Re: Announce: Rakudo Star Release 2017.04
On 05/01/2017 08:29 AM, Steve Mynott wrote: A useful and usable production distribution of Perl 6 I posted the following RFE: Would you please compile RPM's up for 2017.04: https://github.com/nxadm/rakudo-pkg/issues/11
Re: Need "contains" help
On 05/02/2017 10:02 PM, Shrivats wrote: Careful :-) You're actually closing the single quote youstarted with perl6 -e. In other words, this is your Shell's doing. You can execute this as a script with single quote around string literals with no issues Streetcars Mumble. And I did know that. :'( Thank you!
Re: Need "contains" help
On 05/02/2017 10:02 PM, Shrivats wrote: Careful :-) You're actually closing the single quote youstarted with perl6 -e. In other words, this is your Shell's doing. You can execute this as a script with single quote around string literals with no issues Streetcars Mumble. I did know that. Thank you!
Re: Need "contains" help
Careful :-)
You're actually closing the single quote youstarted with perl6 -e. In
other words, this is your Shell's doing.
You can execute this as a script with single quote around string literals
with no issues
Streetcars
On May 3, 2017 10:27, "ToddAndMargo" wrote:
> Hi All,
>
> Why does this work
>
> $ perl6 -e 'my $x="abcdef"; if $x.contains( "abc" ) { say "yes" } else {
> say "no" };'
> yes
>
>
> And this does not?
>
> $ perl6 -e 'my $x="abcdef"; if $x.contains( 'abc' ) { say "yes" } else {
> say "no" };'
> ===SORRY!=== Error while compiling -e
> Undeclared routine:
> abc used at line 1. Did you mean 'abs'?
>
> Why can I not use 'abc' and must use "abc"?
>
>
> Many thanks,
> -T
>
>
> --
>
> Yesterday it worked.
> Today it is not working.
> Windows is like that.
>
>
Need "contains" help
Hi All,
Why does this work
$ perl6 -e 'my $x="abcdef"; if $x.contains( "abc" ) { say "yes" } else {
say "no" };'
yes
And this does not?
$ perl6 -e 'my $x="abcdef"; if $x.contains( 'abc' ) { say "yes" } else {
say "no" };'
===SORRY!=== Error while compiling -e
Undeclared routine:
abc used at line 1. Did you mean 'abs'?
Why can I not use 'abc' and must use "abc"?
Many thanks,
-T
--
Yesterday it worked.
Today it is not working.
Windows is like that.
Re: Modulino in Perl 6
On Tue, May 02, 2017 at 05:02:40PM +0200, Gabor Szabo wrote: : Using the caller() in Perl 5 one can figure out if the file was loaded : as a module or executed as a script. : : In Python one could check if __name__ is equal to "__main__". : : Is there some way in Perl 6 to tell if a file was executed directly or : loaded into memory as a module? : : regards : Gabor If you write a MAIN sub, it should be called only if the file was executed directly. Larry
Re: Modulino in Perl 6
On Tue, 2 May 2017 17:02:40 +0200
Gabor Szabo wrote:
> Is there some way in Perl 6 to tell if a file was executed directly or
> loaded into memory as a module?
One way that seems to work: define a ``sub MAIN``; it will be invoked
when you execute the file as a program, but won't be touched if you
load it as a module.
Example: in file ``/tmp/x/Foo.pm6``::
class Foo {
has $.value;
}
sub MAIN($value) {
say Foo.new(:$value).value;
}
then::
$ perl6 -I /tmp/x -e 'use Foo;say Foo.new(:value(5)).value'
5
$ perl6 /tmp/x/Foo.pm6
Usage:
/tmp/x/Foo.pm6
$ perl6 /tmp/x/Foo.pm6 12
12
--
Dakkar -
GPG public key fingerprint = A071 E618 DD2C 5901 9574
6FE2 40EA 9883 7519 3F88
key id = 0x75193F88
Leela: You buy one pound of underwear and you're on their list forever.
Modulino in Perl 6
Using the caller() in Perl 5 one can figure out if the file was loaded as a module or executed as a script. In Python one could check if __name__ is equal to "__main__". Is there some way in Perl 6 to tell if a file was executed directly or loaded into memory as a module? regards Gabor
