Just a test
Mikhail Berman
Just a test
I don¹t seem to be getting any messages, this is just a test, mysql query -- - Scott HanedaTel: 415.898.2602 http://www.newgeo.com Fax: 313.557.5052 [EMAIL PROTECTED]Novato, CA U.S.A. -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
This is just a test: sql,query,
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Re: [OT] C program warnning (Just a test i try to understand C in order to build my mysql client program)
Hi.
You know, this question is off-topic on the MySQL list.
On Wed, Feb 14, 2001 at 09:54:44AM +, [EMAIL PROTECTED] wrote:
Hi folks,
I am trying to compile a simple program to play with mysql. But i am
running into single problems, but i guess easy to solve by too many of
the wizards here.
I am too paranoic when compiling my programs, so i activate all warnning
(at least i try) flags to gnu c compiler.
The problem occurs when type conversion: type conversion is automatic
when a functions takes a single pointer to const anything, but when
there is a double pointer to a const type and i pass double pointer to a
non const type i run into problem? Why in the later case conversion is
not automatic? the former is.
This is a FAQ, see e.g. http://faqs.jmas.co.jp/FAQs/C-faq/faq, section
11.10. For a somewhat better explanation have a look at the C++ FAQ
(and also applies to your C program):
http://reality.sgi.com/austern_mti/std-c++/faq.html#C1
The summary is that one could bypass the const qualifier c() adds (not
in your example, but in general).
Here is the simple code (just to test):
#include stdio.h
int
t(const int *i)
{
printf("%d\n", *i);
return 0;
}
void
c(const char **reg)
With C++, you can declare it as
void c(const char * const* reg)
but this does not seem to be allowed in C (I am not used to C anymore,
but gcc 2.95.3 complains).
{
while (*reg)
printf("%s\n", *reg++);
}
int
main(int argc, char *argv[])
{
int i;
char*reg[] = {
"Gustavo",
"Vieira",
"Goncalves",
"Coelho", "Rios", NULL};
The other way is to declare "reg" to what is really is, instead:
const char *reg[] = ...
This will also work with C.
The solution of the C-FAQ is dirty (as it opens the hole again because
of which the auto cast is not made) and should IMHO be avoided, if
possible.
Bye,
Benjamin.
i = 10;
(void) t(i);
c(reg);
return 0;
}
But when compiling:
grios@etosha$ cc -ansi -pedantic -Wconversion -Wall -Werror t.c
cc1: warnings being treated as errors
t.c: In function `main':
t.c:30: warning: passing arg 1 of `c' from incompatible pointer type
grios@etosha$
[...]
-
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C program warnning (Just a test i try to understand C in order to build my mysql client program)
Hi folks,
I am trying to compile a simple program to play with mysql. But i am
running into single problems, but i guess easy to solve by too many of
the wizards here.
I am too paranoic when compiling my programs, so i activate all warnning
(at least i try) flags to gnu c compiler.
The problem occurs when type conversion: type conversion is automatic
when a functions takes a single pointer to const anything, but when
there is a double pointer to a const type and i pass double pointer to a
non const type i run into problem? Why in the later case conversion is
not automatic? the former is.
Here is the simple code (just to test):
#include stdio.h
int
t(const int *i)
{
printf("%d\n", *i);
return 0;
}
void
c(const char **reg)
{
while (*reg)
printf("%s\n", *reg++);
}
int
main(int argc, char *argv[])
{
int i;
char*reg[] = {
"Gustavo",
"Vieira",
"Goncalves",
"Coelho", "Rios", NULL};
i = 10;
(void) t(i);
c(reg);
return 0;
}
But when compiling:
grios@etosha$ cc -ansi -pedantic -Wconversion -Wall -Werror t.c
cc1: warnings being treated as errors
t.c: In function `main':
t.c:30: warning: passing arg 1 of `c' from incompatible pointer type
grios@etosha$
Why there is no problem when i pass a int * to as an argument to a
function that requires a const int * but when the argument is a double
pointer to a const it complains if i pass a double pointer to a non
const type. This warnnings always happen even if the argument
requirement is of type
const [int|float|double|any_thing] ** and the value passed is
[int|float|double|any_thing] **. Why automatic conversion does not take
place here too ?
Thanks a lot for your time and cooperation.
-
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