Re: [SQL] ordering by date for each ID

2011-05-12 Thread Samuel Gendler 
On Thu, May 12, 2011 at 1:45 PM, Thomas Kellerer  wrote:

> Nguyen,Diep T wrote on 12.05.2011 03:59:
>
>>
>> Any help would be appreciated.
>>
>
> SELECT id,
>   date,
>   score_count,
>   row_number() over (partition by id order by date desc) as order_value
> FROM your_table
>
>
>
Or the more general answer to your question is this:
http://www.postgresql.org/docs/8.4/interactive/functions-window.html
There's lots of neat things you can do with window functions.

--sam

Re: [SQL] ordering by date for each ID

2011-05-12 Thread Thomas Kellerer 

Nguyen,Diep T wrote on 12.05.2011 03:59:


Each ID can have different number of score counts.

My goal is to add column "order", which shows the order of the values
in column "date" in descendant order for each property. The expected output
will look like this:

  id |   date   | score_count | order
+--+---+---
  13 | 1999-09-16   |   4| 4
  13 | 2002-06-27   |   4| 3
  13 | 2006-10-25   |   4| 2
  13 | 2010-05-12   |   4| 1
  65 | 2002-07-18   |   3| 3
  65 | 2004-08-05   |   3| 2
  65 | 2007-08-15   |   3| 1
  86 | 2001-05-29   |   5| 5
  86 | 2002-04-04   |   5| 4
  86 | 2006-03-02   |   5| 3
  86 | 2008-02-13   |   5| 2
  86 | 2011-01-19   |   5| 1

Any help would be appreciated.


SELECT id,
   date,
   score_count,
   row_number() over (partition by id order by date desc) as order_value
FROM your_table


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[SQL] ordering by date for each ID

2011-05-12 Thread Nguyen,Diep T 
Hi all,
I have this table
 id |   date | score_count 
+--+-
 13 | 1999-09-16   |   4
 13 | 2002-06-27   |   4
 13 | 2006-10-25   |   4
 13 | 2010-05-12   |   4
 65 | 2002-07-18   |   3
 65 | 2004-08-05   |   3
 65 | 2007-08-15   |   3
 86 | 2001-05-29   |   5
 86 | 2002-04-04   |   5
 86 | 2006-03-02   |   5
 86 | 2008-02-13   |   5
 86 | 2011-01-19   |   5

Each ID can have different number of score counts.

My goal is to add column "order", which shows the order of the values
in column "date" in descendant order for each property. The expected output
will look like this:

 id |   date   | score_count | order
+--+---+---
 13 | 1999-09-16   |   4| 4
 13 | 2002-06-27   |   4| 3
 13 | 2006-10-25   |   4| 2
 13 | 2010-05-12   |   4| 1
 65 | 2002-07-18   |   3| 3
 65 | 2004-08-05   |   3| 2
 65 | 2007-08-15   |   3| 1
 86 | 2001-05-29   |   5| 5
 86 | 2002-04-04   |   5| 4
 86 | 2006-03-02   |   5| 3
 86 | 2008-02-13   |   5| 2 
 86 | 2011-01-19   |   5| 1

Any help would be appreciated.

Thanks,

Diep
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