Problem with complex query

2001-09-03 Thread Mike Yuen

Hi, i'm trying to make a simple message board and I need a bit of help to
finish up.  Here's my database structure first with some example data:
TABLE: mboard
mid |   topic   |   name| date
1   New site  John Doe  
2   Re: New site  Susie Q

TABLE: mboardindex
mbiid | mid | message
1   1   1
2   1   2

mboard holds all the data and mboardindex holds what messages go with
what.  In this case, mid = message = 1 indicates original message.
mid =1, message = 2 indicates reply to message 1.

Now, my problem is, i'm doing this in PHP4 and without subselects, i'm not
sure how to get the data to list like:

New siteJohn Doe
Re: New siteSusie Q

Here's my query:
SELECT * FROM mboard,mboardindex WHERE mboard.mid = mboardindex.mid ORDER
BY date

Well, this gets me everything with mboard.mid = mboardindex.mid = 1 (in
the case above).

Well, how do I get it mysql to select from the result of the above SELECT
statement.  For example, I want to select the mboardindex.message from the
above select statement results.  Normally, I would use a sub-select but we
can't do that in mysql.  Can anyone help me out?

Thanks,
Mike








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max. value from select statement

2001-09-03 Thread Mike Yuen

I have a table as such where mid is my auto increment primary key:

TABLE: mboard
mid
2
3
4
5

I'm doing this in combination with PHP4.
What I want to do is build a query that will allow me to get the largest mid 
from the table (mboard) above.
The query I have is: select max(mid) from mboard;
BUT I tried the following in PHP and it doesn't work:

$myquery = SELECT max(mid) FROM mboard;
$myresult = mysql_query($myquery);
$row = mysql_fetch_object($myresult);
print $row-mid is result;

Any ideas on how to do this?
Mike


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ERROR rotating logs problem in MySQL(Linux)

2001-08-08 Thread Mike Yuen

I'm pretty new to the Linux world and i'm getting the following error:
errors occured while rotating /var/log/mysqld.log

mysqladmin: connect to server at 'localhost' failed
error: 'Access denied for user: 'root@localhost'
erorr running prerotate script -- leaving old in place

Does anyone know how I can fix this on my Linux Red Hat 7 Server?

Thanks,
Mike




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Query help

2001-04-17 Thread Mike Yuen

I'm trying to build a query for a calendar program for a web site.  
Basically, I want a query that will print a word if there is an event booked 
on that day.

Here's how the relevant tables are laid out and what they mean:

TABLE: activities
AID - Primary Key
ALocation
AEmail
AName
ADay
AMonth
AYear
ACost
ATime

TABLE: clientactivities
CAID - Primary key
CUserName
AID - Foreign key from activities

Basically, activities lists all the activities announced by members.  Client 
activities shows all the events that a person has signed up for.

How can I build a query that will accommodate both tables.  Currently, i've 
got:
SELECT * FROM activities WHERE (activities.CUserName='$CUserName' AND 
ADay='$d' AND AMonth='$themonth' AND AYear='$y') OR activities.AID = 
clientactivity.AID)

But it doesn't quite work.

Thanks,
Mike
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external access to mysql

2001-02-12 Thread Mike Yuen

I and 2 others are working on a web site an occasionally.  Each of us are
in different locations and exchange info email.  Some of them
need to query the database to compare results with what is on the site
with the MySQL database.

My question is, is there a way to allow access to my database by creating
an account for each user and allowing them to connect to the database
externally?

Thanks,
Mike



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Exporting data

2001-02-10 Thread Mike Yuen

How do I dump all the contents of a table called "clients" into a .txt
file (or anyother kind of file for that matter).

Thanks for your help.
Mike



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PHP and MySQL combo

2001-01-18 Thread Mike Yuen

Is there anyway to tell how many connections are currently being served by
MySQL.  I'm using this in combination with PHP.  Also, does MySQL
automatically shut down when you leave the page?  I'm not using
mysql_pconnect - just the regular mysql_connect.

Thanks,
Mike



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Problem with creating default value

2001-01-14 Thread Mike Yuen

Hi.  This is a really easy question:

I have an existing table called clients.  I have an existing field called
CPicture.  I'm trying to add a default value of "no".

I've tried several times and can't seem to get it right.  So, does anyone
know how I can add a default value of "no" to an existing table (clients)
and field (CPicture)?

Thanks for your help.
Mike



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