ID: 35427
Updated by: [EMAIL PROTECTED]
Reported By: tomas_matousek at hotmail dot com
-Status: Open
+Status: Feedback
Bug Type: Strings related
Operating System: *
PHP Version: 5.1.0
New Comment:
Really, where? Do you have a patch to fix this?
Previous Comments:
[2005-11-28 21:27:28] tomas_matousek at hotmail dot com
No, I needn't. str_word_count("bar-var") returns 1, so '-' is
considered as a part of the word if it is followed by 'word'
character.
See the source code. The bug is clear there.
[2005-11-28 09:47:30] [EMAIL PROTECTED]
Yes, you need to add the - in the list.
[2005-11-28 09:29:10] tomas_matousek at hotmail dot com
Read again the full doc! Don't stop at the middle.
RTFM:
"charlist
A list of additional characters which will be considered as 'word' "
[2005-11-28 01:04:24] [EMAIL PROTECTED]
RTFM: "For the purpose of this function, 'word' is defined as a locale
dependent string containing alphabetic characters, which also may
contain, but not start with "'" and "-" characters."
[2005-11-27 20:00:54] tomas_matousek at hotmail dot com
By passing "0" as the third parameter, one declares '0' character legal
word character which should be equivalent to any other letter, e.g. 'x'.
"bar-xbar" is considered to be a word so "bar-0bar" should be word as
well.
The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
http://bugs.php.net/35427
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