Re: [HACKERS] How do I get the current time in seconds in the unix

2001-10-16 Thread Bill Studenmund

On Mon, 15 Oct 2001, Christopher Kings-Lynne wrote:

> Hmmm.  I don't know why date_part isn't working, but I now only use the
> EXTRACT syntax for maximum SQL compatibility.  ie. Do this instead:
>
> v_seed := EXTRACT (EPOCH FROM CURRENT_TIMESTAMP);

Unfortunatly that gives the same error. I think the problem is that the
underlying code isn't liking the EPOCH timezone. Tom mentioned he had
patches.

Take care,

Bill


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Re: [HACKERS] How do I get the current time in seconds in the unix

2001-10-14 Thread Thomas Lockhart

> > In 7.1 I was able to get this (I thought) with
> > date_part(''epoch'', timestamp ''now'') . That doesn't seem to work for me
> > in last week's -current.
> Thomas, I think you broke something.

It was actually a side effect of changing the date/time parser to no
longer ignore unrecognized text fields. The previous behavior has been
there from the Beginning, and the new behavior meant that the search
routine no longer returns "ignore" as a status (which caused the calling
routine to drop into the "special case" tests including "epoch").

Anyway, I've got patches, so no worries...

   - Thomas

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Re: [HACKERS] How do I get the current time in seconds in the unix epoch?

2001-10-13 Thread Tom Lane

Bill Studenmund <[EMAIL PROTECTED]> writes:
> In 7.1 I was able to get this (I thought) with
> date_part(''epoch'', timestamp ''now'') . That doesn't seem to work for me
> in last week's -current.

Indeed: in 7.1 I can do

test71=# select date_part('epoch', timestamp 'now');
 date_part

 1002946239
(1 row)

but current sources give

regression=# select date_part('epoch', timestamp 'now');
ERROR:  Timestamp with time zone units 'epoch' not recognized

Thomas, I think you broke something.

regards, tom lane

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