Re: using DISTINCT after the ORDER BY clause has been applied

2007-03-14 Thread Yashesh Bhatia

On 3/14/07, Bill Guion [EMAIL PROTECTED] wrote:

At 11:33 PM + 3/13/07, [EMAIL PROTECTED] wrote:

Date: Tue, 13 Mar 2007 20:56:08 +0530
To: mysql@lists.mysql.com
From: Yashesh Bhatia [EMAIL PROTECTED]
Subject: using DISTINCT after the ORDER BY clause has been applied
Message-ID: [EMAIL PROTECTED]

Hello:

I had a quick question on using the DISTINCT clause in a SELECT query.

I have the following table which stores webpages viewed

table: page_viewed
page_idint   unsignedpage id of the page viewed
user_id int   unsigneduser id of the page viewed
ts timestamptimestamp of the page view.

Now i need to query the most recently viewed distinct pages and i have
the following data


page_id user_id ts

1  1   2007-03-13 20:40:46
2  1   2007-03-13 20:40:53
2  1   2007-03-13 20:41:01
1  1   2007-03-13 20:41:10


so basically i tried to write a query for recently viewed (for user_id
1) as follows

SELECT DISTINCT page_id
FROM page_viewed
WHERE user_id =1
ORDER BY ts DESC

however, this does not give me the result as i needed, i'd like to have it as

page_id

1
2

but the output is


page_id

2
1

therefore the DISTINCT clause would be first used to filter the rows
and then the ORDER BY would be applied, is there anyway to specify
that DISTINCT be applied after the ORDER BY clause ? if not, any other
way i could retrieve the above data ?

Thanks.

Yashesh Bhatia.




It looks to me as if your query returned exactly what you asked for.
It found the first two rows (other rows are not distinct), and then
ordered them in descending order by time stamp. Descending is largest
to smallest. TS for row 2 is larger than TS for row 1.



thx bill. yep. the DISTINCT is applied to the query first and then the
ORDER BY hence it takes the 1st 2 rows and then applies the ORDER BY.
however, in the application i need to get the rows ORDER BY ts DESC
first and then remove duplicates.

so it'd take the 4 rows and order them by ts desc

page_id

1
2
2
1

and then remove duplicates to give

page_id

1
2


any query to get the above desired result ?

thx.

yashesh bhatia


  -= Bill =-
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Re: using DISTINCT after the ORDER BY clause has been applied

2007-03-14 Thread Yashesh Bhatia

hi bill..

thx a lot for that tip. it worked fine.. this is the final one

SELECT DISTINCT t1.page_id
FROM (
SELECT page_id
FROM page_viewed
ORDER BY ts DESC
)t1

thanks.

yashesh bhatia.

On 3/14/07, Bill Guion [EMAIL PROTECTED] wrote:

At 8:48 PM +0530 3/14/07, Yashesh Bhatia wrote:

On 3/14/07, Bill Guion [EMAIL PROTECTED] wrote:
At 11:33 PM + 3/13/07, [EMAIL PROTECTED] wrote:

Date: Tue, 13 Mar 2007 20:56:08 +0530
To: mysql@lists.mysql.com
From: Yashesh Bhatia [EMAIL PROTECTED]
Subject: using DISTINCT after the ORDER BY clause has been applied
Message-ID: [EMAIL PROTECTED]

Hello:

 I had a quick question on using the DISTINCT clause in a SELECT query.

I have the following table which stores webpages viewed

table: page_viewed
page_idint   unsignedpage id of the page viewed
user_id int   unsigneduser id of the page viewed
ts timestamptimestamp of the page view.

Now i need to query the most recently viewed distinct pages and i have
the following data


page_id user_id ts

1  1   2007-03-13 20:40:46
2  1   2007-03-13 20:40:53
2  1   2007-03-13 20:41:01
1  1   2007-03-13 20:41:10


so basically i tried to write a query for recently viewed (for user_id
1) as follows

SELECT DISTINCT page_id
FROM page_viewed
WHERE user_id =1
ORDER BY ts DESC

How about some variation of:

SELECT DISTICNT page_id from
(SELECT page_id, user_id, ts
FROM page_viewed
ORDER BY ts DESC);

Some how you will have to sort the input to the SELECT DISTINCT first.

  -= Bill =-

  
however, this does not give me the result as i needed, i'd like to
have it as

page_id

1
2

but the output is


page_id

2
1

therefore the DISTINCT clause would be first used to filter the rows
and then the ORDER BY would be applied, is there anyway to specify
that DISTINCT be applied after the ORDER BY clause ? if not, any other
way i could retrieve the above data ?

Thanks.

Yashesh Bhatia.


It looks to me as if your query returned exactly what you asked for.
It found the first two rows (other rows are not distinct), and then
ordered them in descending order by time stamp. Descending is largest
to smallest. TS for row 2 is larger than TS for row 1.


thx bill. yep. the DISTINCT is applied to the query first and then the
ORDER BY hence it takes the 1st 2 rows and then applies the ORDER BY.
however, in the application i need to get the rows ORDER BY ts DESC
first and then remove duplicates.

so it'd take the 4 rows and order them by ts desc

page_id

1
2
2
1

and then remove duplicates to give

page_id

1
2


any query to get the above desired result ?

thx.

yashesh bhatia

   -= Bill =-
--

You were born with all you need to win at life.


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using DISTINCT after the ORDER BY clause has been applied

2007-03-13 Thread Yashesh Bhatia

Hello:

  I had a quick question on using the DISTINCT clause in a SELECT query.

I have the following table which stores webpages viewed

table: page_viewed
page_id int unsigned page id of the page viewed
user_id int unsigned user id of the page viewed
ts timestamp timestamp of the page view.

Now i need to query the most recently viewed distinct pages and i have
the following data

page_id  user_id ts
1   1   2007-03-13 20:40:46
2   1   2007-03-13 20:40:53
2   1   2007-03-13 20:41:01
1   1   2007-03-13 20:41:10


SELECT DISTINCT page_id
FROM page_viewed
WHERE user_id =1
ORDER BY ts DESC


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using DISTINCT after the ORDER BY clause has been applied

2007-03-13 Thread Yashesh Bhatia

Hello:

  I had a quick question on using the DISTINCT clause in a SELECT query.

I have the following table which stores webpages viewed

table: page_viewed
page_idint   unsignedpage id of the page viewed
user_id int   unsigneduser id of the page viewed
ts timestamptimestamp of the page view.

Now i need to query the most recently viewed distinct pages and i have
the following data


page_id  user_id ts

1   1   2007-03-13 20:40:46
2   1   2007-03-13 20:40:53
2   1   2007-03-13 20:41:01
1   1   2007-03-13 20:41:10


so basically i tried to write a query for recently viewed (for user_id
1) as follows

SELECT DISTINCT page_id
FROM page_viewed
WHERE user_id =1
ORDER BY ts DESC

however, this does not give me the result as i needed, i'd like to have it as

page_id

1
2

but the output is


page_id

2
1

therefore the DISTINCT clause would be first used to filter the rows
and then the ORDER BY would be applied, is there anyway to specify
that DISTINCT be applied after the ORDER BY clause ? if not, any other
way i could retrieve the above data ?

Thanks.

Yashesh Bhatia.


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using DISTINCT after the ORDER BY clause has been applied

2007-03-13 Thread Bill Guion

At 11:33 PM + 3/13/07, [EMAIL PROTECTED] wrote:


Date: Tue, 13 Mar 2007 20:56:08 +0530
To: mysql@lists.mysql.com
From: Yashesh Bhatia [EMAIL PROTECTED]
Subject: using DISTINCT after the ORDER BY clause has been applied
Message-ID: [EMAIL PROTECTED]

Hello:

   I had a quick question on using the DISTINCT clause in a SELECT query.

I have the following table which stores webpages viewed

table: page_viewed
page_idint   unsignedpage id of the page viewed
user_id int   unsigneduser id of the page viewed
ts timestamptimestamp of the page view.

Now i need to query the most recently viewed distinct pages and i have
the following data


page_id  user_id ts

1   1   2007-03-13 20:40:46
2   1   2007-03-13 20:40:53
2   1   2007-03-13 20:41:01
1   1   2007-03-13 20:41:10


so basically i tried to write a query for recently viewed (for user_id
1) as follows

SELECT DISTINCT page_id
FROM page_viewed
WHERE user_id =1
ORDER BY ts DESC

however, this does not give me the result as i needed, i'd like to have it as

page_id

1
2

but the output is


page_id

2
1

therefore the DISTINCT clause would be first used to filter the rows
and then the ORDER BY would be applied, is there anyway to specify
that DISTINCT be applied after the ORDER BY clause ? if not, any other
way i could retrieve the above data ?

Thanks.

Yashesh Bhatia.


It looks to me as if your query returned exactly what you asked for. 
It found the first two rows (other rows are not distinct), and then 
ordered them in descending order by time stamp. Descending is largest 
to smallest. TS for row 2 is larger than TS for row 1.


 -= Bill =-
--

You were born with all you need to win at life.


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