[SQL] 1-byte integers
how can i specify an integer to be one byte byte or even 4 bits long? int1, int(1), tinyint are nowhere to be seen. smallest i can find is smallint that is 2 bytes. in a table i will have a few columns with values between 0 and 15, so optimally i am looking for some kind of unsigned 4-bits, or (un)signed integer (1-byte). i can live with smallint for a while but estimate a few millions of rows in the table to be a reality soon, in such cases every byte matters. is there some stig ---(end of broadcast)--- TIP 2: you can get off all lists at once with the unregister command (send "unregister YourEmailAddressHere" to [EMAIL PROTECTED])
Re: [SQL] A Not Join
L van der Walt wrote: > I have three table: > Users - Contains username, ID etc... > Permissions - A permission name and ID > Link up table - The user.id and permission.id > > If a user.id and a permission.id row exists in the linkuptable the user > have that permission granted. > > With the statement below I can see the permissions a user have. > > SELECT users.username, permissions.name > FROM users INNER JOIN linkuptable > ON (users.id = linkuptable.userid) > INNER JOIN permissions > ON (permissions.id = linkuptable.permissionid) > WHERE users.username = 'DummyUser' > > How do I see the permissions that user DON'T have with a fast SQL > statement. > > Thus, a NOT the statement for the above SQL statement > > Regards > > Lani > what you need to do is select all possible permissions and then remove the permissions that exist. try somthing like: SELECT permissions.name FROM permissions.name WHERE permission.permissionid NOT IN ( SELECT permissions.permissionid FROM users INNER JOIN linkuptable ON (users.id = linkuptable.userid) INNER JOIN permissions ON (permissions.id = linkuptable.permissionid) WHERE users.username = 'DummyUser' ) ---(end of broadcast)--- TIP 6: explain analyze is your friend
[SQL] a celko-puzzle from long time ago
While reading celko's SQL puzzles (second edition) i followed a reference to http://www.dbmsmag.com/9801d06.html. There is a puzzle that counts items in boxes. When i try to run the proposed solution on PG 8.1.5, PG says: ERROR: column reference "qty" is ambiguous apparently the variable declaration used in the solution is not proper for PostgreSQL. Is there a way to solve this puzzle in PostgreSQL? /stig ---(end of broadcast)--- TIP 3: Have you checked our extensive FAQ? http://www.postgresql.org/docs/faq