Bug #54254 [Com]: cal_from_jd returns month = 6 when there is only one Adar
Edit report at https://bugs.php.net/bug.php?id=54254edit=1 ID: 54254 Comment by: oc666 at netvision dot net dot il Reported by:asphp at dsgml dot com Summary:cal_from_jd returns month = 6 when there is only one Adar Status: Closed Type: Bug Package:Calendar related PHP Version:5.3.5 Assigned To:stas Block user comment: N Private report: N New Comment: I think the bug still exists. Under 5.4.9 I get the same results like in the reproduce example: Array ( [date] = 6/24/5772 [month] = 6 [day] = 24 [year] = 5772 [dow] = 0 [abbrevdayname] = Sun [dayname] = Sunday [abbrevmonth] = AdarI [monthname] = AdarI ) 0 29 Previous Comments: [2012-08-07 08:49:33] s...@php.net This bug has been fixed in SVN. Snapshots of the sources are packaged every three hours; this change will be in the next snapshot. You can grab the snapshot at http://snaps.php.net/. For Windows: http://windows.php.net/snapshots/ Thank you for the report, and for helping us make PHP better. fixed in master [2012-03-29 18:33:50] asphp at dsgml dot com woordengeschrift you misunderstand the Hebrew calendar. In non-leap years there is a gap, the calendar months go: 4,5,7,8 - month 6 is skipped. Unfortunately PHP does 4,5,6,8 - it skips month 7 instead of 6 which is incorrect. In a leap year it is AdarI that is added - AdarII is the same as Adar. Yes, I know you would expect the second one to be the extra, but that's not how the calendar works. [2012-03-29 12:13:03] info at woordengeschrift dot nl In NON-leap years, there is only the unnumbered month of Adar. [2012-03-29 12:09:41] info at woordengeschrift dot nl In leap years, there is only the unnumbered month of Adar. Numbered Adars only occur in leap years: Adar_I (the actual leap month), followed by Adar_II. [2011-03-15 09:53:50] asphp at dsgml dot com Description: cal_from_jd() returns 6 for Adar when there is only one Adar, (it should return 7, since if there is only one Adar it's AdarII). It also says AdarI, which is wrong (it should be either Adar or at least AdarII). Furthermore the cal_days_in_month() (correctly) only works with month 7, and not 6 as returned by cal_from_jd. Test script: --- ? print_r(cal_from_jd(2456005, CAL_JEWISH)); echo cal_days_in_month(CAL_JEWISH, 6, 5772) . \n; echo cal_days_in_month(CAL_JEWISH, 7, 5772) . \n; ? Expected result: The month in cal_from_jd should be 7. The second two lines demonstrate how cal_days_in_month also expects the month to be 7. Actual result: -- Array ( [date] = 6/24/5772 [month] = 6 [day] = 24 [year] = 5772 [dow] = 0 [abbrevdayname] = Sun [dayname] = Sunday [abbrevmonth] = AdarI [monthname] = AdarI ) 0 29 -- Edit this bug report at https://bugs.php.net/bug.php?id=54254edit=1
Bug #54254 [Com]: cal_from_jd returns month = 6 when there is only one Adar
Edit report at https://bugs.php.net/bug.php?id=54254edit=1 ID: 54254 Comment by: info at woordengeschrift dot nl Reported by:asphp at dsgml dot com Summary:cal_from_jd returns month = 6 when there is only one Adar Status: Open Type: Bug Package:Calendar related PHP Version:5.3.5 Block user comment: N Private report: N New Comment: In leap years, there is only the unnumbered month of Adar. Numbered Adars only occur in leap years: Adar_I (the actual leap month), followed by Adar_II. Previous Comments: [2011-03-15 09:53:50] asphp at dsgml dot com Description: cal_from_jd() returns 6 for Adar when there is only one Adar, (it should return 7, since if there is only one Adar it's AdarII). It also says AdarI, which is wrong (it should be either Adar or at least AdarII). Furthermore the cal_days_in_month() (correctly) only works with month 7, and not 6 as returned by cal_from_jd. Test script: --- ? print_r(cal_from_jd(2456005, CAL_JEWISH)); echo cal_days_in_month(CAL_JEWISH, 6, 5772) . \n; echo cal_days_in_month(CAL_JEWISH, 7, 5772) . \n; ? Expected result: The month in cal_from_jd should be 7. The second two lines demonstrate how cal_days_in_month also expects the month to be 7. Actual result: -- Array ( [date] = 6/24/5772 [month] = 6 [day] = 24 [year] = 5772 [dow] = 0 [abbrevdayname] = Sun [dayname] = Sunday [abbrevmonth] = AdarI [monthname] = AdarI ) 0 29 -- Edit this bug report at https://bugs.php.net/bug.php?id=54254edit=1
Bug #54254 [Com]: cal_from_jd returns month = 6 when there is only one Adar
Edit report at https://bugs.php.net/bug.php?id=54254edit=1 ID: 54254 Comment by: info at woordengeschrift dot nl Reported by:asphp at dsgml dot com Summary:cal_from_jd returns month = 6 when there is only one Adar Status: Open Type: Bug Package:Calendar related PHP Version:5.3.5 Block user comment: N Private report: N New Comment: In NON-leap years, there is only the unnumbered month of Adar. Previous Comments: [2012-03-29 12:09:41] info at woordengeschrift dot nl In leap years, there is only the unnumbered month of Adar. Numbered Adars only occur in leap years: Adar_I (the actual leap month), followed by Adar_II. [2011-03-15 09:53:50] asphp at dsgml dot com Description: cal_from_jd() returns 6 for Adar when there is only one Adar, (it should return 7, since if there is only one Adar it's AdarII). It also says AdarI, which is wrong (it should be either Adar or at least AdarII). Furthermore the cal_days_in_month() (correctly) only works with month 7, and not 6 as returned by cal_from_jd. Test script: --- ? print_r(cal_from_jd(2456005, CAL_JEWISH)); echo cal_days_in_month(CAL_JEWISH, 6, 5772) . \n; echo cal_days_in_month(CAL_JEWISH, 7, 5772) . \n; ? Expected result: The month in cal_from_jd should be 7. The second two lines demonstrate how cal_days_in_month also expects the month to be 7. Actual result: -- Array ( [date] = 6/24/5772 [month] = 6 [day] = 24 [year] = 5772 [dow] = 0 [abbrevdayname] = Sun [dayname] = Sunday [abbrevmonth] = AdarI [monthname] = AdarI ) 0 29 -- Edit this bug report at https://bugs.php.net/bug.php?id=54254edit=1
