Dyego,
from the documentation of CreateFile in old Visual C++ docs I found the
following description how to specify in Windows the name of a disk drive or
a partition on a disk drive. The name you used below looks more a Linux way
to specify a disk partition.
Best regards,
Heikki Tuuri
Innobase Oy
---
InnoDB - transactions, hot backup, and foreign key support for MySQL
See http://www.innodb.com, download MySQL-Max from http://www.mysql.com
"
Disk Devices
Windows NT: You can use the CreateFile function to open a disk drive or a
partition on a disk drive. The function returns a handle to the disk device;
that handle can be used with the DeviceIOControl function. The following
requirements must be met in order for such a call to succeed:
· The caller must have administrative privileges for the operation to
succeed on a hard disk drive.
· The lpFileName string should be of the form \\.\PHYSICALDRIVEx to open the
hard disk x. Hard disk numbers start at zero. For example: String
Meaning
\\.\PHYSICALDRIVE2
Obtains a handle to the third physical drive on the users computer.
· The lpFileName string should be \\.\x: to open a floppy drive x or a
partition x on a hard disk. For example: String
Meaning
\\.\A:
Obtains a handle to drive A on the users computer.
\\.\C:
Obtains a handle to drive C on the users computer.
"
--
Subject: The InnoDB on raw devices...
From: Dyego Souza do Carmo
Date: Fri, 13 Dec 2002 08:18:19 -0200
I'm trying to use InnoDB on raw device under Windows XP Prof.
my innodb_data_file_path is :
innodb_data_file_path = /dev/hda2:5Gnewraw
but mysql not create a database :(
any idea ?
my system is :
MySQL 3.23.54 on Windows XP
Tnks,
sql,query
-
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