Re: Removing ' characters
On 1/10/22 07:41, Richard Hainsworth wrote:
If a string is enclosed in ' characters, and I want to remove the
bracketing ', how do I do it?
Seems like ' is not a normal character, or is it because its not a
bracketing character?
Using REPL I got
> my $s = '\'\''
''
> $s.subst( / \' ~ \' (.+) /, $0)
Use of Nil in string context
in block at line 1
> my $t = '{}'
{}
> $t.subst( / \{ ~ \} (.+) /, $0)
For clarity
raku -v
Welcome to Rakudo™ v2021.12.
Implementing the Raku® Programming Language v6.d.
Built on MoarVM version 2021.12.
Hi Richard,
Are you trying to remove "all" single quotes
or just the ones surrounding the spoken word:
The profession said "The prime minister
rejected the phrase 'Bob's your Uncle'".
Which or all of the single quotes?
-T
Bob is definitely NOT my uncle.
Re: Removing ' characters
Hi Richard,
In a script:
my $s = '\'\'';
$s.subst( / "'" ~ "'" (.+) /, {$0}).put;
put s/ \< .+ \/ \> /$// given $s;
put s/ \' <( .+ )> \' /$// given $s;
#all three return:
HTH, Bill.
On Mon, Jan 10, 2022 at 8:46 AM Simon Proctor wrote:
>
> Within the regex the ' character is just another string so rather than
> escaping it you can write the regex as :
>
> $s.subst( / "'" ~ "'" (.+) /, $0)
>
> (That's " ' " (without spaces) to be exact.) And it does the trick.
>
> You can do the same when defining it $s = "''"; or $s =
> q['']; both work.
>
>
> On Mon, 10 Jan 2022 at 16:12, Richard Hainsworth
> wrote:
>>
>> Aha. Thanks
>>
>> On 10/01/2022 15:59, Gianni Ceccarelli wrote:
>> > On Mon, 10 Jan 2022 15:41:04 +
>> > Richard Hainsworth wrote:
>> >
>> >> Using REPL I got
>> >>
>> >> > my $s = '\'\''
>> >> ''
>> >> > $s.subst( / \' ~ \' (.+) /, $0)
>> >> Use of Nil in string context
>> >> in block at line 1
>> > That error message (which is a bit LTA) refers to the `$0`. As
>> > https://docs.raku.org/routine/subst#Callable shows, you need to write:
>> >
>> > $s.subst( / \' ~ \' (.+) /, { $0 })
>> >
>> >> > my $t = '{}'
>> >> {}
>> >> > $t.subst( / \{ ~ \} (.+) /, $0)
>> >>
>> > This only appear to work because you're running it in the same REPL
>> > session; the previous `subst` had the side-effect of setting `$0`
>> > (well, it sets `$/`, but `$0` is an alias for `$/[0]`…)
>> >
>
>
>
> --
> Simon Proctor
> Cognoscite aliquid novum cotidie
>
> http://www.khanate.co.uk/
Re: Removing ' characters
Within the regex the ' character is just another string so rather than
escaping it you can write the regex as :
$s.subst( / "'" ~ "'" (.+) /, $0)
(That's " ' " (without spaces) to be exact.) And it does the trick.
You can do the same when defining it $s = "''"; or $s =
q['']; both work.
On Mon, 10 Jan 2022 at 16:12, Richard Hainsworth
wrote:
> Aha. Thanks
>
> On 10/01/2022 15:59, Gianni Ceccarelli wrote:
> > On Mon, 10 Jan 2022 15:41:04 +
> > Richard Hainsworth wrote:
> >
> >> Using REPL I got
> >>
> >> > my $s = '\'\''
> >> ''
> >> > $s.subst( / \' ~ \' (.+) /, $0)
> >> Use of Nil in string context
> >> in block at line 1
> > That error message (which is a bit LTA) refers to the `$0`. As
> > https://docs.raku.org/routine/subst#Callable shows, you need to write:
> >
> > $s.subst( / \' ~ \' (.+) /, { $0 })
> >
> >> > my $t = '{}'
> >> {}
> >> > $t.subst( / \{ ~ \} (.+) /, $0)
> >>
> > This only appear to work because you're running it in the same REPL
> > session; the previous `subst` had the side-effect of setting `$0`
> > (well, it sets `$/`, but `$0` is an alias for `$/[0]`…)
> >
>
--
Simon Proctor
Cognoscite aliquid novum cotidie
http://www.khanate.co.uk/
Re: Removing ' characters
Aha. Thanks
On 10/01/2022 15:59, Gianni Ceccarelli wrote:
On Mon, 10 Jan 2022 15:41:04 +
Richard Hainsworth wrote:
Using REPL I got
> my $s = '\'\''
''
> $s.subst( / \' ~ \' (.+) /, $0)
Use of Nil in string context
in block at line 1
That error message (which is a bit LTA) refers to the `$0`. As
https://docs.raku.org/routine/subst#Callable shows, you need to write:
$s.subst( / \' ~ \' (.+) /, { $0 })
> my $t = '{}'
{}
> $t.subst( / \{ ~ \} (.+) /, $0)
This only appear to work because you're running it in the same REPL
session; the previous `subst` had the side-effect of setting `$0`
(well, it sets `$/`, but `$0` is an alias for `$/[0]`…)
Re: Removing ' characters
On Mon, 10 Jan 2022 15:41:04 +
Richard Hainsworth wrote:
> Using REPL I got
>
> > my $s = '\'\''
> ''
> > $s.subst( / \' ~ \' (.+) /, $0)
> Use of Nil in string context
> in block at line 1
That error message (which is a bit LTA) refers to the `$0`. As
https://docs.raku.org/routine/subst#Callable shows, you need to write:
$s.subst( / \' ~ \' (.+) /, { $0 })
> > my $t = '{}'
> {}
> > $t.subst( / \{ ~ \} (.+) /, $0)
>
This only appear to work because you're running it in the same REPL
session; the previous `subst` had the side-effect of setting `$0`
(well, it sets `$/`, but `$0` is an alias for `$/[0]`…)
--
Dakkar -
GPG public key fingerprint = A071 E618 DD2C 5901 9574
6FE2 40EA 9883 7519 3F88
key id = 0x75193F88
Removing ' characters
If a string is enclosed in ' characters, and I want to remove the
bracketing ', how do I do it?
Seems like ' is not a normal character, or is it because its not a
bracketing character?
Using REPL I got
> my $s = '\'\''
''
> $s.subst( / \' ~ \' (.+) /, $0)
Use of Nil in string context
in block at line 1
> my $t = '{}'
{}
> $t.subst( / \{ ~ \} (.+) /, $0)
For clarity
raku -v
Welcome to Rakudo™ v2021.12.
Implementing the Raku® Programming Language v6.d.
Built on MoarVM version 2021.12.
