please help .........very urgent
hi ,
I wanted to check the following condition and if it is
success i wanted to display a massage.I tried as
follows. but no luck. nothing displayed.
$dbQuery = results;
$result = mysql_query($dbQuery) or die(Couldn't get
file list);
if (!isset($result))
{echo NULL;}
//if (mysql_result($result == 0))(
//echo sorry;
?
please , tell me how can i do this ?
Thanx
Kane.
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Re: please help .........very urgent
Kane Wilson wrote:
I wanted to check the following condition and if it is
success i wanted to display a massage.I tried as
follows. but no luck. nothing displayed.
$dbQuery = results;
$result = mysql_query($dbQuery) or die(Couldn't get
file list);
if (!isset($result))
{echo NULL;}
//if (mysql_result($result == 0))(
//echo sorry;
?
Although this is something for a PHP mailing list of forum, I'll try to
give you some pointers.
I assume that you first used mysql_connect() to connect to the MySQL db.
mysql_query() returns FALSE if the query failed for some reason. In that
case you can use mysql_error() to retrieve the error message.
$result = mysql_query($dbQuery);
if (!$result) die('Query failed: ' . mysql_error());
Checking isset() is useless, since $result is always set (either with
false, true or the result resource of the query).
http://www.php.net/manual/en/ref.mysql.php contains an example which
shows all the steps you need to set up a connection and run a query.
Regards, Jigal.
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Re: please help .........very urgent
Hello.
$dbQuery = results;
Have you forgotten to put '$' before the 'results'? Do you
have display_errors = On in your php.ini?
Kane Wilson [EMAIL PROTECTED] wrote:
hi ,
I wanted to check the following condition and if it is
success i wanted to display a massage.I tried as
follows. but no luck. nothing displayed.
$dbQuery = results;
$result = mysql_query($dbQuery) or die(Couldn't get
file list);
if (!isset($result))
{echo NULL;}
//if (mysql_result($result == 0))(
//echo sorry;
?
please , tell me how can i do this ?
Thanx
Kane.
__
Click here to donate to the Hurricane Katrina relief effort.
http://store.yahoo.com/redcross-donate3/
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RE: please help .........very urgent
Hi!!
$dbQuery = select * from table where 1 ;
$result = mysql_query($dbQuery) or die(Error trying to execute the query:
.mysql_error());
If(mysql_num_rows($result)1){ //also: ==0 works
echo NULL;
-Original Message-
From: Kane Wilson [mailto:[EMAIL PROTECTED]
Sent: Wednesday, September 07, 2005 1:40 AM
To: mysql
Subject: please help .very urgent
hi ,
I wanted to check the following condition and if it is success i wanted to
display a massage.I tried as follows. but no luck. nothing displayed.
$dbQuery = results;
$result = mysql_query($dbQuery) or die(Couldn't get file list);
if (!isset($result))
{echo NULL;}
//if (mysql_result($result == 0))(
//echo sorry;
?
please , tell me how can i do this ?
Thanx
Kane.
__
Click here to donate to the Hurricane Katrina relief effort.
http://store.yahoo.com/redcross-donate3/
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
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For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
