Re: [Paraview] Rendering in Paraview

[Fastl, Thomas]

Hello,

thank you for the help so far, I really appreciate any input!

ad Cory's response: I totally agree, seems to be a classic thing in rendering 
and makes total sense to me. However, strange is that this happens only for the 
right half of the ellipsoid. Any ideas on that?

ad Sam's and Ken's response: I was thinking about doing that in Matlab during 
generation, but thanks for pointing out that I can do it pretty straight 
forward in Paraview directly, makes things easier.

Again, I think it is just a little bit strange that the rendering problem 
occurs only on one half of the ellipsoid, maybe someone has experienced 
something similar? Thanks!

Thomas
?

From: ParaView  on behalf of Moreland, Kenneth 

Sent: Thursday, April 23, 2015 10:19 PM
To: Samuel Key
Cc: paraview@paraview.org
Subject: Re: [Paraview] Rendering in Paraview

If you want to use this approach, it is probably easier to use the transform 
filter and scale by 0.99 than use the calculator.

-Ken

Sent from my iPad so blame autocorrect.

On Apr 23, 2015, at 4:13 PM, Samuel Key 
mailto:samuel...@bresnan.net>> wrote:

Thomas,

Assuming your x,y,z-origin is at the center of the ellipsoid, and you are using 
PV version4.3.1, you might be able to do the following:

If you want to display these two objects at the same time, use the "eyeball" in 
the Pipeline Browser to turn off the hex mesh, then use the Calculator filter 
just on the quad mesh to shrink its x,y,z-coordinates by, say, 0.99. This will 
"pull" the quad mesh just inside the hex mesh. You can then do whatever 
variable display you like on the objects.

If you are going to this display several times, the pipeline can be saved with 
Save State.

Sam


On 4/23/2015 12:21 PM, Fastl, Thomas wrote:

Hello Community,


I have a question concerning rendering in Paraview (Version 4.2.0). I have two 
.vtk files: i) an ellipsoidal volume geometry of hexahedral cells (cell type = 
12) and ii) the internal surface of the ellipsoidal geometry represented using 
quadrilateral cells (cell type = 9). The first one is colored grey in the 
attached image, while the latter one is displayed in blue. Opening both of them 
at the same time leads to a quite confusing representation, which I don't 
really understand.


In the image attached the quadrilateral surface was opened first followed by 
the hexahedral volume. So I can understand why Paraview renders the left part 
in the color of the volume, but I do not get why it splits the rendering and is 
checkered on the right side? Is this an intended behavior or might I have made 
a mistake? I checked the coordinates of the points in both files and they are 
identical. Thanks!


Best, Thomas Fastl




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Re: [Paraview] Rendering in Paraview

[Moreland, Kenneth]

If you want to use this approach, it is probably easier to use the transform 
filter and scale by 0.99 than use the calculator.

-Ken

Sent from my iPad so blame autocorrect.

On Apr 23, 2015, at 4:13 PM, Samuel Key 
mailto:samuel...@bresnan.net>> wrote:

Thomas,

Assuming your x,y,z-origin is at the center of the ellipsoid, and you are using 
PV version4.3.1, you might be able to do the following:

If you want to display these two objects at the same time, use the "eyeball" in 
the Pipeline Browser to turn off the hex mesh, then use the Calculator filter 
just on the quad mesh to shrink its x,y,z-coordinates by, say, 0.99. This will 
"pull" the quad mesh just inside the hex mesh. You can then do whatever 
variable display you like on the objects.

If you are going to this display several times, the pipeline can be saved with 
Save State.

Sam


On 4/23/2015 12:21 PM, Fastl, Thomas wrote:

Hello Community,


I have a question concerning rendering in Paraview (Version 4.2.0). I have two 
.vtk files: i) an ellipsoidal volume geometry of hexahedral cells (cell type = 
12) and ii) the internal surface of the ellipsoidal geometry represented using 
quadrilateral cells (cell type = 9). The first one is colored grey in the 
attached image, while the latter one is displayed in blue. Opening both of them 
at the same time leads to a quite confusing representation, which I don't 
really understand.


In the image attached the quadrilateral surface was opened first followed by 
the hexahedral volume. So I can understand why Paraview renders the left part 
in the color of the volume, but I do not get why it splits the rendering and is 
checkered on the right side? Is this an intended behavior or might I have made 
a mistake? I checked the coordinates of the points in both files and they are 
identical. Thanks!


Best, Thomas Fastl




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Re: [Paraview] Rendering in Paraview

[Samuel Key]

  
  
Thomas,

Assuming your x,y,z-origin is at the center of the ellipsoid, and
you are using PV version4.3.1, you might be able to do the
following: 

If you want to display these two objects at the same time, use the
"eyeball" in the Pipeline Browser to turn off the hex mesh, then use
the Calculator filter just on the quad mesh to shrink its
x,y,z-coordinates by, say, 0.99. This will "pull" the quad mesh just
inside the hex mesh. You can then do whatever variable display you
like on the objects.

If you are going to this display several times, the pipeline can be
saved with Save State.

Sam


On 4/23/2015 12:21 PM, Fastl, Thomas
  wrote:


  
  
  
Hello Community,



I have a question concerning rendering in Paraview (Version
  4.2.0). I have two .vtk files: i) an ellipsoidal
volume geometry of hexahedral cells (cell type = 12) and ii) the internal surface of the ellipsoidal
geometry represented using quadrilateral cells (cell type = 9). The first one is colored grey in the attached image, while
the latter one is displayed in blue. Opening both of them at the same
time leads to a quite confusing representation, which I
don't really understand.

  
In the image attached the
quadrilateral surface was opened first followed by the
hexahedral volume. So I can understand why Paraview renders
the left part in the color of the volume, but I do not get
why it splits the rendering and is checkered on the right
side? Is this an intended behavior or might I have made a
mistake? I checked the coordinates of the points in both
files and they are identical. Thanks!


Best, Thomas Fastl



  
  
  
  
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Re: [Paraview] Rendering in Paraview

[Cory Quammen]

Thomas,

This looks like a classic case of z-fighting:

http://en.wikipedia.org/wiki/Z-fighting

One way to remedy this is to turn off the display of one of the surfaces.

Cory

On Thu, Apr 23, 2015 at 2:21 PM, Fastl, Thomas 
wrote:

>  Hello Community,
>
>
>  I have a question concerning rendering in Paraview (Version 4.2.0). I
> have two .vtk files: i) an ellipsoidal volume geometry of hexahedral cells 
> (cell
> type = 12) and ii) the internal surface of the ellipsoidal geometry
> represented using quadrilateral cells (cell type = 9). The first one is
> colored grey in the attached image, while the latter one is displayed in
> blue. Opening both of them at the same time leads to a quite confusing
> representation, which I don't really understand.
>
>
>  In the image attached the quadrilateral surface was opened first
> followed by the hexahedral volume. So I can understand why Paraview renders
> the left part in the color of the volume, but I do not get why it splits
> the rendering and is checkered on the right side? Is this an intended
> behavior or might I have made a mistake? I checked the coordinates of the
> points in both files and they are identical. Thanks!
>
>
>  Best, Thomas Fastl
>
>
>
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> Powered by www.kitware.com
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> http://www.kitware.com/opensource/opensource.html
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> Please keep messages on-topic and check the ParaView Wiki at:
> http://paraview.org/Wiki/ParaView
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>
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>


-- 
Cory Quammen
R&D Engineer
Kitware, Inc.
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