simple reg ex

[lorid]

I know this is perl not javascript, I thought I was good at deciphering reg ex
but the 2nd line in this function has got me puzzled.
Can anyone decipher:
 X = (!X ? 2 : X);

function round(number,X) {
 // rounds number to X decimal places, defaults to 2
 X = (!X ? 2 : X);
 return Math.round(number*Math.pow(10,X))/Math.pow(10,X);
 }
thanks
lori
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RE: simple reg ex

[Peter Guzis]

This is not a regular expression, but rather what is know as the ternary 
operator.  It is a terse way of writing an if-else statement with variable 
assignment.  In this case, it is the equivalent of writing:

if (!X) {

  X = 2;

} else {

  X = X;

}

-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of
lorid
Sent: Thursday, March 10, 2005 5:02 PM
To: perl-win32-users
Subject: simple reg ex


I know this is perl not javascript, I thought I was good at deciphering reg ex
but the 2nd line in this function has got me puzzled.
Can anyone decipher:
  X = (!X ? 2 : X);



function round(number,X) {
  // rounds number to X decimal places, defaults to 2
  X = (!X ? 2 : X);
  return Math.round(number*Math.pow(10,X))/Math.pow(10,X);
  }

thanks
lori

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Re: simple reg ex

[lorid]

sorry , I sent question too soon, long day.
forgot about the conditional reg ex
(test_value ? if_true : if_false)
lori
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RE: simple reg ex

[Charles K. Clarkson]

lorid  wrote:

: sorry , I sent question too soon, long day.
: 
: 
: forgot about the conditional reg ex

It's not a regular expression. It's an operator.


: (test_value ? if_true : if_false)


Charles K. Clarkson
-- 
Mobile Homes Specialist
254 968-8328

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