ID: 27418
User updated by: wb at pro-net dot co dot uk
Reported By: wb at pro-net dot co dot uk
Status: Open
Bug Type: *XML functions
Operating System: FreeBSD, WindowsXP
PHP Version: 5.0.0b4 (beta4)
New Comment:
Thanks for your reply. I have been playing around as well as reading
some threads on the DEV mailing list.
I think the main issue is that the simpleXML documentation in the
online manual is misleading and needs to be updated, this i feel would
probably solve 80% of the issues :)
But the other, and to me more important, issue is the inconsistancy
when using print_r() or var_dump(). They should always refer to the
items as a simplexml_element Object and never as a string. The thing to
remember is that the quickest way to find out what a vairable is is to
just print_r() or var_dump() it. Now i feel that most people will be
doing this to try to get an understanding of the new PHP5 objects, they
want to see quickly what is available, and when they see a value as a
string they expect to be able to use it as a string and not have it
turn out to be an object later on. Alos the fact that it looks like an
empty object when it is a simplexml_element dosen't help either.
I have no problem with haveing to cast the variable as a string as it
does show exactly how the object is being used in that situation and
rightfully a string != $anElement.
What about haveing the following methods to the simplexml_element
Object:
-setText($string)
-getText()
Then people could use these to get and set the 'text' value for that
element. I added the setValue() method because from the documentation i
can't see how one would set it anyway.
Anyway those are my ideas and i would be interested to find out what
people think.
Previous Comments:
[2004-03-02 10:17:02] adam at trachtenberg dot com
To parphrase Arthur C Clarke: You get different answers
because of magic. Well, advanced PHP technology that is
indistinguishable from magic.
The current solution to your problem is to cast the
variable before passing it to the function, like this:
utf8_decode((string) $user-login)
It would be better if you didn't need to do this, but
there's no clean solution to this problem right now.
We're working on it.
[2004-03-02 08:10:51] wb at pro-net dot co dot uk
I hav ebeen reading through the PHP-DEV archive and found message:
http://marc.theaimsgroup.com/?l=php-devm=107807524506690w=
Which contains...
foreach($xml-user as $user){
if (utf8_decode($user-login) == $login
utf8_decode($user-password) == $password) {
// valid users
}
}
Both seem like they should work, but neither do.
This infact does work in the example below with the php5 versions that
i have tried. Just thought that i would point it out even if i am not
quite doing things correctly (what should eb the correct way?).
My main issue/question for this bug is how do i traverse over multiple
site elements for each user? And why does is go from being
[site] = Array
(
[0] = www.pro-net.co.uk
[1] = www.example.com
)
)
To:
$user-site is:
Array
(
[0] = simplexml_element Object
(
)
[1] = simplexml_element Object
(
)
)
depending on how you call it?
[2004-02-27 09:43:44] wb at pro-net dot co dot uk
Description:
When using simpleXML you are unable to fetch some information. The
information is displayed with print_r() but you can't get it it
directly.
Use the example provided as an example.
Reproduce code:
---
?php
header('Content-type: text/plain');
$xmlstr = '?xml version=1.0?
access
user
loginuser1/login
passwordletMeIn/password
sitewww.pro-net.co.uk/site
sitewww.example.com/site
/user
user
loginuser2/login
passwordmyPassword/password
sitewww.pro-net.co.uk/site
/user
/access';
$nl = \r\n;
$xml = simplexml_load_string($xmlstr);
print('Current PHP version is : '.phpversion().$nl.$nl);
print('$xml is:'.$nl);
print_r($xml);
print($nl.$nl);
// Test authentication to get the correct user information
$login = 'user1';
$password = 'letMeIn';
print($nl.$nl.'Trying to authenticate '.$login.' with password
'.$password.'.'.$nl.$nl);
$isAuth = false;
foreach($xml-user as $user){
if(utf8_decode($user-login) == $login
utf8_decode($user-password) == $password){
$isAuth = true;
break;
}
}
if(!$isAuth){
print($nl.$nl.'Invalid User.'.$nl);
die();
}
// So lets output the variables to see what we have...
print('$user is:'.$nl);
print_r($user);
