[PHP-DB] Re: Fast and high-quality Web Site Creation

2004-12-14 Thread CNA Programming Group
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[PHP-DB] Dates prior to Dec 31, 1969

2004-12-14 Thread Frank Marousek
I'm using the following code to display dates returned from a query of a
mySQL database.

$new_timestamp = strtotime($row_SearchPlayerRcrdSt['Date']);
$new_date_formatted = date ("m/d/y", $new_timestamp);
echo $new_date_formatted;

It appears that all dates prior to Dec 31, 1969 are displayed as 12/31/69.

What am I doing wrong?

Thanks,
Frank

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Re: [PHP-DB] String question

2004-12-14 Thread Jochem Maas
Chris Payne wrote:
Hi there everyone,
 

I am having to read a string with text in, but the way the DB is written in
the same string you have the price, for example”
this doesn't sound like a DB problem, sounds more like a regexp problem.
(i.e. php-db is probably the wrong list)
 

CASARON 4G
50lb Sacks in Ton Lots
$88.00
 

How can I strip out the 88.00 (Baring in mind it could be any number)  into
it’s own string?
http://nl2.php.net/manual/en/ref.pcre.php
NB: note the difference between using single and double quotes when
defining your regexp. e.g:
$regexp = '/^.*\$[ \t]?([0-9]+\.[0-9]{2})$/s';
and:
$regexp = "/^.*\$[ \t]?([0-9]+\.[0-9]{2})$/s";
...are not the same.
assuming that the price is at the end of the string you and is preceeded 
by a dollar sign (with or without a seperating space) could do:


$myString = "
CASARON 4G
50lb Sacks in Ton Lots
$88.00
\r\n
\t\r\n
";
$matches = array();
$found = preg_match(
   '/^.*\$[ \t]?([0-9]+\.[0-9]{2})$/s',
   /* some commented out alternatives */
   // '/^.*\$([0-9]+\.[0-9]{2})$/s',
   // '/^.*\$([0-9]+\.00)$/s',
   // '/^.*\$(88\.00)$/s',
   // '/.*\$(\d+\.\d+)/s',
   trim($myString), /* make life easier have a trim */
   $matches /* passed by ref */
   );
print_r("original string:\n--\n$myString");
print_r("\n\ntrimmed string:\n--\n".trim($myString)."\n\n");
print_r("found: $found\n matches array contents:\n\n");
print_r($matches);
?>
 

Thank you.
 

Chris
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Re: [PHP-DB] Dates prior to Dec 31, 1969

2004-12-14 Thread Jochem Maas
Frank Marousek wrote:
I'm using the following code to display dates returned from a query of a
mySQL database.
What kind of field is it? (int,timestamp,datetime,etc)
$new_timestamp = strtotime($row_SearchPlayerRcrdSt['Date']);
what do the following contain:
$new_timestamp
$row_SearchPlayerRcrdSt['Date']
you also might want to try connecting to the DB with the cmdline
mysql app to take a look at the date values actually stored in the DB.
$new_date_formatted = date ("m/d/y", $new_timestamp);
echo $new_date_formatted;
It appears that all dates prior to Dec 31, 1969 are displayed as 12/31/69.
What am I doing wrong?
Sounds like you have yet to come across the 'unix epoch' (try googling 
that). something to do with this looks to be tripping you up.

Either the date in the DB is invalid (eg. equal to 0) or strtotime or 
date are truncating the date value in your version of php.

(what version of php & mysql?)
Also notice that you are taking a formatted date string, parsing it for 
a timestamp and then creating a new formatted date string. Why not let 
mySQL just format it how you want straight away and save 2 function calls?

Thanks,
Frank
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Re: [PHP-DB] Dates prior to Dec 31, 1969

2004-12-14 Thread Ramil Sagum
On Tue, 14 Dec 2004 15:39:52 -0600, Frank Marousek
<[EMAIL PROTECTED]> wrote:
> I'm using the following code to display dates returned from a query of a
> mySQL database.
> 
> $new_timestamp = strtotime($row_SearchPlayerRcrdSt['Date']);
> $new_date_formatted = date ("m/d/y", $new_timestamp);
> echo $new_date_formatted;
> 
> It appears that all dates prior to Dec 31, 1969 are displayed as 12/31/69.
> 
> What am I doing wrong?
> Thanks,
> Frank
> 

On my system it displays at 01/01/70. This may be related to that note
in the strtotime page of the php manual:

http://ww.php.net/manual/en/function.strtotime.php


Note:  The valid range of a timestamp is typically from Fri, 13 Dec
1901 20:45:54 GMT to Tue, 19 Jan 2038 03:14:07 GMT. (These are the
dates that correspond to the minimum and maximum values for a 32-bit
signed integer.) Additionally, not all platforms support negative
timestamps, therefore your date range may be limited to no earlier
than the Unix epoch. This means that e.g. dates prior to Jan 1, 1970
will not work on Windows, some Linux distributions, and a few other
operating systems.


How about letting MySQL format the date for you? 
http://dev.mysql.com/doc/mysql/en/Date_and_time_functions.html#IDX1384



ramil
http://ramil.sagum.net

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[PHP-DB] String question

2004-12-14 Thread Chris Payne
Hi there everyone,

 

I am having to read a string with text in, but the way the DB is written in
the same string you have the price, for example”

 

CASARON 4G

50lb Sacks in Ton Lots

$88.00

 

How can I strip out the 88.00 (Baring in mind it could be any number)  into
it’s own string?

 

Thank you.

 

Chris


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[PHP-DB] Turn off "out of offfice" messages for the list, please

2004-12-14 Thread John Holmes
List,
I'm sure many of us will be taking some time off for the holidays (if 
you aren't already). Just a friendly reminder to either 1) unsubscribe 
while you're gone (you won't miss much, trust me) or 2) set your notice 
to not reply to postings to the list. These get quite annoying after a 
while, if you can imagine. Yes, I know how to filter them to my Junk 
folder, but let's try to stop it at the source instead, eh? ;)

Happy Holidays,
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php|architect: The Magazine for PHP Professionals – www.phparch.com
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[PHP-DB] Re: mysql_array_array

2004-12-14 Thread Zeljko Cvrkotic

"Yemi Obembe" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
>  if ($v = strtolower($_POST['email'])) {
> $host = mysql ;
> $user = "myusername" ;
> $pass= "mypassword" ;
> mysql_connect($host , $user , $pass ) ;
> mysql_select_db("ng") ;
> $sql = "SELECT * FROM arcadia WHERE email=$v";

Try to put email='$v'


> gives the error:
> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result resource in /var/www/ng/subscribe.php on line 32
>
> the concept of the script is to first see if the subscribed email is not
already in the list (to prevent double subscription) before subscribing. but
dis always come out wit d above error. what do you think could be wrong?
>
>
>
>
>
> -
>
> A passion till tomorrow,
> www.opeyemi.tk
>
>
>
>
> __
> Do You Yahoo!?
> Tired of spam?  Yahoo! Mail has the best spam protection around
> http://mail.yahoo.com

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