[newbie] darned networking tables

2001-08-18 Thread dic98

I just noticed an annoying ethernet redundancy and I can't figure how to get rid
of it.  Or maybe I'm not noticing anything and I'm just crazy.  You tell me...

# netstat -rn
Kernel IP routing table
DestinationGateway Genmask  Flags  MSS  Window  irtt  Iface
(my isp)   0.0.0.0  255.255.255.255  UH 0  0  0ppp0
(my network.0) (my ip)  255.255.255.0UG 0  0  0eth0
(my network.0) 0.0.0.0  255.255.255.0U  0  0  0eth0
127.0.0.0  0.0.0.0  255.0.0.0U  0  0  0lo
0.0.0.0(my isp) 0.0.0.0  UG 0  0  0ppp0

Okay, why am I eth0'ing thru my localhost ip (2nd entry) to my network? 
Obviously I need the 0.0.0.0 to my network (3rd entry), but isn't #2 redundant?
 If so, what are the ramifications of it being like this and how do I fix it? 
I've tried route del'ing, but all i get is:

# route del 192.168.0.0
SIOCDELRT: no such process

Any suggestions/explanations would be much appreciated.

 - Isaac

ps: I have a copy and have read the Network Administrator's Guide, so if you
know where to send me in there you can just give me a chapter or page number
instead of typing it all out yourself.



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Re: [newbie] darned networking tables

2001-08-18 Thread dic98

ip for my machine is 192.168.0.1 (thats the my ip in the table)
ip for network is 192.168.0.0 (my network.0 as i wrote it)
everything with the network is fine, it seems
i can ping back and forth without any trouble
ifconfig looks great
i just dont know how to get rid of that annoying 2nd eth0 to 192.168.0.0

 - isaac



Quoting etharp [EMAIL PROTECTED]:

 is the IP for your machine end in .0? needs to end in .1 to .253 as I
 believe 
 the 192.168.0.0 is reserved as well as 192.168.0.255. 
 the 0.0.0.0 is default until they are assigned a IP from dhcp
 it is not a problem (normally) for an interface to have more than one
 entry. 
 what does ifconfig say? 
 
 On Saturday 18 August 2001 07:39, [EMAIL PROTECTED] wrote:
  I just noticed an annoying ethernet redundancy and I can't figure how
 to
  get rid of it.  Or maybe I'm not noticing anything and I'm just crazy.
  You
  tell me...
 
  # netstat -rn
  Kernel IP routing table
  DestinationGateway Genmask  Flags  MSS  Window  irtt 
 Iface
  (my isp)   0.0.0.0  255.255.255.255  UH 0  0  0   
 ppp0
  (my network.0) (my ip)  255.255.255.0UG 0  0  0   
 eth0
  (my network.0) 0.0.0.0  255.255.255.0U  0  0  0   
 eth0
  127.0.0.0  0.0.0.0  255.0.0.0U  0  0  0   
 lo
  0.0.0.0(my isp) 0.0.0.0  UG 0  0  0   
 ppp0
 
  Okay, why am I eth0'ing thru my localhost ip (2nd entry) to my
 network?
  Obviously I need the 0.0.0.0 to my network (3rd entry), but isn't #2
  redundant? If so, what are the ramifications of it being like this and
 how
  do I fix it? I've tried route del'ing, but all i get is:
 
  # route del 192.168.0.0
  SIOCDELRT: no such process
 
  Any suggestions/explanations would be much appreciated.
 
   - Isaac
 
  ps: I have a copy and have read the Network Administrator's Guide, so
 if
  you know where to send me in there you can just give me a chapter or
 page
  number instead of typing it all out yourself.
 
 
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Re: [newbie] darned networking tables

2001-08-18 Thread etharp

is the IP for your machine end in .0? needs to end in .1 to .253 as I believe 
the 192.168.0.0 is reserved as well as 192.168.0.255. 
the 0.0.0.0 is default until they are assigned a IP from dhcp
it is not a problem (normally) for an interface to have more than one entry. 
what does ifconfig say? 

On Saturday 18 August 2001 07:39, [EMAIL PROTECTED] wrote:
 I just noticed an annoying ethernet redundancy and I can't figure how to
 get rid of it.  Or maybe I'm not noticing anything and I'm just crazy.  You
 tell me...

 # netstat -rn
 Kernel IP routing table
 DestinationGateway Genmask  Flags  MSS  Window  irtt  Iface
 (my isp)   0.0.0.0  255.255.255.255  UH 0  0  0ppp0
 (my network.0) (my ip)  255.255.255.0UG 0  0  0eth0
 (my network.0) 0.0.0.0  255.255.255.0U  0  0  0eth0
 127.0.0.0  0.0.0.0  255.0.0.0U  0  0  0lo
 0.0.0.0(my isp) 0.0.0.0  UG 0  0  0ppp0

 Okay, why am I eth0'ing thru my localhost ip (2nd entry) to my network?
 Obviously I need the 0.0.0.0 to my network (3rd entry), but isn't #2
 redundant? If so, what are the ramifications of it being like this and how
 do I fix it? I've tried route del'ing, but all i get is:

 # route del 192.168.0.0
 SIOCDELRT: no such process

 Any suggestions/explanations would be much appreciated.

  - Isaac

 ps: I have a copy and have read the Network Administrator's Guide, so if
 you know where to send me in there you can just give me a chapter or page
 number instead of typing it all out yourself.


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Re: [newbie] darned networking tables

2001-08-18 Thread etharp

linuxconf?
netconf.

On Saturday 18 August 2001 08:18, [EMAIL PROTECTED] wrote:
 ip for my machine is 192.168.0.1 (thats the my ip in the table)
 ip for network is 192.168.0.0 (my network.0 as i wrote it)
 everything with the network is fine, it seems
 i can ping back and forth without any trouble
 ifconfig looks great
 i just dont know how to get rid of that annoying 2nd eth0 to 192.168.0.0

  - isaac

 Quoting etharp [EMAIL PROTECTED]:
  is the IP for your machine end in .0? needs to end in .1 to .253 as I
  believe
  the 192.168.0.0 is reserved as well as 192.168.0.255.
  the 0.0.0.0 is default until they are assigned a IP from dhcp
  it is not a problem (normally) for an interface to have more than one
  entry.
  what does ifconfig say?
 
  On Saturday 18 August 2001 07:39, [EMAIL PROTECTED] wrote:
   I just noticed an annoying ethernet redundancy and I can't figure how
 
  to
 
   get rid of it.  Or maybe I'm not noticing anything and I'm just crazy.
 
   You
 
   tell me...
  
   # netstat -rn
   Kernel IP routing table
   DestinationGateway Genmask  Flags  MSS  Window  irtt
 
  Iface
 
   (my isp)   0.0.0.0  255.255.255.255  UH 0  0  0
 
  ppp0
 
   (my network.0) (my ip)  255.255.255.0UG 0  0  0
 
  eth0
 
   (my network.0) 0.0.0.0  255.255.255.0U  0  0  0
 
  eth0
 
   127.0.0.0  0.0.0.0  255.0.0.0U  0  0  0
 
  lo
 
   0.0.0.0(my isp) 0.0.0.0  UG 0  0  0
 
  ppp0
 
   Okay, why am I eth0'ing thru my localhost ip (2nd entry) to my
 
  network?
 
   Obviously I need the 0.0.0.0 to my network (3rd entry), but isn't #2
   redundant? If so, what are the ramifications of it being like this and
 
  how
 
   do I fix it? I've tried route del'ing, but all i get is:
  
   # route del 192.168.0.0
   SIOCDELRT: no such process
  
   Any suggestions/explanations would be much appreciated.
  
- Isaac
  
   ps: I have a copy and have read the Network Administrator's Guide, so
 
  if
 
   you know where to send me in there you can just give me a chapter or
 
  page
 
   number instead of typing it all out yourself.
 
  
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