Re: [Numpy-discussion] The I dtype character

2013-04-12 Thread Georg Brandl 
Am 08.04.2013 09:14, schrieb Georg Brandl:
 Hi,
 
 is it intentional that I is supported as a dtype character, but cannot be
 suffixed with a size?
 
 dtype('i1')
 dtype('int8')
 dtype('I1')
 dtype('uint32')
 
 I know u is documented as unsigned integer, but this seems an unnecessary
 restriction that is confusing.

Looking at the code, I see now that using I2 raises a
DeprecationWarning anyway, which is fair enough.

Georg

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Re: [Numpy-discussion] The I dtype character

2013-04-12 Thread Nathaniel Smith 
On Mon, Apr 8, 2013 at 8:14 AM, Georg Brandl g.bra...@gmx.net wrote:
 Hi,

 is it intentional that I is supported as a dtype character, but cannot be
 suffixed with a size?

 dtype('i1')
 dtype('int8')
 dtype('I1')
 dtype('uint32')

i means integer. i1 means integer with 8 bits.

I means 32-bit unsigned integer. I1 means 32-bit unsigned
integer with 8 bits.

Obviously this last thing doesn't make much sense :-). Historically
numpy as accepted it anyway, and just ignored the suffix. In current
numpy it's still allowed for backwards compatibility, but deprecated,
and will become an error at some point. See
  https://github.com/numpy/numpy/issues/294

-n
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[Numpy-discussion] The I dtype character

2013-04-08 Thread Georg Brandl 
Hi,

is it intentional that I is supported as a dtype character, but cannot be
suffixed with a size?

 dtype('i1')
dtype('int8')
 dtype('I1')
dtype('uint32')

I know u is documented as unsigned integer, but this seems an unnecessary
restriction that is confusing.

thanks,
Georg

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