Re: [PATCH v2 1/3] net: irda: pxaficp_ir: use sched_clock() for time management

2015-09-22 Thread Robert Jarzmik
David Miller  writes:

> From: Robert Jarzmik 
> Date: Fri, 18 Sep 2015 18:36:56 +0200
>
>> Which brings me to wonder which is the more correct :
>>  (a) replace to reproduce the same calculation
>>  Previously mtt was compared to a difference of 76ns steps (as 307ns / 4 
>> =
>>  76ns):
>>  while ((sched_clock() - si->last_clk) * 76 < mtt)
>> 
>>  (b) change the calculation assuming mtt is in microseconds :
>>  while ((sched_clock() - si->last_clk) * 1000 < mtt)
>> 
>> I have no IRDA protocol knowledge so unless someone points me to the correct
>> calculation I'll try my luck with (b).
>
> "a" would be "safer" and less likely to break anything, although as
> you say "b" might be more correct.
Indeed.

Well, let me try (b) then. I'll add in the commit message the timings change,
and if anybody complains a regression pops out, I'll provide a patch to fallback
to (a).

Cheers.

-- 
Robert
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Re: [PATCH v2 1/3] net: irda: pxaficp_ir: use sched_clock() for time management

2015-09-21 Thread David Miller
From: Robert Jarzmik 
Date: Fri, 18 Sep 2015 18:36:56 +0200

> Which brings me to wonder which is the more correct :
>  (a) replace to reproduce the same calculation
>  Previously mtt was compared to a difference of 76ns steps (as 307ns / 4 =
>  76ns):
>  while ((sched_clock() - si->last_clk) * 76 < mtt)
> 
>  (b) change the calculation assuming mtt is in microseconds :
>  while ((sched_clock() - si->last_clk) * 1000 < mtt)
> 
> I have no IRDA protocol knowledge so unless someone points me to the correct
> calculation I'll try my luck with (b).

"a" would be "safer" and less likely to break anything, although as
you say "b" might be more correct.
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Re: [PATCH v2 1/3] net: irda: pxaficp_ir: use sched_clock() for time management

2015-09-18 Thread Robert Jarzmik
David Miller  writes:

>> My understanding is that the flow will be :
>>  sched_clock()
>>rd->read_sched_clock() (cyc_to_ns() transformed for return)
>>  pxa_read_sched_clock()
>>readl_relaxed(OSCR)
>> 
>> I didn't see any timings issue, as the flow looks equivalent to the 
>> readl(OSCR),
>> but I might have overlooked something.
>
> Of course it's different, because sched_clock() converts the value read
> from OSCR into nanoseconds, which is obviously different from using the
> OSCR register value directly.
>
> You're therefore feeding different values into this IRDA code.
Ah yes, I see it.
Which brings me to wonder which is the more correct :
 (a) replace to reproduce the same calculation
 Previously mtt was compared to a difference of 76ns steps (as 307ns / 4 =
 76ns):
 while ((sched_clock() - si->last_clk) * 76 < mtt)

 (b) change the calculation assuming mtt is in microseconds :
 while ((sched_clock() - si->last_clk) * 1000 < mtt)

I have no IRDA protocol knowledge so unless someone points me to the correct
calculation I'll try my luck with (b).

Cheers.

-- 
Robert
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Re: [PATCH v2 1/3] net: irda: pxaficp_ir: use sched_clock() for time management

2015-09-17 Thread David Miller
From: Robert Jarzmik 
Date: Wed, 16 Sep 2015 11:34:01 +0200

> David Miller  writes:
> 
>> From: Robert Jarzmik 
>> Date: Sat, 12 Sep 2015 13:45:22 +0200
>>
>>> Instead of using directly the OS timer through direct register access,
>>> use the standard sched_clock(), which will end up in OSCR reading
>>> anyway.
>>> 
>>> This is a first step for direct access register removal and machine
>>> specific code removal from this driver.
>>> 
>>> Signed-off-by: Robert Jarzmik 
>>
>> What is the granularity of the OSCR register?
> It's 307ns (ie. 3.25MHz clock).
> 
>> If it is not nanoseconds, then you need to adjust calculations
>> such as this one:
> Tell me if the 307ns requires something I should adjust.
> 
> My understanding is that the flow will be :
>  sched_clock()
>rd->read_sched_clock() (cyc_to_ns() transformed for return)
>  pxa_read_sched_clock()
>readl_relaxed(OSCR)
> 
> I didn't see any timings issue, as the flow looks equivalent to the 
> readl(OSCR),
> but I might have overlooked something.

Of course it's different, because sched_clock() converts the value read
from OSCR into nanoseconds, which is obviously different from using the
OSCR register value directly.

You're therefore feeding different values into this IRDA code.
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Re: [PATCH v2 1/3] net: irda: pxaficp_ir: use sched_clock() for time management

2015-09-16 Thread Robert Jarzmik
David Miller  writes:

> From: Robert Jarzmik 
> Date: Sat, 12 Sep 2015 13:45:22 +0200
>
>> Instead of using directly the OS timer through direct register access,
>> use the standard sched_clock(), which will end up in OSCR reading
>> anyway.
>> 
>> This is a first step for direct access register removal and machine
>> specific code removal from this driver.
>> 
>> Signed-off-by: Robert Jarzmik 
>
> What is the granularity of the OSCR register?
It's 307ns (ie. 3.25MHz clock).

> If it is not nanoseconds, then you need to adjust calculations
> such as this one:
Tell me if the 307ns requires something I should adjust.

My understanding is that the flow will be :
 sched_clock()
   rd->read_sched_clock() (cyc_to_ns() transformed for return)
 pxa_read_sched_clock()
   readl_relaxed(OSCR)

I didn't see any timings issue, as the flow looks equivalent to the readl(OSCR),
but I might have overlooked something.

Cheers.

-- 
Robert
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Re: [PATCH v2 1/3] net: irda: pxaficp_ir: use sched_clock() for time management

2015-09-15 Thread David Miller
From: Robert Jarzmik 
Date: Sat, 12 Sep 2015 13:45:22 +0200

> Instead of using directly the OS timer through direct register access,
> use the standard sched_clock(), which will end up in OSCR reading
> anyway.
> 
> This is a first step for direct access register removal and machine
> specific code removal from this driver.
> 
> Signed-off-by: Robert Jarzmik 

What is the granularity of the OSCR register?

If it is not nanoseconds, then you need to adjust calculations
such as this one:

> @@ -549,7 +548,7 @@ static int pxa_irda_hard_xmit(struct sk_buff *skb, struct 
> net_device *dev)
>   skb_copy_from_linear_data(skb, si->dma_tx_buff, skb->len);
>  
>   if (mtt)
> - while ((unsigned)(readl_relaxed(OSCR) - 
> si->last_oscr)/4 < mtt)
> + while ((sched_clock() - si->last_clk) / 4 < mtt)
>   cpu_relax();
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