Edit report at http://bugs.php.net/bug.php?id=49542&edit=1
ID: 49542
Comment by: matt dot lubner at gmail dot com
Reported by:mjs at beebo dot org
Summary:__callStatic() only invoked if instance method does
not exist
Status: Open
Type: Feature/Change Request
Package:Feature/Change Request
Operating System: Ubuntu
PHP Version:5.3.0
Block user comment: N
New Comment:
I should have also mentioned that calling an instance method in a static
context
does not generate an error, unless the called method has any references
to $this
(which of course is not in scope), in which case a fatal error occurs.
This can
be a little tricky to track down, and so would be preferable if instance
methods
were simply not in scope for static contexts.
Previous Comments:
[2010-10-15 03:40:41] matt dot lubner at gmail dot com
With PHP 5.3.2, if the instance method bar() is *not* public, and
__callStatic()
*is*, __callStatic() will be invoked, because bar() won't be in scope.
Unfortunately, this seems like a horribly hacked work-around. Ideally,
public
instance methods should not be in scope from a static context, so
__callStatic()
will be called instead.
[2009-09-13 14:34:38] mjs at beebo dot org
Description:
A static call to Foo::bar() does not invoke __callStatic() if an
instance method bar() exists.
One reason you might want this is to convert static calls to Foo::bar()
to the equivalent operation on a singleton:
public static function __callStatic($name, $args) {
$obj = self::getInstance();
return call_user_func_array(array($obj, $name), $args);
}
In the sample code below, __callStatic() is not invoked even though the
caller has deliberately initiated a static call.
Reproduce code:
---
http://bugs.php.net/bug.php?id=49542&edit=1
