Re: Query Help 2
yes, just a typing mistakes~~ anyway, both of them work fine. gerald_clark [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] DId I type that? I meant 1,4 I left it as substring because that was what he tried. ¿n©_ ¡E¢X ¡¸ wrote: yes, it should work, but should not be 1,1 ? or simply: UPDATE RemoteStation SET company=LEFT(ID, 4); ? gerald_clark [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] How about: update RemoteStation set company=substring(ID,1,1); Jeff McKeon wrote: Damn fat fingers and MS Outlook. I sent the Query Help message before I was finishes typing. Sorry... I have two tables, customer table and a company table The customer table has an ID field that is 8 characters long. The first 4 characters are the company code. We just added a company table that has an id field that contains that companies id code. We also added a field to the customer table that will hold the company ID that the customer belongs to. So. Customer table ID name company 12347771 joe null 12347772 mary null 43210001 bob null Company Table ID name 1234 Acme 4321 Acme_Europe What I now need to do is create an update statement that will match the customer to the company by substring(Customer.ID,1,4) to Company.ID I tried: update RemoteStation set Company_ID=Company.ID where substring(Company_ID,1,4) like Company.ID; But it didn't work. Any suggestions? Thanks for the help, Jeff -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Query Help 2
Damn fat fingers and MS Outlook. I sent the Query Help message before I was finishes typing. Sorry... I have two tables, customer table and a company table The customer table has an ID field that is 8 characters long. The first 4 characters are the company code. We just added a company table that has an id field that contains that companies id code. We also added a field to the customer table that will hold the company ID that the customer belongs to. So. Customer table ID namecompany 12347771joe null 12347772marynull 43210001bob null Company Table ID name 1234Acme 4321Acme_Europe What I now need to do is create an update statement that will match the customer to the company by substring(Customer.ID,1,4) to Company.ID I tried: update RemoteStation set Company_ID=Company.ID where substring(Company_ID,1,4) like Company.ID; But it didn't work. Any suggestions? Thanks for the help, Jeff -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Query Help 2
How about: update RemoteStation set company=substring(ID,1,1); Jeff McKeon wrote: Damn fat fingers and MS Outlook. I sent the Query Help message before I was finishes typing. Sorry... I have two tables, customer table and a company table The customer table has an ID field that is 8 characters long. The first 4 characters are the company code. We just added a company table that has an id field that contains that companies id code. We also added a field to the customer table that will hold the company ID that the customer belongs to. So. Customer table ID namecompany 12347771joe null 12347772marynull 43210001bob null Company Table ID name 1234Acme 4321Acme_Europe What I now need to do is create an update statement that will match the customer to the company by substring(Customer.ID,1,4) to Company.ID I tried: update RemoteStation set Company_ID=Company.ID where substring(Company_ID,1,4) like Company.ID; But it didn't work. Any suggestions? Thanks for the help, Jeff -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Query Help 2
yes, it should work, but should not be 1,1 ? or simply: UPDATE RemoteStation SET company=LEFT(ID, 4); ? gerald_clark [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] How about: update RemoteStation set company=substring(ID,1,1); Jeff McKeon wrote: Damn fat fingers and MS Outlook. I sent the Query Help message before I was finishes typing. Sorry... I have two tables, customer table and a company table The customer table has an ID field that is 8 characters long. The first 4 characters are the company code. We just added a company table that has an id field that contains that companies id code. We also added a field to the customer table that will hold the company ID that the customer belongs to. So. Customer table ID name company 12347771 joe null 12347772 mary null 43210001 bob null Company Table ID name 1234 Acme 4321 Acme_Europe What I now need to do is create an update statement that will match the customer to the company by substring(Customer.ID,1,4) to Company.ID I tried: update RemoteStation set Company_ID=Company.ID where substring(Company_ID,1,4) like Company.ID; But it didn't work. Any suggestions? Thanks for the help, Jeff -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Re: Query Help 2
DId I type that? I meant 1,4 I left it as substring because that was what he tried. ¿n©_ ¡E¢X ¡¸ wrote: yes, it should work, but should not be 1,1 ? or simply: UPDATE RemoteStation SET company=LEFT(ID, 4); ? gerald_clark [EMAIL PROTECTED] wrote in message news:[EMAIL PROTECTED] How about: update RemoteStation set company=substring(ID,1,1); Jeff McKeon wrote: Damn fat fingers and MS Outlook. I sent the Query Help message before I was finishes typing. Sorry... I have two tables, customer table and a company table The customer table has an ID field that is 8 characters long. The first 4 characters are the company code. We just added a company table that has an id field that contains that companies id code. We also added a field to the customer table that will hold the company ID that the customer belongs to. So. Customer table ID name company 12347771 joe null 12347772 mary null 43210001 bob null Company Table ID name 1234 Acme 4321 Acme_Europe What I now need to do is create an update statement that will match the customer to the company by substring(Customer.ID,1,4) to Company.ID I tried: update RemoteStation set Company_ID=Company.ID where substring(Company_ID,1,4) like Company.ID; But it didn't work. Any suggestions? Thanks for the help, Jeff -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED] -- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
