ID: 37047
Updated by: [EMAIL PROTECTED]
Reported By: karoly at negyesi dot net
-Status: Verified
+Status: Open
-Bug Type: Documentation problem
+Bug Type: Variables related
Operating System: Irrevelant
PHP Version: 5.1.2
New Comment:
If static variables are resolved in compile time then
<?php
function storage($key) {
return $storage;
static $storage = array('a' => array('x', 'y'));
}
var_dump(storage('a'));
?>
should give an expected result.
Previous Comments:
------------------------------------------------------------------------
[2006-04-12 08:31:01] [EMAIL PROTECTED]
It's the same as
<?php
exit;
class Test { }
?>
The class will be still declared, even though there is an exit
statement before the declaration. It doesn't mean that it's "executed",
because there is a big difference between "execution" and "compilation".
------------------------------------------------------------------------
[2006-04-11 22:44:27] karoly at negyesi dot net
Hint. If you doc this please doc everything as well that executes at
compile time. It will be a very interesting handbook page...
------------------------------------------------------------------------
[2006-04-11 22:38:31] [EMAIL PROTECTED]
Sorry. I misread.
You're right (-:
S
------------------------------------------------------------------------
[2006-04-11 22:37:29] [EMAIL PROTECTED]
see: http://php.net/return
"the return() statement immediately ends execution of the current
function"
(It's already documented.)
S
------------------------------------------------------------------------
[2006-04-11 22:28:04] karoly at negyesi dot net
Then this is a docs issue. Because I do not expect anything to be
executed after a return...
------------------------------------------------------------------------
The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
http://bugs.php.net/37047
--
Edit this bug report at http://bugs.php.net/?id=37047&edit=1
