May be something for the developers to look at). But in the meantime I need to get this going SELECT PROJID,PROJECTNAME FROM S_PROJECTREGISTER WHERE SNAPSHOTID = 56 AND PROJID IN ( SELECT PROJID FROM SL_PROGPROJ WHERE SNAPSHOTID = 56 AND PROGID IN ( SELECT PROGID FROM SL_PORTPROG WHERE SNAPSHOTID = 56 AND PORTID IN(100994,100996) ) ) AND PROJECTSTATUS 'Potential' Ken mailto:[EMAIL PROTECTED] -- Johan Hk, Facility Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Newbie query question...
Hi John, I think you missed on the precedence of AND/OR if you change to AND (cat_id='2' OR cat_id='5' ) it should work as you want it to /Johan John Croson wrote: I have a simple query: SELECT id,year,month,day,cat_id FROM events LEFT JOIN calendar_cat ON events.cat=calendar_cat.cat_id WHERE year=YEAR(CURDATE()) AND month=MONTH(CURDATE()) AND day=DAYOFMONTH(CURDATE()) AND cat_id='2' OR cat_id='5' AND approved='1' ORDER BY year,month,day ASC -- Johan Höök, Facility Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: inser woes
Hi Doug, I think you need to quote imgsml=C2BUWS1028.jpg, like imgsml='C2BUWS1028.jpg', take care, /Johan [EMAIL PROTECTED] wrote: This has to be something silly, but I can not see it. Any help greatly appreciated: use newshop; insert into products set storeid=2, deptid=5, groupid=66, prodid='C2BUWS1028', prodtitle='bAntique Circle 6/20; 1/2inches-lg Pearl Buttons Novelty Buttons/b', proddesc1='3 buttons per card; 1/2 inches', price=3.75, imgsml=C2BUWS1028.jpg, imgsmlwidth=105, imgsmlheight=105, discid=12; gets ERROR 1109 at line 2: Unknown table 'C2BUWS1028' in field list mysql explain products; +--+--+--+-+-+---+ | Field| Type | Null | Key | Default | Extra | +--+--+--+-+-+---+ | storeid | varchar(50) | | PRI | | | | deptid | varchar(50) | | PRI | | | | groupid | varchar(50) | | PRI | | | | prodid | varchar(50) | | PRI | | | : : If I put all the col=value entries on one line it seems to work. I am generating a bunch of these so I can format them in any manner that works. It seems that set col1=value1, col2=value2, ... can not be continued Is this correct? Thanks for any pointers _ Douglas Denault [EMAIL PROTECTED] Voice: 301-469-8766 Fax: 301-469-0601 -- Johan Höök, Facility Engineering Group - MailTo:[EMAIL PROTECTED] - http://www.pythagoras.se Pythagoras AB, Stormbyv. 2-4, SE-163 55 SPÅNGA, Sweden Phone: +46 8 760 00 10 Fax: +46 8 761 22 77 -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
