ID: 39853
User updated by: anton dot kirsanov at gmail dot com
Reported By: anton dot kirsanov at gmail dot com
Status: Open
Bug Type: Strings related
Operating System: Windows XP SP2
PHP Version: 4.4.4
New Comment:
Hi:)
funny...
you will use /e modifier if you want parse the pattern as a php code.
Say me, why a function str_repeat() really work in this situation:
?php
$s = A-B;
echo preg_replace(/\-([a-z])/iU, str_repeat($1, 10), $s);
?
// --
// ACTUAL RESULT:
// --
ABB
Why?
See that:
?php
$s = A-B;
echo preg_replace(/\-([a-z])/iU, strtolower(str_repeat($1, 10)),
$s);
?
// --
// ACTUAL RESULT:
// --
ABB
// Why that ? :)
Previous Comments:
[2006-12-16 18:09:15] judas dot iscariote at gmail dot com
Why you think this is a bug ?
you are looking for preg_replace_callback ... or if you are crazy, the
preg_replace /e modifier.
not a bug, read the manual ;-)
[2006-12-16 12:40:44] ara at lenta dot ru
Tu XYu.
[2006-12-16 12:37:46] anton dot kirsanov at gmail dot com
Sorry, am mix up a 'Expected result' and 'Actual result' :)
Please read this quite the contrary - 'Expected result' is a 'Actual
result'.
[2006-12-16 12:35:36] ara at lenta dot ru
#1090;#1099; #1093;#1091;#1081;
[2006-12-16 12:33:44] anton dot kirsanov at gmail dot com
Description:
strtoupper(), strtolower() function does not change
string(as virtual vars - like $1(\\1)) what be returned a preg_replace
function.
Reproduce code:
---
?php
// 1
$s = A-B;
echo preg_replace(/\-([a-z])/iU, strtolower($1), $s);
echo \n;
// 2
$s = a-b;
echo preg_replace(/\-([a-z])/iU, strtoupper($1), $s);
// 3
$s = B-B;
echo preg_replace(/([a-z]-[a-z])/i, strtolower(A-$1-A), $s);
?
Expected result:
AB
ab
a-B-B-a
Actual result:
--
Ab
aB
abba
--
Edit this bug report at http://bugs.php.net/?id=39853edit=1
