Re: [PHP-DB] Processing a web form / loop etc.

2006-05-31 Thread Andri Heryandi

USE ARRAY OF FORM OBJECT



  
  
  ...
  ...
  
  




actionfile.php
";
   }
?>

Modify that script.

I Hope it will help you.

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[PHP-DB] How can I get in PHP the number of files in a directory

2006-05-31 Thread suad

Hi,

This is for reading a file:


How can I get in PHP the number of files in the directory (rasmus)
and the files names in a loop?

Thanks
Suad

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Re: [PHP-DB] How can I get in PHP the number of files in a directory

2006-05-31 Thread Stut

suad wrote:


This is for reading a file:


How can I get in PHP the number of files in the directory (rasmus)
and the files names in a loop? 



http://php.net/glob or http://php.net/readdir

-Stut

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Re: [PHP-DB] How can I get in PHP the number of files in a directory

2006-05-31 Thread Brad Bonkoski

http://www.php.net/manual/en/ref.dir.php

suad wrote:


Hi,

This is for reading a file:


How can I get in PHP the number of files in the directory (rasmus)
and the files names in a loop?

Thanks
Suad



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[PHP-DB] allow-url-fopen setting

2006-05-31 Thread Manoj Singh

Hello all,

Can i change the "allow-url-fopen"(php.ini variable) setting through php
code.

If any one knows how to do that, please help me.

Regards
Manoj


Re: [PHP-DB] allow-url-fopen setting

2006-05-31 Thread Brad Bonkoski



Manoj Singh wrote:


Hello all,

Can i change the "allow-url-fopen"(php.ini variable) setting through php
code.

If any one knows how to do that, please help me.

Regards
Manoj


http://www.php.net/manual/en/ref.filesystem.php

Note: This setting can only be set in php.ini due to security reasons.

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[PHP-DB] Combining Fields

2006-05-31 Thread Grae Wolfe - PHP
Good Day!
  I am trying to use my limited knowledge to create a VERY simple process to 
display some of the information in my table, allow a particular record to be 
selected, then opened on a page with text boxes to edit the information, 
after which the UPDATE command will be used to update the database.
  That being said, I have a way that I think this will work, but I don't 
have a unique record number in my table for each of the entries.  I have 
tried getting PHPMyAdmin to set this up, but I cannot seem to make it work. 
SO - I need to try to create that ID on the fly.  I figured I could just 
combine the first and last names to make this ID, but I am not sure what the 
syntax should be.  Here is the code I have dealing with defining the 
variables...

Any help or thoughts would be splendid!

while ($row = mysql_fetch_array($result)) {
 $id = $row['last_name'],$row['first_name'];
 $fname = $row['first_name'];
 $lname = $row['last_name'];

 $option_block .= "$lname, $fname";


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Re: [PHP-DB] Combining Fields

2006-05-31 Thread Brad Bonkoski



Grae Wolfe - PHP wrote:


Good Day!
 I am trying to use my limited knowledge to create a VERY simple process to 
display some of the information in my table, allow a particular record to be 
selected, then opened on a page with text boxes to edit the information, 
after which the UPDATE command will be used to update the database.
 That being said, I have a way that I think this will work, but I don't 
have a unique record number in my table for each of the entries.  I have 
tried getting PHPMyAdmin to set this up, but I cannot seem to make it work. 
SO - I need to try to create that ID on the fly.  I figured I could just 
combine the first and last names to make this ID, but I am not sure what the 
syntax should be.  Here is the code I have dealing with defining the 
variables...


Any help or thoughts would be splendid!

while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];

$option_block .= "$lname, $fname";


 


Use the dot (.) for appending variables...
so it would be:
$id = $row['last_name'].$row['first_name'];
...or course if you want that would look like this: 'SmithAdam'
if you want 'Smith,Adam' as your id then:
$id = $row['last_name'].",".$row['first_name'];
-Brad

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Re: [PHP-DB] Combining Fields

2006-05-31 Thread Grae Wolfe - PHP
Thank you Brad - That is what I was looking for, but now that I see how it 
behaves, I am thinking that it isn't going to work the way I wanted.  I need 
to then be able to pass the "ID" back to MySQL so that it will retrieve just 
the one record for editing.

I guess I need to go back to making the DB create an auto-incrementing ID 
number.  Hmmm...

Thanks!!


"Brad Bonkoski" <[EMAIL PROTECTED]> wrote in message 
news:[EMAIL PROTECTED]
>
>
> Grae Wolfe - PHP wrote:
>
>>Good Day!
>>  I am trying to use my limited knowledge to create a VERY simple process 
>> to display some of the information in my table, allow a particular record 
>> to be selected, then opened on a page with text boxes to edit the 
>> information, after which the UPDATE command will be used to update the 
>> database.
>>  That being said, I have a way that I think this will work, but I don't 
>> have a unique record number in my table for each of the entries.  I have 
>> tried getting PHPMyAdmin to set this up, but I cannot seem to make it 
>> work. SO - I need to try to create that ID on the fly.  I figured I could 
>> just combine the first and last names to make this ID, but I am not sure 
>> what the syntax should be.  Here is the code I have dealing with defining 
>> the variables...
>>
>>Any help or thoughts would be splendid!
>>
>>while ($row = mysql_fetch_array($result)) {
>> $id = $row['last_name'],$row['first_name'];
>> $fname = $row['first_name'];
>> $lname = $row['last_name'];
>>
>> $option_block .= "$lname, $fname";
>>
>>
>>
> Use the dot (.) for appending variables...
> so it would be:
> $id = $row['last_name'].$row['first_name'];
> ...or course if you want that would look like this: 'SmithAdam'
> if you want 'Smith,Adam' as your id then:
> $id = $row['last_name'].",".$row['first_name'];
> -Brad 

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Re: [PHP-DB] Combining Fields

2006-05-31 Thread Brad Bonkoski



Grae Wolfe - PHP wrote:

Thank you Brad - That is what I was looking for, but now that I see how it 
behaves, I am thinking that it isn't going to work the way I wanted.  I need 
to then be able to pass the "ID" back to MySQL so that it will retrieve just 
the one record for editing.


I guess I need to go back to making the DB create an auto-incrementing ID 
number.  Hmmm...


Thanks!!

 

Well, the unique ID would probably be the *best* way to go, but you 
could also get the record with the below solution, of course this 
requires every combination of first and last name is unique...

if you do:
$id = "Smith,Adam"
Then:
list($fname, $lname) = explode(",",$id);
select * from table where first_name = '$fname' and last_name='$lname'
would do the trick...
Of course this has many "what-ifs" asociated with it...all of which 
would be taken care of with an auto-incrementing/primary key ID field 
for wach record ;-)


-Brad

"Brad Bonkoski" <[EMAIL PROTECTED]> wrote in message 
news:[EMAIL PROTECTED]
 


Grae Wolfe - PHP wrote:

   


Good Day!
I am trying to use my limited knowledge to create a VERY simple process 
to display some of the information in my table, allow a particular record 
to be selected, then opened on a page with text boxes to edit the 
information, after which the UPDATE command will be used to update the 
database.
That being said, I have a way that I think this will work, but I don't 
have a unique record number in my table for each of the entries.  I have 
tried getting PHPMyAdmin to set this up, but I cannot seem to make it 
work. SO - I need to try to create that ID on the fly.  I figured I could 
just combine the first and last names to make this ID, but I am not sure 
what the syntax should be.  Here is the code I have dealing with defining 
the variables...


Any help or thoughts would be splendid!

while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];

$option_block .= "$lname, $fname";



 


Use the dot (.) for appending variables...
so it would be:
$id = $row['last_name'].$row['first_name'];
...or course if you want that would look like this: 'SmithAdam'
if you want 'Smith,Adam' as your id then:
$id = $row['last_name'].",".$row['first_name'];
-Brad 
   



 



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Re: [PHP-DB] Combining Fields

2006-05-31 Thread Grae Wolfe - PHP
Again, my many thanks - I didn't know about the 'explode' function - that 
may be a huge help.

Hopefully, I am on the right track now...  thanks!



"Brad Bonkoski" <[EMAIL PROTECTED]> wrote in message 
news:[EMAIL PROTECTED]
>
>
> Grae Wolfe - PHP wrote:
>
>>Thank you Brad - That is what I was looking for, but now that I see how it 
>>behaves, I am thinking that it isn't going to work the way I wanted.  I 
>>need to then be able to pass the "ID" back to MySQL so that it will 
>>retrieve just the one record for editing.
>>
>>I guess I need to go back to making the DB create an auto-incrementing ID 
>>number.  Hmmm...
>>
>>Thanks!!
>>
>>
> Well, the unique ID would probably be the *best* way to go, but you could 
> also get the record with the below solution, of course this requires every 
> combination of first and last name is unique...
> if you do:
> $id = "Smith,Adam"
> Then:
> list($fname, $lname) = explode(",",$id);
> select * from table where first_name = '$fname' and last_name='$lname'
> would do the trick...
> Of course this has many "what-ifs" asociated with it...all of which would 
> be taken care of with an auto-incrementing/primary key ID field for wach 
> record ;-)
>
> -Brad
>
>>"Brad Bonkoski" <[EMAIL PROTECTED]> wrote in message 
>>news:[EMAIL PROTECTED]
>>
>>>Grae Wolfe - PHP wrote:
>>>
>>>
Good Day!
 I am trying to use my limited knowledge to create a VERY simple process 
 to display some of the information in my table, allow a particular 
 record to be selected, then opened on a page with text boxes to edit 
 the information, after which the UPDATE command will be used to update 
 the database.
 That being said, I have a way that I think this will work, but I don't 
 have a unique record number in my table for each of the entries.  I 
 have tried getting PHPMyAdmin to set this up, but I cannot seem to make 
 it work. SO - I need to try to create that ID on the fly.  I figured I 
 could just combine the first and last names to make this ID, but I am 
 not sure what the syntax should be.  Here is the code I have dealing 
 with defining the variables...

Any help or thoughts would be splendid!

while ($row = mysql_fetch_array($result)) {
$id = $row['last_name'],$row['first_name'];
$fname = $row['first_name'];
$lname = $row['last_name'];

$option_block .= "$lname, $fname";




>>>Use the dot (.) for appending variables...
>>>so it would be:
>>>$id = $row['last_name'].$row['first_name'];
>>>...or course if you want that would look like this: 'SmithAdam'
>>>if you want 'Smith,Adam' as your id then:
>>>$id = $row['last_name'].",".$row['first_name'];
>>>-Brad
>>
>> 

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[PHP-DB] Re: Open a file?

2006-05-31 Thread The Panister
Well
You may try this:

First you can make a form and add the option to write to the file hidden in
the form... just like that:




 




-
Then the Action File should be contain some thing like that:


That's All.

Of course you can modify and enhance the code to meet your needs
I wish this help you.

The Panister!

Wim Van Geyt <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Hi,
>
> I want to send a choice to a textfile in php.
> Now i don't know how to let the button communicate with the php script?
> And do i have to write the script in the same page as the page where i
have writed the radiobuttons?
>
> Does anyone knows an answer ?
>
> Thanks
> Crazydj
> -
> Mail.be, WebMail and Virtual Office
> http://www.mail.be

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