Re: forany, forall...
On Sun, Jan 16, 2005 at 09:27:56PM -0800, Jonathan Lang wrote:
> How would I do the following in Perl 6?
Modulo any syntax foibles, I think it'd look like this:
>
> if a given condition is true for every element in a list, do something.
if all(LIST) > 3 { do_something }
>
> or
>
> if a given condition is true for any element in a list, do something.
if any(LIST) > 3 { do_something }
Where LIST is, of course, the actual list of things. The exact syntax
of the conditional would change with what you wish to test.
if all(LIST) ~~ /foo/ { do_something }
if 7 < all(LIST) < 15 { do_something }
if all(LIST) eq 'fred' { do_something }
-Scott
--
Jonathan Scott Duff
[EMAIL PROTECTED]
Re: forany, forall...
Both of your questions are quite elegantly handled by junctions. If
the condition were, say, $elem > 10:
Jonathan Lang <[EMAIL PROTECTED]> wrote:
> if a given condition is true for every element in a list, do something.
if all(@list) > 10 { ... }
> if a given condition is true for any element in a list, do something.
if any(@list) > 10 { ... }
--
Brent 'Dax' Royal-Gordon <[EMAIL PROTECTED]>
Perl and Parrot hacker
"For those of you that can't spell, this site also contains free
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forany, forall...
How would I do the following in Perl 6? if a given condition is true for every element in a list, do something. or if a given condition is true for any element in a list, do something. = Jonathan "Dataweaver" Lang __ Do you Yahoo!? Yahoo! Mail - Helps protect you from nasty viruses. http://promotions.yahoo.com/new_mail
