#25731 [Com]: '1d1' == '1e1' ??

[chara at interia dot pl]

 ID:               25731
 Comment by:       chara at interia dot pl
 Reported By:      md5 at pf dot pl
 Status:           Bogus
 Bug Type:         Feature/Change Request
 Operating System: *
 PHP Version:      *
 New Comment:

I thing, this is new float format:
1d1 = 1*10^1 = 1e1

example:
if (('3.5d3' == 3500) AND ('3.5d3' == '3.5E+3') AND ('3.5e3' ==
'3.5E+3')) {
  print('ok');
} else {
  print('no');
}
output:
ok

ALL IS OK. This is new float format. :)

Greetings,
CHARA=>TOMeK


Previous Comments:
------------------------------------------------------------------------

[2003-10-02 16:02:39] [EMAIL PROTECTED]

Use either === or strcmp()

------------------------------------------------------------------------

[2003-10-02 15:59:36] marcin dot staniszczak at wp dot pl

:-)

$a = '1d1';
if($a == '1d1') print('ok');
if($a == '1e1') print('ok');

php output:
okok


'1d1' == '1e1' !?

next example:
if('1d1' == '1e1') print('ok');

output:
ok

last example:
if('1d1' == '1e1') 
  print('ok');
else 
  print('no');

output:
ok
I thing, should be: no

------------------------------------------------------------------------

[2003-10-02 10:39:16] [EMAIL PROTECTED]

I don't understand polish, but what I understood from the example, this
is bogus.


------------------------------------------------------------------------

[2003-10-02 10:22:42] md5 at pf dot pl

Description:
------------
na php5 otrzymuje dwa razy napis "ok"

$a = '1d1';
if($a == '1d1') print('ok');
if($a == '1e1') print('ok');

wyniak z tego ze:
 '1d1' == '1e1'

i taki warunek:
if('1d1' == '1e1') print('ok');
takze pokazuje "ok"

Reproduce code:
---------------
if('1d1' == '1e1') print('ok');
else print('no');

Expected result:
----------------
powinno pojawic sie "no"

Actual result:
--------------
pojawia sie "ok"


------------------------------------------------------------------------


-- 
Edit this bug report at http://bugs.php.net/?id=25731&edit=1