Re: Problem with PHP, but I know it MySQL
On Sat, 2002-06-15 at 05:31, Chuck Payne wrote: ... // Some where here it's not working. $sql = SELECT concat_ws(' ', fname, lname)as actor FROM actormovie WHERE title = '$title' ORDER by lname; $result = mysql_query($sql); print $sql; $actor = ; while ($myrow = mysql_fetch_array($result)) { $actor = $myrow[actor]; $actor .= A HREF='' . $actor . /ABR\n; } What am I doing working. Hi Chuck, What happens if you run the query in the mysql command line client? -- __ ___ ___ __ / |/ /_ __/ __/ __ \/ /Zak Greant [EMAIL PROTECTED] / /|_/ / // /\ \/ /_/ / /__ MySQL AB, Advocate /_/ /_/\_, /___/\___\_\___/ Calgary, Canada ___/ www.mysql.com - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Re: Problem with PHP, but I know it MySQL
A friend of my who is a programmer helped me only after I gave up on the mailing answering me. So it is fix now. I had to the following... // This is the actor query $sql = SELECT concat_ws(\ \, fname, lname)as actor FROM actormovie WHERE title = '$title'; $result = mysql_query($sql); $actor = ; while ($myrow = mysql_fetch_array($result)) { $actor = $myrow[actor]; $actor .= A HREF='' . $actor . /ABR\n; } where you set $actor = , it needs to be $actors, then the while loop should look like this; $actors = ; while ($myrow = mysql_fetch_array($result)) { $actor = $myrow[actor]; $actors .= A HREF='' . $actor . /ABR\n; } then when putting the info in the table, in the cast part you want to put $actors and not $actor. What is happening is that $actor is being reset every time you go through the loop. Thanks anyway, but I felt no was going to help me, since no answer after a day. Chuck On 6/15/02 10:42 PM, Zak Greant [EMAIL PROTECTED] wrote: On Sat, 2002-06-15 at 05:31, Chuck Payne wrote: ... // Some where here it's not working. $sql = SELECT concat_ws(' ', fname, lname)as actor FROM actormovie WHERE title = '$title' ORDER by lname; $result = mysql_query($sql); print $sql; $actor = ; while ($myrow = mysql_fetch_array($result)) { $actor = $myrow[actor]; $actor .= A HREF='' . $actor . /ABR\n; } What am I doing working. Hi Chuck, What happens if you run the query in the mysql command line client? - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
Problem with PHP, but I know it MySQL
Hi, I am working on a movie database I have two database that I am calling from but the problem I am having when I ask it to go and fetch all the movies with the same title, it stops and only shows one. Here is a basic layout... if($videoid) { $result = mysql_query(SELECT * FROM library WHERE videoid=$videoid,$db); $myrow = mysql_fetch_array($result); // The Myrows $title = $myrow[title]; $videoid = $myrow[videoid]; $catergory = $myrow[catergory]; $appraisal = $myrow[appraisal]; // Some where here it's not working. $sql = SELECT concat_ws(' ', fname, lname)as actor FROM actormovie WHERE title = '$title' ORDER by lname; $result = mysql_query($sql); print $sql; $actor = ; while ($myrow = mysql_fetch_array($result)) { $actor = $myrow[actor]; $actor .= A HREF='' . $actor . /ABR\n; } What am I doing working. Chuck Payne - Before posting, please check: http://www.mysql.com/manual.php (the manual) http://lists.mysql.com/ (the list archive) To request this thread, e-mail [EMAIL PROTECTED] To unsubscribe, e-mail [EMAIL PROTECTED] Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php