#20406 [Bgs]: defined() does not work properly within function or class
ID: 20406
User updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Bogus
Bug Type: Variables related
Operating System: Windows XP
PHP Version: 4.2.0
New Comment:
About NAME and NOM : this is a translation problem only (NOM being the
french word for NAME). This piece of code is just an example to show
the bug : please read NAME and NOM as the same constant. I tested this
code and it print _really_ "value".
As for the name of an undefined constant being treated as the string
value of the name, i didn't knew about it.
It just makes me wonder more how are we supposed to check if a constant
is defined within a function or a class, and why we can't althought we
can access the value of this constant. I can't help but thinking that
this _is_ a bug.
Previous Comments:
[2002-11-13 07:35:44] [EMAIL PROTECTED]
Btw. your example is wrong, you check 'NOM' instead of 'NAME'.
Another thing in your script is "defined(NOM)". You should write
"define('NOM')".
And the last: you can't use "if (NAME)" for a replacement of "if
(defined('NAME'))". In this case NAME is evaluted to the string 'NAME'.
The condition is always TRUE :)
Think about it.
[2002-11-13 07:32:26] [EMAIL PROTECTED]
first, read the code you gave us again. it can't produce the output you
claim
it does. it will output "NOM", and possibly an E_NOTICE. clearly, this
is
not a test case for your perceived problem.
second, i don't know what EasyPHP is, but maybe you should file a PR
with its
vendor?
[2002-11-13 07:20:19] [EMAIL PROTECTED]
I was not asking for support nor help. I know that i can replace "if
(defined(NAME))" by "if (NAME)", for example.
I may be wrong about the place where i reported this bug.
But i wonder how you can explain that this is a good behavior for
defined() : how can a constant have a value that you can have access to
and not be defined ?
[2002-11-13 04:58:33] [EMAIL PROTECTED]
Sorry, but your problem does not imply a bug in PHP itself. For a
list of more appropriate places to ask for help using PHP, please
visit http://www.php.net/support.php as this bug system is not the
appropriate forum for asking support questions.
Thank you for your interest in PHP.
[2002-11-13 04:39:32] [EMAIL PROTECTED]
The function defined() always return false within a function or class,
although the value of the constant is still available.
the code :
will print "value" only. Currently tested with EasyPHP running with a
Windows XP computer.
--
Edit this bug report at http://bugs.php.net/?id=20406&edit=1
#20406 [Bgs]: defined() does not work properly within function or class
ID: 20406
User updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Bogus
Bug Type: Variables related
Operating System: Windows XP
PHP Version: 4.2.0
New Comment:
oh, and EasyPHP is a all-in-one package for installing Apache, MySQL,
PHP and PHPMyAdmin on one windows computer.
Check http://www.easyphp.org/ for more info. It's free ;o)
Previous Comments:
[2002-11-13 09:43:38] [EMAIL PROTECTED]
About NAME and NOM : this is a translation problem only (NOM being the
french word for NAME). This piece of code is just an example to show
the bug : please read NAME and NOM as the same constant. I tested this
code and it print _really_ "value".
As for the name of an undefined constant being treated as the string
value of the name, i didn't knew about it.
It just makes me wonder more how are we supposed to check if a constant
is defined within a function or a class, and why we can't althought we
can access the value of this constant. I can't help but thinking that
this _is_ a bug.
[2002-11-13 07:35:44] [EMAIL PROTECTED]
Btw. your example is wrong, you check 'NOM' instead of 'NAME'.
Another thing in your script is "defined(NOM)". You should write
"define('NOM')".
And the last: you can't use "if (NAME)" for a replacement of "if
(defined('NAME'))". In this case NAME is evaluted to the string 'NAME'.
The condition is always TRUE :)
Think about it.
[2002-11-13 07:32:26] [EMAIL PROTECTED]
first, read the code you gave us again. it can't produce the output you
claim
it does. it will output "NOM", and possibly an E_NOTICE. clearly, this
is
not a test case for your perceived problem.
second, i don't know what EasyPHP is, but maybe you should file a PR
with its
vendor?
[2002-11-13 07:20:19] [EMAIL PROTECTED]
I was not asking for support nor help. I know that i can replace "if
(defined(NAME))" by "if (NAME)", for example.
I may be wrong about the place where i reported this bug.
But i wonder how you can explain that this is a good behavior for
defined() : how can a constant have a value that you can have access to
and not be defined ?
[2002-11-13 04:58:33] [EMAIL PROTECTED]
Sorry, but your problem does not imply a bug in PHP itself. For a
list of more appropriate places to ask for help using PHP, please
visit http://www.php.net/support.php as this bug system is not the
appropriate forum for asking support questions.
Thank you for your interest in PHP.
The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
http://bugs.php.net/20406
--
Edit this bug report at http://bugs.php.net/?id=20406&edit=1
#20406 [Bgs]: defined() does not work properly within function or class
ID: 20406
User updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Bogus
Bug Type: Variables related
Operating System: Windows XP
PHP Version: 4.2.0
New Comment:
oh, and EasyPHP is a all-in-one package for installing Apache, MySQL,
PHP and PHPMyAdmin on one windows computer.
Check http://www.easyphp.org/ for more info. It's free ;o)
Previous Comments:
[2002-11-13 09:47:01] [EMAIL PROTECTED]
oh, and EasyPHP is a all-in-one package for installing Apache, MySQL,
PHP and PHPMyAdmin on one windows computer.
Check http://www.easyphp.org/ for more info. It's free ;o)
[2002-11-13 09:43:38] [EMAIL PROTECTED]
About NAME and NOM : this is a translation problem only (NOM being the
french word for NAME). This piece of code is just an example to show
the bug : please read NAME and NOM as the same constant. I tested this
code and it print _really_ "value".
As for the name of an undefined constant being treated as the string
value of the name, i didn't knew about it.
It just makes me wonder more how are we supposed to check if a constant
is defined within a function or a class, and why we can't althought we
can access the value of this constant. I can't help but thinking that
this _is_ a bug.
[2002-11-13 07:35:44] [EMAIL PROTECTED]
Btw. your example is wrong, you check 'NOM' instead of 'NAME'.
Another thing in your script is "defined(NOM)". You should write
"define('NOM')".
And the last: you can't use "if (NAME)" for a replacement of "if
(defined('NAME'))". In this case NAME is evaluted to the string 'NAME'.
The condition is always TRUE :)
Think about it.
[2002-11-13 07:32:26] [EMAIL PROTECTED]
first, read the code you gave us again. it can't produce the output you
claim
it does. it will output "NOM", and possibly an E_NOTICE. clearly, this
is
not a test case for your perceived problem.
second, i don't know what EasyPHP is, but maybe you should file a PR
with its
vendor?
[2002-11-13 07:20:19] [EMAIL PROTECTED]
I was not asking for support nor help. I know that i can replace "if
(defined(NAME))" by "if (NAME)", for example.
I may be wrong about the place where i reported this bug.
But i wonder how you can explain that this is a good behavior for
defined() : how can a constant have a value that you can have access to
and not be defined ?
The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
http://bugs.php.net/20406
--
Edit this bug report at http://bugs.php.net/?id=20406&edit=1
#20406 [Bgs]: defined() does not work properly within function or class
ID: 20406 Updated by: [EMAIL PROTECTED] Reported By: [EMAIL PROTECTED] Status: Bogus Bug Type: Variables related Operating System: Windows XP PHP Version: 4.2.0 New Comment: first, read the code you gave us again. it can't produce the output you claim it does. it will output "NOM", and possibly an E_NOTICE. clearly, this is not a test case for your perceived problem. second, i don't know what EasyPHP is, but maybe you should file a PR with its vendor? Previous Comments: [2002-11-13 07:20:19] [EMAIL PROTECTED] I was not asking for support nor help. I know that i can replace "if (defined(NAME))" by "if (NAME)", for example. I may be wrong about the place where i reported this bug. But i wonder how you can explain that this is a good behavior for defined() : how can a constant have a value that you can have access to and not be defined ? [2002-11-13 04:58:33] [EMAIL PROTECTED] Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Thank you for your interest in PHP. [2002-11-13 04:39:32] [EMAIL PROTECTED] The function defined() always return false within a function or class, although the value of the constant is still available. the code : will print "value" only. Currently tested with EasyPHP running with a Windows XP computer. -- Edit this bug report at http://bugs.php.net/?id=20406&edit=1
#20406 [Bgs]: defined() does not work properly within function or class
ID: 20406 User updated by: [EMAIL PROTECTED] Reported By: [EMAIL PROTECTED] Status: Bogus Bug Type: Variables related Operating System: Windows XP PHP Version: 4.2.0 New Comment: I was not asking for support nor help. I know that i can replace "if (defined(NAME))" by "if (NAME)", for example. I may be wrong about the place where i reported this bug. But i wonder how you can explain that this is a good behavior for defined() : how can a constant have a value that you can have access to and not be defined ? Previous Comments: [2002-11-13 04:58:33] [EMAIL PROTECTED] Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Thank you for your interest in PHP. [2002-11-13 04:39:32] [EMAIL PROTECTED] The function defined() always return false within a function or class, although the value of the constant is still available. the code : will print "value" only. Currently tested with EasyPHP running with a Windows XP computer. -- Edit this bug report at http://bugs.php.net/?id=20406&edit=1
