ID: 37225
User updated by: max at hightech dot lv
Reported By: max at hightech dot lv
-Status: Open
+Status: Bogus
Bug Type: Scripting Engine problem
Operating System: ALL
PHP Version: 5.1.2
Assigned To: dmitry
New Comment:
"$a1 =& $a2;
This line means that both $a[0] and $a[1] become references that point
to the same value."
I see now. strange... I don't change variable, but it change...
Previous Comments:
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[2006-08-24 15:02:30] max at hightech dot lv
But why after the second line "$arr" is references? I don't define it
as references!
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[2006-08-24 14:56:04] [EMAIL PROTECTED]
Duplicate of #37917.
You're copying and modifying refernces and this is expected.
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[2006-04-27 16:07:28] max at hightech dot lv
Description:
------------
looks like after copy reference to some variable, source-variable start
to be reference it self. Is it correct? In result we can't make copy
array, if some of it element was used as reference.
Reproduce code:
---------------
$arr = array("TEXT" => "test");
$tmp =& $arr["TEXT"];
$zz = $arr;
$zz["TEXT"] = 1;
var_dump($arr);
Expected result:
----------------
array(1) { ["TEXT"]=> string(4) "test" }
Actual result:
--------------
array(1) { ["TEXT"]=> &int(1) }
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Edit this bug report at http://bugs.php.net/?id=37225&edit=1
