Re: [HACKERS] Is current_user a function ?

2002-11-29 Thread Masaru Sugawara
On 28 Nov 2002 11:34:49 -0500
Rod Taylor <[EMAIL PROTECTED]> wrote:

> Force the system to use it as a function.
> select "current_user"();


On Thu, 28 Nov 2002 17:20:59 -0500
Tom Lane <[EMAIL PROTECTED]> wrote:

> > As for some current_*** functions, "select current_user;" seems to
> > work, but  "select current_user();" doesn't .
> 
> Complain to the SQL spec authors --- they mandated this peculiar keyword
> syntax for what is really a function call.


Since current_user() can be used in 7.2, I have thought it would work in 7.3 too.
I now understand it doesn't work any more -- as well, session_user(), user(),
current_date(), current_time(), current_timestamp() and etc. 


Thank you, Rod and Tom.



Regards,
Masaru Sugawara




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Re: [HACKERS] Is current_user a function ?

2002-11-28 Thread Tom Lane
Masaru Sugawara <[EMAIL PROTECTED]> writes:
> As for some current_*** functions, "select current_user;" seems to
> work, but  "select current_user();" doesn't .

Complain to the SQL spec authors --- they mandated this peculiar keyword
syntax for what is really a function call.

regards, tom lane

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Re: [HACKERS] Is current_user a function ?

2002-11-28 Thread Rod Taylor
Force the system to use it as a function.

select "current_user"();

On Thu, 2002-11-28 at 11:31, Masaru Sugawara wrote:
> Hi,
> 
> As for some current_*** functions, "select current_user;" seems to
> work, but  "select current_user();" doesn't . Though current_user is
> defined as one of functions, why does such an error occur ?
> 
> renew=# select current_user();
> ERROR:   parser: parse error at or near "(" at character 20
> 
> 
> Regards,
> Masaru Sugawara
> 
> 
> renew=# \df
>   List of functions
>Result data type  |   Schema   | Name  | Argument data types  
>   
> -++---+---
>  ...
>  name| pg_catalog | current_database  | 
>  name| pg_catalog | current_schema| 
>  name[]  | pg_catalog | current_schemas   | boolean
>  text| pg_catalog | current_setting   | text
>  name| pg_catalog | current_user  | 
>  ...
> 
> 
> renew=# select current_user();
> ERROR:   parser: parse error at or near "(" at character 20
> 
> renew=# select current_database();
>  current_database 
> --
>  renew
> (1 row)
> 
> renew=# select current_schema();
>  current_schema 
> 
>  public
> (1 row)
> 
> renew=# select current_schema(true);
>current_schemas   
> -
>  {pg_catalog,postgres,public}
> (1 row)
> 
> renew=# select current_schema(false);
>current_schemas   
> -
>  {postgres,public}
> (1 row)
> 
> renew=# select current_setting('search_path');
>  current_setting 
> -
>  $user,public
> (1 row)
> 
> 
> 
> 
> 
> 
> 
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-- 
Rod Taylor <[EMAIL PROTECTED]>


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[HACKERS] Is current_user a function ?

2002-11-28 Thread Masaru Sugawara
Hi,

As for some current_*** functions, "select current_user;" seems to
work, but  "select current_user();" doesn't . Though current_user is
defined as one of functions, why does such an error occur ?

renew=# select current_user();
ERROR:   parser: parse error at or near "(" at character 20


Regards,
Masaru Sugawara


renew=# \df
  List of functions
   Result data type  |   Schema   | Name  | Argument data types
 
-++---+---
 ...
 name| pg_catalog | current_database  | 
 name| pg_catalog | current_schema| 
 name[]  | pg_catalog | current_schemas   | boolean
 text| pg_catalog | current_setting   | text
 name| pg_catalog | current_user  | 
 ...


renew=# select current_user();
ERROR:   parser: parse error at or near "(" at character 20

renew=# select current_database();
 current_database 
--
 renew
(1 row)

renew=# select current_schema();
 current_schema 

 public
(1 row)

renew=# select current_schema(true);
   current_schemas   
-
 {pg_catalog,postgres,public}
(1 row)

renew=# select current_schema(false);
   current_schemas   
-
 {postgres,public}
(1 row)

renew=# select current_setting('search_path');
 current_setting 
-
 $user,public
(1 row)







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