ID: 41871 Updated by: [EMAIL PROTECTED] Reported By: kulakov74 at yandex dot ru -Status: Open +Status: Bogus Bug Type: MySQL related Operating System: Linux / Windows PHP Version: 5.2.3 New Comment:
This is expected result. mysql_free_result() just decreases the refcount to the result and actual freeing happens during request shutdown (if refcount to the result is 0!). Previous Comments: ------------------------------------------------------------------------ [2007-07-02 13:12:53] kulakov74 at yandex dot ru Description: ------------ When I call mysql_free_result($Res) I expect I won't be able to use the result in calls to mysql_fetch_array() etc. But if $Res is passed by reference as a function parameter and is copied to another variable the result is not freed and I can still use it. I realize this is a VERY unlikely condition and I found it by accident (mixed 2 lines of code and got surprised to see no error). Also this might well be intentional behavior. Anyway, just in case. Reproduce code: --------------- a($Res); function a(&$Res){ $Res=mysql_query("Show Tables"); $Res1=$Res; mysql_free_result($Res); mysql_fetch_array($Res); //still works! } Expected result: ---------------- Warning: mysql_fetch_array(): 7 is not a valid MySQL result resource in Actual result: -------------- No errors ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=41871&edit=1