[PHP-DB] strange results in mysql with readdir.php
Anybody has an idea about what happened to me ?
The following script should just charge in a mysql db the images located in
a directory. Unfortunately everytime I call readdir.php (never mind if
there are or not new images) mysql is charging 2 or 6 copies of the same
last image uploaded into the directory. Anybody may explain to me where I'm
failing?
Thanks for all the phpers!
Alessandro
?
$dbcnx = mysql_connect(localhost, root, password);
mysql_select_db(news);
if (!$dbcnx)
{
echo( pconnection to database server failed!/p);
exit();
}
if (! @mysql_select_db(news) )
{
echo( pImage Database Not Available!/p );
exit();
}
$path = ./;
$dir_handle = @opendir($path) or die(Unable to open directory $path);
while ($file = readdir($dir_handle)) {
$filetyp = substr($file, -3);
if ($filetyp == 'gif' OR $filetyp == 'jpg') {
$handle = fopen($path . / . $file,'r');
$file_content = fread($handle,filesize($path . / . $file));
fclose($handle);
$encoded = chunk_split(base64_encode($file_content));
$sql = INSERT INTO images SET sixfourdata='$encoded';
@mysql_query($sql);
}
}
closedir($dir_handle);
echo(complete);
?
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Re: [PHP-DB] strange results in mysql with readdir.php
I'd think there where multiple files with jpg and gif extensions.
Like:
image1.jpg
image1.jpg.jpg
Anybody has an idea about what happened to me ?
The following script should just charge in a mysql db the images located in
a directory. Unfortunately everytime I call readdir.php (never mind if
there are or not new images) mysql is charging 2 or 6 copies of the same
last image uploaded into the directory. Anybody may explain to me where I'm
failing?
Thanks for all the phpers!
Alessandro
?
$dbcnx = mysql_connect(localhost, root, password);
mysql_select_db(news);
if (!$dbcnx)
{
echo( pconnection to database server failed!/p);
exit();
}
if (! @mysql_select_db(news) )
{
echo( pImage Database Not Available!/p );
exit();
}
$path = ./;
$dir_handle = @opendir($path) or die(Unable to open directory $path);
while ($file = readdir($dir_handle)) {
$filetyp = substr($file, -3);
if ($filetyp == 'gif' OR $filetyp == 'jpg') {
$handle = fopen($path . / . $file,'r');
$file_content = fread($handle,filesize($path . / . $file));
fclose($handle);
$encoded = chunk_split(base64_encode($file_content));
$sql = INSERT INTO images SET sixfourdata='$encoded';
@mysql_query($sql);
}
}
closedir($dir_handle);
echo(complete);
?
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[PHP-DB] Re: strange results in mysql with readdir.php
Alessandro,
i think the sql insert statement should be:
insert into images(sixfourdata) values ('$encoded');
Rui Cunha
Alessandro Folghera writes:
Anybody has an idea about what happened to me ?
The following script should just charge in a mysql db the images located in
a directory. Unfortunately everytime I call readdir.php (never mind if
there are or not new images) mysql is charging 2 or 6 copies of the same
last image uploaded into the directory. Anybody may explain to me where I'm
failing?
Thanks for all the phpers!
Alessandro
?
$dbcnx = mysql_connect(localhost, root, password);
mysql_select_db(news);
if (!$dbcnx)
{
echo( pconnection to database server failed!/p);
exit();
}
if (! @mysql_select_db(news) )
{
echo( pImage Database Not Available!/p );
exit();
}
$path = ./;
$dir_handle = @opendir($path) or die(Unable to open directory $path);
while ($file = readdir($dir_handle)) {
$filetyp = substr($file, -3);
if ($filetyp == 'gif' OR $filetyp == 'jpg') {
$handle = fopen($path . / . $file,'r');
$file_content = fread($handle,filesize($path . / . $file));
fclose($handle);
$encoded = chunk_split(base64_encode($file_content));
$sql = INSERT INTO images SET sixfourdata='$encoded';
@mysql_query($sql);
}
}
closedir($dir_handle);
echo(complete);
?
*
* Rui Pedro Cunha *
* Dpto. de Ciências e Tecnologias *
* Universidade Autónoma de Lisboa *
* Rua de Santa Marta, 56, *
* 1169-023 Lisboa *
* Telefone (+351) 21 317 76 35/49 *
* Fax (+351) 21 353 37 02 *
* Url : http://www.ual.pt/dct/ *
* E-mail: [EMAIL PROTECTED] *
*
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Re: [PHP-DB] Error loading module: Unable to load dynamic library
Philippe wrote: Well, the exact message is: Unable to load dynamic library php_oci8.dll: The specified procedure could not be found If I remove the library the message becomes The specified module could not be found. It seems to be able to find the library (all the paths are correct) but it seems that this php_oci8.dll file is the wrong version or that it is looking for an additional DLL that it can't find OR that it can find the additional DLL but it is the wrong version. If I only knew what DLL was needed! Philippe The common problem would be that php_oci8.dll cannot find Oracle's libraries. Have you elimated this as the problem? There are a coupel of things to try: (i) Check phpinfo() output. Make sure PATH in the Apache env section contains the Oracle bin directory. If this is not clear in my FAQ, please let me know so I can update the FAQ. Currently http://otn.oracle.com/tech/opensource/php/php_troubleshooting_faq.html#envvars says: If Apache starts but gives errors about Oracle libraries and/or OCI8 function calls fail, try looking at PHP's environment. Create the following script phpinfo.php where your web server can read it and load it in a browser: ?php phpinfo(); ? Triple-check the environment and path configuration. On UNIX check that LD_LIBRARY_PATH (or equivalent) contains $ORACLE_HOME/lib. On Windows the PATH variable may need to contain %ORACLE_HOME%\bin. (ii) Install http://www.dependencywalker.com/ and run it on php_oci8.dll I'll look into adding a comment about this utility in the next FAQ update. Chris -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
