[Numpy-discussion] How construct custom slice
Hi Folks a = np.zeros((4,3,5,55,5),dtype='|S8') myLen = 4 # here I use myLen = len(something) li = [3,2,4] # li from a list.append(something) sl = slice(0,myLen) tmpIndex = tuple(li) + sl + 4 # == Here my problem a[tmpIndex] # So What I want is: fillMe = np.array(['foo','bar','hello','world']) # But I cant contruct by hand like this a[3,2,4,:4,4] = fillMe a Again. I need construct custom slice from here tmpIndex = tuple(li) + sl + 4 a[tmpIndex] Who can help me? Best Regards Mario Moura ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
Re: [Numpy-discussion] How construct custom slice
On Mon, Dec 27, 2010 at 10:36 AM, Mario Moura moura.ma...@gmail.com wrote: Hi Folks a = np.zeros((4,3,5,55,5),dtype='|S8') myLen = 4 # here I use myLen = len(something) li = [3,2,4] # li from a list.append(something) sl = slice(0,myLen) tmpIndex = tuple(li) + sl + 4 # == Here my problem a[tmpIndex] # So What I want is: fillMe = np.array(['foo','bar','hello','world']) # But I cant contruct by hand like this a[3,2,4,:4,4] = fillMe a Again. I need construct custom slice from here tmpIndex = tuple(li) + sl + 4 a[tmpIndex] First let's do it by hand: a = np.zeros((4,3,5,55,5),dtype='|S8') fillMe = np.array(['foo','bar','hello','world']) a[3,2,4,:4,4] = fillMe Now let's try using an index: b = np.zeros((4,3,5,55,5),dtype='|S8') myLen = 4 li = [3,2,4] sl = slice(0,myLen) Make index: idx = range(a.ndim) idx[:3] = li idx[3] = sl idx[4] = 4 idx = tuple(idx) Compare results: b[idx] = fillMe (a == b).all() True ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
Re: [Numpy-discussion] How construct custom slice
Hi Mr. Goodman Thanks a lot. Works Fine Reagards Mario Moura 2010/12/27 Keith Goodman kwgood...@gmail.com: On Mon, Dec 27, 2010 at 10:36 AM, Mario Moura moura.ma...@gmail.com wrote: Hi Folks a = np.zeros((4,3,5,55,5),dtype='|S8') myLen = 4 # here I use myLen = len(something) li = [3,2,4] # li from a list.append(something) sl = slice(0,myLen) tmpIndex = tuple(li) + sl + 4 # == Here my problem a[tmpIndex] # So What I want is: fillMe = np.array(['foo','bar','hello','world']) # But I cant contruct by hand like this a[3,2,4,:4,4] = fillMe a Again. I need construct custom slice from here tmpIndex = tuple(li) + sl + 4 a[tmpIndex] First let's do it by hand: a = np.zeros((4,3,5,55,5),dtype='|S8') fillMe = np.array(['foo','bar','hello','world']) a[3,2,4,:4,4] = fillMe Now let's try using an index: b = np.zeros((4,3,5,55,5),dtype='|S8') myLen = 4 li = [3,2,4] sl = slice(0,myLen) Make index: idx = range(a.ndim) idx[:3] = li idx[3] = sl idx[4] = 4 idx = tuple(idx) Compare results: b[idx] = fillMe (a == b).all() True ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion ___ NumPy-Discussion mailing list NumPy-Discussion@scipy.org http://mail.scipy.org/mailman/listinfo/numpy-discussion
