Dear Reynier,
You can use JOIN on your both,
The JOIN have to run on the same feilds i.e IDA.
SELECT * FROM carro_de_compras LEFT JOIN os_articulo ON carro_de_compras.IDA
= os_articulo.IDA
This query returns all your users with their articles if any and you can
iterate on it.
but one note:
Use INDEX on both tables. You may encounter problems when your rows grow up.
about the UPDATE query:
UPDATE table SET value=value+1 WHERE id='1'
is enough, use that.
On 2/7/06, Reynier Perez Mira [EMAIL PROTECTED] wrote:
Hi:
I'm develop a simple shopping cart. I have this two tables:
carro_de_compras
--
IDU int(11) NOT NULL
IDA int(11) NOT NULL
CantidadDeArticulos int(11) NOT NULL
os_articulo
--
IDA int(11) NOT NULL auto_increment,
IDC int(11) NOT NULL default '0',
ANombre varchar(200) NOT NULL default '',
ADescripcion text,
ACantidad int(11) NOT NULL default '0',
AImagen varchar(50) default NULL,
IDU int(11) NOT NULL default '0',
APrecio float(6,2) default NULL,
KEY AI_IDA (`IDA`)
Before ask let me explain some things. As you can see in the tables I have
the same field IDU in both tables. So in first(table carro_de_compras) it
means is user ID loged on ecommerce system, the second is the user ID who
upload articles for sale. Something like eBay in wich you can sale and buy
at every time. The arrive the point in wich I need to optimize queries:
PHP Code:
-
$sql = mysql_query(SELECT * FROM carro_de_compras);
$sresultado = mysql_fetch_assoc($sql);
$query = mysql_query(SELECT * FROM os_articulo WHERE
(IDA='.$sresultado['IDA'].'));
while ($record = mysql_fetch_assoc($query)) {
$productos[] = $record;
}
The question for this problem is: exists any way to optimize this query
and leave only in one line? I read in MySQL doc about it and found some
about JOIN but I can't understand how it works. Maybe because I'm cuban and
not understand english as well as I want.
The other questions is how to add some values to a field. For example:
$sql = mysql_query(UPDATE table SET value=value+1 WHERE id='1');
For do this query I do this:
$sql = mysql_query(SELECT value FROM table WHERE id='1');
$result = mysql_query($sql);
$update = mysql_query(UPDATE table SET (value='.$result['value'].' + 1)
WHERE id='1');
So is possible to optimize this query?
Regards
ReynierPM
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