Re: [PHP-DB] Re: [PHP] Strange Query Error...
On Nov 27, 2010, at 1:24 PM, Don Wieland wrote: On Nov 27, 2010, at 10:44 AM, Daniel P. Brown wrote: Note how you keep changing case here. For example, m.aucciim_id vs. m.AUCCIIM_ID. Also note that all of this is cAsE-sEnSiTiVe. You are right. But it still chokes in PHP: select m.* from Members m inner join Member_Years my on m.AUCCIIM_ID = my.member_id where now() < DATE_ADD(DATE_SUB(concat (member_year + 1,'-07-01'), INTERVAL 1 DAY), INTERVAL 30 DAY) AND m.Preferred_First_Name LIKE 'Don%' group by m.AUCCIIM_ID order by m.preferred_last_name Don Don't know if you necessarily need this but I found it while checking to see if one letter names are a good idea in MySQL statements. Might help in your like query. http://techonthenet.com/sql/like.php HTH, Best, Karl DeSaulniers Design Drumm http://designdrumm.com -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] ON DUPLICATE KEY UPDATE
Read through this:
http://dev.mysql.com/doc/refman/5.0/en/insert-on-duplicate.html, especially
the last 2 paragraphs.
On Sun, Nov 28, 2010 at 12:40 PM, Ron Piggott <
ron.pigg...@actsministries.org> wrote:
> My question is with the syntax below: If the “ON DUPLICATE KEY UPDATE
> `name` = '$name'” occurs will $_SESSION['referral_clients_reference'] be
> populated with the mysql_insert_id() value? If not, should I just query for
> it? Ron
>
> mysql_query("INSERT INTO `referral_clients` ( `reference` , `name` ,
> `paypal_email` , `last_update` ) VALUES ( NULL , '$name', '$paypal_email',
> CURRENT_TIMESTAMP ) ON DUPLICATE KEY UPDATE `name` = '$name';");
>
> $_SESSION['referral_clients_reference'] = mysql_insert_id();
>
> The Verse of the Day
> “Encouragement from God’s Word”
> http://www.TheVerseOfTheDay.info
[PHP-DB] ON DUPLICATE KEY UPDATE
My question is with the syntax below: If the “ON DUPLICATE KEY UPDATE `name` =
'$name'” occurs will $_SESSION['referral_clients_reference'] be populated with
the mysql_insert_id() value? If not, should I just query for it? Ron
mysql_query("INSERT INTO `referral_clients` ( `reference` , `name` ,
`paypal_email` , `last_update` ) VALUES ( NULL , '$name', '$paypal_email',
CURRENT_TIMESTAMP ) ON DUPLICATE KEY UPDATE `name` = '$name';");
$_SESSION['referral_clients_reference'] = mysql_insert_id();
The Verse of the Day
“Encouragement from God’s Word”
http://www.TheVerseOfTheDay.info
[PHP-DB] Re: [PHP] Strange Query Error...
On Nov 27, 2010, at 10:44 AM, Daniel P. Brown wrote: Note how you keep changing case here. For example, m.aucciim_id vs. m.AUCCIIM_ID. Also note that all of this is cAsE-sEnSiTiVe. You are right. But it still chokes in PHP: select m.* from Members m inner join Member_Years my on m.AUCCIIM_ID = my.member_id where now() < DATE_ADD(DATE_SUB(concat(member_year + 1,'-07-01'), INTERVAL 1 DAY), INTERVAL 30 DAY) AND m.Preferred_First_Name LIKE 'Don%' group by m.AUCCIIM_ID order by m.preferred_last_name Don
[PHP-DB] Re: [PHP] Strange Query Error...
On Sat, Nov 27, 2010 at 13:18, Don Wieland wrote: > On Nov 27, 2010, at 10:07 AM, Bastien wrote: > >> Try removing the backticks around the table names. If you do use them, >> then all values (field names and table names) need it. > > I tried that and still chokes... > > select m.* from Members m inner join Member_Years my on m.aucciim_id = > my.member_id where now() < DATE_ADD(DATE_SUB(concat(member_year + > 1,'-07-01'), INTERVAL 1 DAY), INTERVAL 30 DAY) AND m.Preferred_First_Name > LIKE 'Don%' group by m.AUCCIIM_ID order by m.preferred_last_name > > ERROR: You have an error in your SQL syntax; check the manual that > corresponds to your MySQL server version for the right syntax to use near > 'AND m.Preferred_First_Name LIKE 'Don%'' at line 1 Note how you keep changing case here. For example, m.aucciim_id vs. m.AUCCIIM_ID. Also note that all of this is cAsE-sEnSiTiVe. -- Dedicated Servers, Cloud and Cloud Hybrid Solutions, VPS, Hosting (866-) 725-4321 http://www.parasane.net/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Re: [PHP] Strange Query Error...
> On Nov 27, 2010, at 10:08 AM, Daniel P. Brown wrote: > > > one primary question: are you using the mysql_* > > family, mysqli_* family, or another method of interfacing with MySQL? > > mysql_ > > $results = mysql_query($query) or die(mysql_error()); > > Don > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php Could you show the actual code, not just the query. The way you are setting up the query could be affecting it. i.e. using single quotes when assigning to a variable would not work with your query. -- Niel Archer niel.archer (at) blueyonder.co.uk -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Strange Query Error...
On Nov 27, 2010, at 10:08 AM, Daniel P. Brown wrote: one primary question: are you using the mysql_* family, mysqli_* family, or another method of interfacing with MySQL? mysql_ $results = mysql_query($query) or die(mysql_error()); Don -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
[PHP-DB] Re: [PHP] Strange Query Error...
On Sat, Nov 27, 2010 at 12:30, Don Wieland wrote: > Hi gang, > > I am executing a query via PHP that gives me a PHP error: > > You have an error in your SQL syntax; check the manual that corresponds to > your MySQL server version for the right syntax to use near 'AND > m.`Preferred_First_Name` LIKE 'Don' AND m.`Preferred_Last_Name` LIKE > 'Wielan' at line 1 > > but when I copy the ECHO of the select query and run it in Sequel Pro Query, > it returns no error. > > Here is the query: > > select m.* from Members m inner join Member_Years my on m.aucciim_id = > my.member_id where now() < DATE_ADD(DATE_SUB(concat(`member_year` + > 1,'-07-01'), INTERVAL 1 DAY), INTERVAL 30 DAY) AND m.`Preferred_First_Name` > LIKE 'Don' AND m.`Preferred_Last_Name` LIKE 'Wieland' group by m.AUCCIIM_ID > order by m.preferred_last_name > > What is causing it to choke via PHP? This is actually better-suited to the DB list (CC'd) than the General list, but one primary question: are you using the mysql_* family, mysqli_* family, or another method of interfacing with MySQL? -- Dedicated Servers, Cloud and Cloud Hybrid Solutions, VPS, Hosting (866-) 725-4321 http://www.parasane.net/ -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP-DB] Using placeholder without pass by reference in MySqli
?> "Bastien" wrote in message news:962f0fd6-0eaa-495a-831e-da05bc1ab...@gmail.com... On 2010-11-26, at 7:46 PM, "None" wrote: > ?Could be a silly question, but i can't find a method to use placeholder > (MySqli) without passing by reference (bind_param) or receive by > reference (bind_result)? is that right? I really hate use reference > becouse in large program is common create a circular reference, even in > multiple query with same data i lost the information after first query > so i need to clean an refill at every step. > > I prefer functions like MySql or DBI. > > Do you think it will be implemented, function like param, param_array, > fetch_assoc, fetch_all_assoc, etc. where is the correct place to ask for > this method? here? > > Thank for your advice > > > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > Look at the prepared statements section of mysqli. Bastien Koert Sent from my iPhone= I double checked the entire documentation, but it's not possible to use prepared queries without sending or receiving data by reference it only accept bind_result and bind_param and, in fact, this's explicitly named in http://us.php.net/manual/en/mysqli-stmt.prepare.php Could I be wrong? there are undocumented methods that allows this? Thank you as always. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
