ID: 45940 Updated by: johan...@php.net Reported By: talmage dot news at gmail dot com -Status: Assigned +Status: Closed Bug Type: MySQLi related Operating System: Centos 5 PHP Version: 5.2.6 Assigned To: mysql New Comment:
This bug has been fixed in CVS. Snapshots of the sources are packaged every three hours; this change will be in the next snapshot. You can grab the snapshot at http://snaps.php.net/. Thank you for the report, and for helping us make PHP better. Previous Comments: ------------------------------------------------------------------------ [2009-01-10 10:23:30] nullhility at gmail dot com Getting the same error with the following version: PHP 5.2.4-2ubuntu5.4 with Suhosin-Patch 0.9.6.2 I was attempting to suppress errors so I could control output/formatting etc. Thought i'd just re-iterate this for version related purposes. <?php //a forced username/password mismatch $dbo = @new mysqli('localhost', 'r00t', 'pass', 'my_db'); var_dump($dbo->connect_error); var_dump(mysqli_connect_error()); ?> output: Warning: main(): Couldn't fetch mysqli in /home/default/php/mysqli.php on line 4 NULL string(63) "Access denied for user 'r00t'@'localhost' (using password: YES)" ------------------------------------------------------------------------ [2008-12-25 21:17:22] ws at develtheory dot com Was able to reproduce the error in the same method on php 5.2.8, both with purposeful incorrect passwords and nonexistent host/port combos. the object is created, connect_error returns NULL on var_dump, error log dumps: "Dec 25 15:12:18 dev01 httpd: PHP Warning: dbo::__construct() [<a href='dbo.--construct'>dbo.--construct</a>]: Couldn't fetch mysqli in /nfs/beta/www/classes/dbo-new.inc.php on line 88" ------------------------------------------------------------------------ [2008-12-01 13:39:16] dannyrjohnston at msn dot com Forget my previous comment. I found some code between the new mysqli statement in the example I was using which was setting the $dbObj to false if mysql_connect_error was returning a value. ------------------------------------------------------------------------ [2008-12-01 13:17:14] dannyrjohnston at msn dot com I have duplicated this issue. According to the manual mysqli::__construct should always return a object, but the function is returning a false value on error. I have tried three different possible error conditions and have the following results: Bad user/password combo: mysqli_connect_error() returns "Access denied for user 'xxx'@'xxx' (using password: YES)", return value is false. User does not have access to the db selected: mysqli_connect_error()returns "Access denied for user 'xxx'@'xxx' to database 'xxx'", return value is false. Bad port number: mysqli_connect_error() returns "Can't connect to MySQL server on 'localhost' (10061)", return value is false. I have not checked any other cases such as bad socked name, but in each of the above conditions I received a false value not an object. test code: <?php $dbObj = new mysqli( "localhost", "user", "pass", "db", 3306); echo "dbObj="; var_dump($dbObj); ?> error result: dbObj=bool(false) sucess result: dbObj==object(mysqli)#1 (0) { } ------------------------------------------------------------------------ [2008-11-29 00:22:45] valentin71 at gmail dot com Not quite sure that mudroeb is right. According to manual the right call format must be following: mysqli mysqli_connect ( [string host [, string username [, string passwd [, string dbname [, int port [, string socket]]]]]] ) However conn=new mysqli('localhost','user','password','my_db',3306); works as expected. ------------------------------------------------------------------------ The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online at http://bugs.php.net/45940 -- Edit this bug report at http://bugs.php.net/?id=45940&edit=1
