ID: 16045
Updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
-Status: Feedback
+Status: No Feedback
Bug Type: *General Issues
Operating System: All
PHP Version: 4.1.1
New Comment:
No feedback was provided for this bug for over a month, so it is
being suspended automatically. If you are able to provide the
information that was originally requested, please do so and change
the status of the bug back to Open.
Previous Comments:
[2002-03-13 15:45:18] [EMAIL PROTECTED]
FWIW, I used the following script and got the correct
results:
?php
error_reporting(E_ALL);
$x = array(1);
echo Count: . count($x) . \n;
unset($x[0]);
echo Count: . count($x) . \n;
?
Results:
Count: 1
Count: 0
This is on version 4.2.0-dev. and 4.1.2. What does this
script produce for you?
Torben
[2002-03-13 15:11:08] [EMAIL PROTECTED]
Hello,
Funny logical error:
if we have a simple variable, say
$x = 1
then
count($x) == 1, which is natural (I don't think so)
And if we have an array
$x[0] = 1;
count($x) == 1,
but after
UnSet($x[0])
we still have
count($x) = 1!
This leads to a very special kind of logical errors which are really
hard to track.
My suggestion:
either: introduce explicit type system (with unions, structs and arrays
;)
or: disable count on variables
--
Edit this bug report at http://bugs.php.net/?id=16045edit=1
