Re: [NTG-context] \def\vec#1

2004-10-31 Thread David Arnold
Matthias,

Of course! Thanks.

>\def\vec#1{{\bf #1}}
>
>Matthias

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Re: [NTG-context] \def\vec#1

2004-10-31 Thread Matthias Weber
\def\vec#1{{\bf #1}}
Matthias
On Oct 31, 2004, at 2:49 PM, David Arnold wrote:
All,
This is fine.
\starttext
\startformula
\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right)=
\left(\matrix{x_1^2\cr x_2^2\cr \vdots\cr x_n^2}\right)
-2\left(\matrix{x_1\cr x_2\cr \vdots\cr x_n}\right)
-\left(\matrix{3\cr 3\cr \vdots\cr 3}\right).
\stopformula
If
\startformula
\vec x =\left(\matrix{x_1\cr x_2\cr \vdots\cr
  x_n}\right)\quad\hbox{and}\quad
\vec y =\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right),
\stopformula
\stoptext
But when I redefine \vec, I get a problem.
\def\vec#1{\bf #1}
\starttext
\startformula
\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right)=
\left(\matrix{x_1^2\cr x_2^2\cr \vdots\cr x_n^2}\right)
-2\left(\matrix{x_1\cr x_2\cr \vdots\cr x_n}\right)
-\left(\matrix{3\cr 3\cr \vdots\cr 3}\right).
\stopformula
If
\startformula
\vec x =\left(\matrix{x_1\cr x_2\cr \vdots\cr
  x_n}\right)\quad\hbox{and}\quad
\vec y =\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right),
\stopformula
\stoptext
I thought \vec in this case should just chew up the very next symbol, 
but
the bold seems to continue into the display in the second formula.

I'm missing something here. What is it?
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[NTG-context] \def\vec#1

2004-10-31 Thread David Arnold
All,

This is fine.

\starttext

\startformula
\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right)=
\left(\matrix{x_1^2\cr x_2^2\cr \vdots\cr x_n^2}\right)
-2\left(\matrix{x_1\cr x_2\cr \vdots\cr x_n}\right)
-\left(\matrix{3\cr 3\cr \vdots\cr 3}\right).
\stopformula
If
\startformula
\vec x =\left(\matrix{x_1\cr x_2\cr \vdots\cr
  x_n}\right)\quad\hbox{and}\quad
\vec y =\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right),
\stopformula

\stoptext

But when I redefine \vec, I get a problem.

\def\vec#1{\bf #1}

\starttext

\startformula
\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right)=
\left(\matrix{x_1^2\cr x_2^2\cr \vdots\cr x_n^2}\right)
-2\left(\matrix{x_1\cr x_2\cr \vdots\cr x_n}\right)
-\left(\matrix{3\cr 3\cr \vdots\cr 3}\right).
\stopformula
If
\startformula
\vec x =\left(\matrix{x_1\cr x_2\cr \vdots\cr
  x_n}\right)\quad\hbox{and}\quad
\vec y =\left(\matrix{y_1\cr y_2\cr \vdots\cr y_n}\right),
\stopformula

\stoptext

I thought \vec in this case should just chew up the very next symbol, but
the bold seems to continue into the display in the second formula.

I'm missing something here. What is it?


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