#29271 [Bgs]: behaviour of $string['text'] = 'new string';
ID: 29271
User updated by: nospam0 at malkusch dot de
Reported By: nospam0 at malkusch dot de
Status: Bogus
Bug Type: Strings related
Operating System: *
PHP Version: 5.0.0
New Comment:
It's expected behaviour: 'index' is casted to it's
integer value (0), that's why you get this result.
But as I use $string[] and not $string{} it's undefined
wether it should be a new array or a string. So why
doesn't PHP throw an error?
Previous Comments:
[2004-07-28 12:39:59] [EMAIL PROTECTED]
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php
It's expected behaviour: 'index' is casted to it's integer value (0),
that's why you get this result.
[2004-07-20 01:54:22] nospam0 at malkusch dot de
Description:
$string = 'a bla';
$string['index'] = 'b blub';
does the same work as
$string = 'a bla';
$string{(int)'index'} = 'b blub'{0};
without any notic of undefined index or too long replacing
string. But it should throw any notice, because one could
expect that the code should produce a new Array('index' =
'b blubb').
Reproduce code:
---
$string = 'a bla';
$string['index'] = 'b blub';
var_dump($string);
Expected result:
Either notices for use of deprecated [], undefined offset
'index' and too long replace char (and of course the
actual result)
or 'a bla' is deleted and $string has array('index' = 'b
blubb') as value.
Actual result:
--
string(5) b bla
--
Edit this bug report at http://bugs.php.net/?id=29271edit=1
#29271 [Bgs]: behaviour of $string['text'] = 'new string';
ID: 29271
Updated by: [EMAIL PROTECTED]
Reported By: nospam0 at malkusch dot de
Status: Bogus
Bug Type: Strings related
Operating System: *
PHP Version: 5.0.0
New Comment:
$string already IS a string and you still can use array-brackets to
access a particular symbol, so it won't become an array.
Previous Comments:
[2004-07-28 13:15:34] nospam0 at malkusch dot de
It's expected behaviour: 'index' is casted to it's
integer value (0), that's why you get this result.
But as I use $string[] and not $string{} it's undefined
wether it should be a new array or a string. So why
doesn't PHP throw an error?
[2004-07-28 12:39:59] [EMAIL PROTECTED]
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php
It's expected behaviour: 'index' is casted to it's integer value (0),
that's why you get this result.
[2004-07-20 01:54:22] nospam0 at malkusch dot de
Description:
$string = 'a bla';
$string['index'] = 'b blub';
does the same work as
$string = 'a bla';
$string{(int)'index'} = 'b blub'{0};
without any notic of undefined index or too long replacing
string. But it should throw any notice, because one could
expect that the code should produce a new Array('index' =
'b blubb').
Reproduce code:
---
$string = 'a bla';
$string['index'] = 'b blub';
var_dump($string);
Expected result:
Either notices for use of deprecated [], undefined offset
'index' and too long replace char (and of course the
actual result)
or 'a bla' is deleted and $string has array('index' = 'b
blubb') as value.
Actual result:
--
string(5) b bla
--
Edit this bug report at http://bugs.php.net/?id=29271edit=1
#29271 [Bgs]: behaviour of $string['text'] = 'new string';
ID: 29271
User updated by: nospam0 at malkusch dot de
Reported By: nospam0 at malkusch dot de
Status: Bogus
Bug Type: Strings related
Operating System: *
PHP Version: 5.0.0
New Comment:
$string already IS a string and you still can use
array-brackets to access a particular symbol
So PHP will never throw an error, even [] on strings is
deprecated since PHP4?
Previous Comments:
[2004-07-28 13:25:55] [EMAIL PROTECTED]
$string already IS a string and you still can use array-brackets to
access a particular symbol, so it won't become an array.
[2004-07-28 13:15:34] nospam0 at malkusch dot de
It's expected behaviour: 'index' is casted to it's
integer value (0), that's why you get this result.
But as I use $string[] and not $string{} it's undefined
wether it should be a new array or a string. So why
doesn't PHP throw an error?
[2004-07-28 12:39:59] [EMAIL PROTECTED]
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php
It's expected behaviour: 'index' is casted to it's integer value (0),
that's why you get this result.
[2004-07-20 01:54:22] nospam0 at malkusch dot de
Description:
$string = 'a bla';
$string['index'] = 'b blub';
does the same work as
$string = 'a bla';
$string{(int)'index'} = 'b blub'{0};
without any notic of undefined index or too long replacing
string. But it should throw any notice, because one could
expect that the code should produce a new Array('index' =
'b blubb').
Reproduce code:
---
$string = 'a bla';
$string['index'] = 'b blub';
var_dump($string);
Expected result:
Either notices for use of deprecated [], undefined offset
'index' and too long replace char (and of course the
actual result)
or 'a bla' is deleted and $string has array('index' = 'b
blubb') as value.
Actual result:
--
string(5) b bla
--
Edit this bug report at http://bugs.php.net/?id=29271edit=1
